similar to: Assignment to string

When I sent the original note, I had it configured this way: [realms] HIJ.KLM.COM <http://hij.klm.com/> = { kdc = ad1.hij.klm.com kdc = ad2.hij.klm.com admin_server = ad.hij.klm.com default_domain = hij.klm.com } [domain_realm] .xyz.hij.klm.com = HIJ.KLM.COM <http://hij.klm.com/> .hij.klm.com = HIJ.KLM.COM <http://hij.klm.com/> But then after reading about kerberos on the

Greetings, Long-time but very occasional samba user here with a new challenge (well for me at least). The basics are that on the domain join, the computer account gets created but throws the dns error which based on my searching seems non-fatal. wbinfo -t gives me a succeeded, wbinfo -a klm.com\\me --ntlmv2 works fine but yet the net ads testjoin fails. Logs on the domain controller show

Hi Louis, Thanks for the reply. Upon checking the URL you sent, I'm not finding which stanzas you're referring to as being samba3 - my smb.conf looks remarkably similar to the sample I see there. Could you perhaps be more specific? Thanks, --Schuyler On Tue, Nov 17, 2015 at 11:23 AM L.P.H. van Belle <belle at bazuin.nl> wrote: > Your using a samba3 config on a samba 4. >

nchar(with(list(2),ls())) gives an internal error. This is of course a peculiar call (no names in the list), but the error is not caught cleanly. It is not clear from the documentation whether with(list(2)...) is allowable; if it is not, it should presumably give an error. If it is, then ls shouldn't have problems with the resulting environment. > qq <- with(list(2),ls())

I place the following data in a file id rs835 rs169 rs174 1001 CC GG CC 10032 CC GG CC 10066 CC NA CC If I read it in as tempDat <- read.table("tempDat.txt",na.strings="NA",header=TRUE) I get the following. id rs835 rs169 rs174 1 1001 CC GG CC 2 10032 CC GG CC 3 10066 CC <NA> CC NA has been assigned a missing

Hi Rowland, Thanks for the response. I stripped my smb.conf down to the bare suggestions and still have a no-go on the testjoin. This really smells to me like a kerberos configuration issue due to the computer existing in one and users authenticating from the forrest root. Unfortunately I don't know where to begin to look for answers as the kerberos configurations I've found referenced

Hello, Could anybody help me with this question? Example data frame NAME TICKER SHARES PERFORMANCE John ABC 100 0.05 John ABC 1000 1.5 Alice EFG 20 0.3 Paul HIJ 50 1.0 Paul JKL 60 2.0 Paul MNO 12 3.0 I would like to aggregate this dataframe by

Interesting. So would having the account I'm creating it with in the same subdomain fix the potential trust issues, or is samba's function in a subdomain in general in question? On Tue, Nov 17, 2015 at 3:25 PM Rowland Penny <rowlandpenny241155 at gmail.com> wrote: > On 17/11/15 19:32, Schuyler Bishop wrote: > > Hi Rowland, > > > > Thanks for the response. I

Hello, I have list of 600K lists, each sublist a list of two elements, the first a character, the second a list of six named elements, some characters some numrics. LISTA (600K) (:= h) |__ List of two elements |__ Character |__ Named List of 6 elements (characters and numerics) This works, sip <- lapply(h,function(r) r[[2]][['sip']]) but I wish to unlist this

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Dear mailing list I have a data that have 20,000 rows and 20 columns. Io wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000 th. can you please help me how do I do that.Than kyou. Example is below. Inpute: AG GG GG AG CC CC CC CC CT CC CT CT GG GG GG GG CC CC CC CC GG GG GG GG CC CC CC CC GG CG CG GG GG GG GG GG *CC CC CC CC* AA AG AG AA AA AA AA AA GG AG AG GG GG AG AG

Dear All I have a data.frame like that: structure(list(name = c("Gga_rs10722041", "Gga_rs10722249", "Gga_rs10722565", "Gga_rs10723082", "Gga_rs10723993", "Gga_rs10724555", "Gga_rs10726238", "Gga_rs10726461", "Gga_rs10726774", "Gga_rs10726967", "Gga_rs10727581", "Gga_rs10728004",

Hi, I am trying to split multiple columns. One column works just fine, but I want to do it for multiple columns??? Example > a ID V2 V3 V4 V5 V6 V7 V8 V9 V10 1 PBBA0644 -- GG AA -- AA -- AA GG GG 2 PBBA1010 -- GG AA -- AA -- AA GG GG 3 0127ATPR -- GG AA -- AA -- AA GG GG 4 0128EHAB -- GG AA -- AG -- AA AG GG 5 PBBA0829 -- GG AA -- AA -- AA GG AG

Dear list, I am trying to evaluate how many elements in a vector equal a certain value. The vectors are the columns of a data.frame, read in using read.table(): > dim(data) [1] 2600 742 > data[1:5,1:5] SNP001 SNP002 SNP003 SNP004 SNP005 1 GG AA TT TT GG 2 GG AA TC TT GG 3 GG AC CC TT GG 4 AG AA TT TT GG 5

I HAVE A VERY BIG DATA OF 67 COLMS AND 25000 ROWS AND WOULD LIKE TO TRANSPOSE IT THE R HELP WAS NOT ENOUGH INFORMATION BECOUSE I AM NOT A PROGRAMMER AND FIRST TIME R USER. SO CAN YOU GIVE SOME HINTS OF CODING, AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC AA TT GG GG CC TO AA AA AA AA AA TT TT TT TT TT GG GG GG GG GG GG GG GG GG GG CC CC CC CC CC [[alternative HTML

Dear R users, I am trying to fill in arrays (5 different according to distinct "id") from objects produced from arbitrary data set below. a <-

Dear Contributors I have a problem with the collection of data from the results of a test. I need to perform a comparative test over groups of data , recall the value of the pvalue and create a table. My problem is in the way to replicate the analysis over and over again over subsets of data according to a condition. I have this database, called y: gg t1 t2 d 40 1 1

I was going through the example below which is taken from the example section in the R documentation for accessing the function call stack. I am confused and I have 3 questions that I was hoping someone could answer. 1) why is y equal to zero even though the call was done with gg(3) 2) what does parents are 0,1,2,0,4,5,6,7 mean ? I understand what a parent frame is but how do the #'s relate

I have a more complicated function I am trying to write, but I run in to a problem when I want to add something to the plot from more than one data set while simultaneously controlling the appearance of the additional layer. # Toy data: foo <- data.frame ( x = 1:4, y = 4:1 , membership = c( "A", "A", "B", "B" ) ) bar <- data.frame ( x = 1:4 + 1 , y

Hi, I have a large dataset on which I would like to do the following: x<-data.frame(id=c(1,2,3), snp1=c("AA","GG", "AG"),snp2=c("GG","AG","GG"),snp3=c("GG","AG","AA")) > x id snp1 snp2 snp3 1 1 AA GG GG 2 2 GG AG AG 3 3 AG GG AA And then