similar to: is.matrix

Dear List, Has anyone worked with R on Ubuntu Server edition. Also would it be possible to connect to this ever using remote desktop . In addition has anyone worked with using R from a Amazon EC2 cloud like structure. Any early previews of Azure SDk's and R . Could you guide me to a place where I can read about this ? This is research project for low cost analytical solutions for developing

Hello rsync folks I'm trying to use rsync for backing up our servers. This mostly works extremely well, with no problems. However, 1 server is giving me a lot of trouble. It has a directory with (currently) 734088 files in it, and every time I try to backup this dir, rsync hangs after transferring roughly 2000 files. Sometimes it's around 1800, sometimes it's over 2100 (I think), but

Hello all I have a somewhat annoying problem with OpenSSH. Now, granted, it's certainly not a bug. I'm just wondering what the best course of action is. At work, we have multiple customers with machines named "fw0", "fs0", etc. This is all good, since it conforms to a standard naming scheme, so it's easier to administrate. However, when we go to our

Dear Sirs, I need to make a backup of email accounts (Maildir) a Linux server to a Windows server with NTFS, but get the following error: rsync: rename "/mnt/rsync/cur/137D94_29.ml110c.qnet.com.pe,S=32828:2,S.M92y5w" -> "cur/137D94_29.ml110c.qnet.com.pe,S=32828:2,S": Invalid argument (22) I have installed Rsync v3.0.9 The command is executed: rsync -rltDvu

Dear all, When I coerce a vector into a multi dimensional array, I would like R to start filling the array along the last dimension, then the 2nd last etc. Let's jump straight into an example. x <- 1 : 24 y <- array(dim=c(2,2,6)) I would like to have: y[1,1,1] = 1 y[1,1,2] = 2 ... y[1,1,6] = 6 y[1,2,1] = 7 y[1,2,2] = 8 ... y[2,1,1] = 13 ... y[2,2,1] = 19 if I do y<- array(x,

Suse Linux Enterprise Server 9 SP3 I've tried to create a large 5TB file system using both reiserfs and ext3 and both have failed. I end up with only a 1.5TB file system. Does anyone know why this doesn't work, what to do to fix it? Others have suggested that only XFS or JFS will work. Is this so? Thanks, -Mark

Hi, when running the following on different instances of R (Linux and Windows), I get different results. The one for Linux seems to be the intended / documented one. When using numeric indices rather than characters, Windows seemed to behave as expected. -----------On Windows-------------- x = matrix(FALSE, nrow=3, ncol=3) colnames(x) = LETTERS[1:3] rownames(x) = letters[1:3] x # A

I have two matrices A and B > dim (A) [1] 30380   104 > dim(Bt) [1] 30380    63 I want to  combine both A and B to matrix C where >dim(C) [1] 30380   167 How do I do that ? Regards, Pankaj Barah Department of Biology, Norwegian University of Science & Technology (NTNU) Realfagbygget, N-7491 [[alternative HTML version deleted]]

Transpose vector extracted from a matrix Hello, I am doing a recursive analysis that uses every line (vector) of a matrix in a loop. In the model, I need to transpose those vectors that are extracted from a matrix. Using simple vectors (no matrix involved) the transpose function works fine: simplevector <-matrix(1:3,3,1) tsimplevector <-t(simplevector) #transposed dim(simplevector)

Hi Is it possible to subset an n-dimensional array by a vector of n dimensions? E.g. assume I have > x <- array(1:24, dim=2:4) > x[1,1,2] [1] 7 > dims <- c(1,1,2) I would like a function that I can supply x and dims as parameters to, and have it return 7. Also, I would like to do something like: > x[1,1,] [1] 1 7 13 19 > dims2<- c(1,1,NA) And have a function of x and

Dear all, apply(X, MARGIN, FUN, ...) returns an array of dimension c(n, dim(X)[MARGIN]) when FUN returns a vector of length n > 1. Matrices and arrays are also vectors, so if FUN returns a matrix or an array, apply returns an array of dimension c(n, dim(X)[MARGIN]) as above. This is in accordance with the description of apply in the Blue Book, and also how Splus works (at least v6.0). I am

Dear sirs, 1...........Kindly tell me is it possible to form a matrix which contains a no of matrices.. for eg.. if a,b,c,d are matrices.... and e is a matrix which contains a,b,c,d as rows and columns.. 2..........Is it possible to form array of array of arrays for eg.. "A" contains two set of arrays (1,2)...and each A[1] and A[2] individually contains two set of arrays I tried like

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48269 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.199.164) In the following example (and many other cases): quote(a=1) # 1 the argument matching is apparently incorrect wrt. the documentation (The R Language Definition, v 2.8.1, sec. 4.3.2, p. 23), which specifies the following algorithm for argument matching: 1. Attempt to

Hi listers, I am having some trouble in a matrix multiplication... I have already checked some posts, but I didn't find my problem... I have the following code... But I am not getting the right multiplication... I checked the dimension and they are fine... id_y <- array(1:10,dim=c(2,1,5)) id_yt<-aperm(id_y,c(2,1,3)) m_id<-array(dim=c(dim(id_y)[1],dim(id_y)[1],dim(id_y)[3])) for (i in

Hi! I have a matrix called M with dimension (586,100,100). I would like to split and save this into 586 matrices with dimension 100 by 100. I have tried the following for loops but couldn't get it work.. l<-dim(M)[1] for (i in (1:l)){ save(M[i,,],file = "M_[i].img") } Can somebody help me with this? Thanks! Hana Lee [[alternative HTML version deleted]]

Hello all, I'm working with a matrix that will have varying dimensions. It will populate an array such that the number of matrix columns will determine the number of 3rd dimension levels of the array. Rows will be the same for both. For this example lets say the array will have 2 columns, but that's not fixed. dim(arr)<-c(dim(mat)[1],2,dim(mat)[2]) I wish to repeat each matrix

I have a matrix M > dim(M) [1] 30380   561 I have another list L contains , that contains some row names of matrix M str (L)  chr [1:21037] Now I want to extract the submatrix subM (21037    ,    561)  from the matrix M by matching the rownames (M) to the 21037 rownames o f L How do I do that ? Thanks and regards, Pankaj Barah   Pankaj Barah Department of Biology  Norwegian University

Hi, With two data sets, one complete and another one partial, I would like to merge them and keep the unmatched lines. The problem is that merge() dosen't keep the unmatched lines. Is there another function that I could use to merge the data frames. Example: completedf <- expand.grid(alpha=letters[1:3],beta=1:3) partdf <- data.frame( alpha= c('a','a','c'),

Hi all Suppose I have a dim=c(2,2,3) matrix A, say: A[,,1]= a b c d A[,,2]= e f g h A[,,3]= i j k l Suppose that I want to create a 2x2 matrix X, which picks elements from the above-mentioned submatrices according to an index matrix J referring to the "depth" dimension: J= 1 3 2 3 In other words, I want X to be X= a j g l since the matrix J says that the (1,1)-element should be

Hi Martin, Fair enough for R functions in general. But the behaviour of apply violates the expectation that apply(m, 1, fun) calls fun n times when m has n rows. That seems pretty basic. Also, I understand from your argument why it makes sense to call apply and return a special result (presumably NULL) for an empty argument; but why should apply call fun? Cheers David On Mon, 30 Jul 2018 at