Displaying 20 results from an estimated 1000 matches similar to: "if does not covert raw to logical (PR#13630)"
2009 Mar 30
1
duplicated fails to rise correct errors (PR#13632)
Full_Name: Wacek Kusnierczyk
Version: 2.8.0 and 2.10.0 r48242
OS: Ubuntu 8.04 Linux 32 bit
Submission from: (NULL) (129.241.110.161)
In the following code:
duplicated(data.frame(), incomparables=NA)
# Error in if (!is.logical(incomparables) || incomparables)
.NotYetUsed("incomparables != FALSE") :
# missing value where TRUE/FALSE needed
the raised error is clearly not the
2008 Oct 26
4
odd behaviour of identical
given what ?identical says, i find the following odd:
x = 1:10
y = 1:10
all.equal(x,y)
[1] TRUE
identical(x,y)
[1] TRUE
y[11] = 11
y = y[1:10]
all.equal(x,y)
[1] TRUE
identical(x,y)
[1] FALSE
y
[1] 1 2 3 4 5 6 7 8 9 10
length(y)
[1] 10
looks like a bug.
platform i686-pc-linux-gnu
arch i686
os linux-gnu
system
2009 Apr 02
2
actual argument matching does not conform to the definition (PR#13634)
Full_Name: Wacek Kusnierczyk
Version: 2.10.0 r48269
OS: Ubuntu 8.04 Linux 32 bit
Submission from: (NULL) (129.241.199.164)
In the following example (and many other cases):
quote(a=1)
# 1
the argument matching is apparently incorrect wrt. the documentation (The R
Language Definition, v 2.8.1, sec. 4.3.2, p. 23), which specifies the following
algorithm for argument matching:
1. Attempt to
2008 Nov 10
6
Variable passed to function not used in function in select=... in subset
Hello!
I have the problem that in my function the passed variable is not used, but the variable name of the dataframe itself?- difficult to explain, but an easy example:
TestFunc<-function(df, group) {
??? print(names(subset(df, select=group)))
}
df1<-data.frame(group="G1", visit="V1", value=0.9)
TestFunc(df1, c("group", "visit"))
Result:
[1]
2009 Apr 21
8
incorrect output and segfaults from sprintf with %*d (PR#13667)
Full_Name: Wacek Kusnierczyk
Version: 2.10.0 r48365
OS: Ubuntu 8.04 Linux 32bit
Submission from: (NULL) (129.241.110.141)
sprintf has a documented limit on strings included in the output using the
format '%s'. It appears that there is a limit on the length of strings included
with, e.g., the format '%d' beyond which surprising things happen (output
modified for conciseness):
2008 Nov 17
4
functional (?) programming in r
the following is a trivialized version of some functional code i tried
to use in r:
(funcs = lapply(1:5, function(i) function() i))
# a list of no-parameter functions, each with its own closure environment,
# each supposed to return the corresponding index when applied to no
arguments
sapply(funcs, function(func) func())
# supposed to return c(1,2,3,4,5)
there is absolutely nothing unusual in
2009 May 13
3
where does the null come from?
m = matrix(1:4, 2)
apply(m, 1, cat, '\n')
# 1 2
# 3 4
# NULL
why the null?
vQ
2009 Jan 02
1
[Fwd: Re: [R] Randomly remove condition-selected rows from a matrix]
Following Duncan's suggestion, I forward the below to R-devel.
vQ
-------- Original Message --------
Subject: Re: [R] Randomly remove condition-selected rows from a matrix
Date: Fri, 02 Jan 2009 10:34:52 -0500
From: Duncan Murdoch <murdoch at stats.uwo.ca>
To: Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no>
CC: R help <R-help at stat.math.ethz.ch>
2009 Feb 25
8
learning R
I was wondering why the following doesn't work:
> a=c(1,2)
> names(a)=c("one","two")
> a
one two
1 2
>
> names(a[2])
[1] "two"
>
> names(a[2])="too"
> names(a)
[1] "one" "two"
> a
one two
1 2
I must not be understanding some basic concept here.
Why doesn't the 2nd name change to
2009 Feb 25
8
learning R
I was wondering why the following doesn't work:
> a=c(1,2)
> names(a)=c("one","two")
> a
one two
1 2
>
> names(a[2])
[1] "two"
>
> names(a[2])="too"
> names(a)
[1] "one" "two"
> a
one two
1 2
I must not be understanding some basic concept here.
Why doesn't the 2nd name change to
2008 Nov 17
2
assign("FALSE", TRUE)
It was recently pointed out by Wacek Kusnierczyk that although one is
prevented from doing
FALSE <- TRUE
one *can* do
assign("FALSE",TRUE)
and have an object named ``FALSE'' with value TRUE in one's workspace.
This apparently has no deleterious effects; e.g. doing
sample(1:7,replace=FALSE)
gives a random permutation of 1:7 as expected and desired. I.e. the
local
2009 Mar 15
4
primitives again
Dear R Gurus:
How do I find the functions which are primitives, please?
Thanks,
Edna Bell
2009 Jan 18
8
regex -> negate a word
Dear all,
let's assume I have a vector of character strings:
x <- c("abcdef", "defabc", "qwerty")
What I would like to find is the following: all elements where the word
'abc' does not appear (i.e. 3 in this case of 'x').
Since I am not really experienced with regular expressions, I started
slowly and thought I find all word were
2008 Nov 30
6
Regex: workaround for variable length negative lookbehind
Hi all
I have the following regular expression problem: I want to find
complete elements of a vector that end in a repeated character but
where the repetition doesn't make up the whole word. That is, for the
vector vec:
vec<-c("aaaa", "baaa", "bbaa", "bbba", "baamm", "aa")
I would like to get
"baaa"
"bbaa"
2009 Mar 19
8
function question
Dear R Gurus:
I read somewhere that functions are considered vectors.
Is this true, please?
thanks
Edna Bell
2009 Mar 18
2
incoherent conversions from/to raw
i wonder about the following examples showing incoherence in how type
conversions are done in r:
x = TRUE
x[2] = as.raw(1)
# Error in x[2] = as.raw(1) :
# incompatible types (from raw to logical) in subassignment type fix
it seems that there is an attempt to coerce the raw value to logical
here, which fails, even though
as.logical(as.raw(1))
# TRUE
likewise,
x[2]
2009 Mar 18
2
incoherent conversions from/to raw
i wonder about the following examples showing incoherence in how type
conversions are done in r:
x = TRUE
x[2] = as.raw(1)
# Error in x[2] = as.raw(1) :
# incompatible types (from raw to logical) in subassignment type fix
it seems that there is an attempt to coerce the raw value to logical
here, which fails, even though
as.logical(as.raw(1))
# TRUE
likewise,
x[2]
2009 Feb 23
1
are arithmetic comparison operators binary?
the man page for relational operators (see, e.g., ?'<') says:
"
Binary operators which allow the comparison of values in atomic vectors.
Arguments:
x, y: atomic vectors, symbols, calls, or other objects for which
methods have been written.
"
it is somewhat surprizing that the following works:
'<'(1)
# logical(0)
'<'()
#
2009 Feb 23
1
are arithmetic comparison operators binary?
the man page for relational operators (see, e.g., ?'<') says:
"
Binary operators which allow the comparison of values in atomic vectors.
Arguments:
x, y: atomic vectors, symbols, calls, or other objects for which
methods have been written.
"
it is somewhat surprizing that the following works:
'<'(1)
# logical(0)
'<'()
#
2009 Mar 22
5
If statement generates two outputs
Hi,
How do I tell an if statement to generate two seperate outputs.
E.g If X>5 I want to create df1 and df2:
if (X>5) {df1<-c(4,5,6,7,8) AND df2<-c(9,10,11,12,13)}
Thanks,
James
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