similar to: 'xtfrm' performance (influences 'order' performance) in R devel

I'm reading in ~3 years worth of data that includes hourly timestamps. Presumably to avoid DST confusion, all the data is in PST time zone -- no discontinuities in the spring or fall. The data comes in a csv file, which I'm reading with myvariable <- read.csv("my_data_file.csv",header=FALSE,

Hi. I'm maintaining a package that creates an object that is essentially a classed version of numeric. I updated recently from 2.7.1 to 2.9.0, and merges involving my class suddenly took a huge performance hit. I've traced the problem to something near rank(). From NEWS, it seems rank() etc. changed in 2.8.0. Methods for xtfrm() are supposed to help, but I've had no success. There

Greetings - I'm battling POSIXct, as per the code below. My input is actually an XL file, but the weird results below correctly model what I am seeing in my program. Before I punt and use lubridate or timeDate, could anyone please help me understand why POSIXct forces my variable back to GMT? I suspect that I'm not properly coding the tzone value, but it does not throw an

? Sat, 27 Apr 2024 13:56:58 -0500 Jonathan Keane <jkeane at gmail.com> ?????: > In devel: > > max(numeric_version(c("1.0.1.100000000", "1.0.3.100000000", > "1.0.2.100000000"))) > [1] ?1.0.1.100000000? > > max(numeric_version(c("1.0.1.10000000", "1.0.3.10000000", > "1.0.2.10000000"))) > [1]

Hello, Sorry if anyone gets this message twice, as my mailserver may not be working. Thanks for your response. Your idea makes a lot of sense to me, but I've been unable to get seconds to work. I ended up with this format finally: "2007-10-31_16:20:22" Problem is I am unable to get it recognized as a date using timeDate(): R>

For a model I am working on, I have samples organized by year and week of the year. For this model, the data (year and week) comes from the basic sample data, but I require a value representing the amount of time since the sample was taken (actually, for the purpose of the model, it is sufficient to use the number of weeks from the middle of the sample week to the present). What I have found so

Given S4 methods [ and [<-, how do I write the Rd-file usage clause for the latter one? What I have now is: \S4method{[}{TimeSeries,TimeDate,missing}(x, i, j, ..., drop) \S4method{[<-}{TimeSeries,TimeDate,missing,ANY}(x, i, j, ..., value) which results in the following output: ## S4 method for signature 'TimeSeries, TimeDate, missing': x[i, j, ..., drop]

Hello: I am trying to use fCalendar for date arithmetic and the RMySQL package for accessing a MySQL database. The fCalendar math operations seem to work fine UNTIL I load the RMySQL package. Here is a demonstration: ean at fibonacci:~/Desktop/amCharts/rsa-metrics$ R R version 2.7.1 (2008-06-23) Copyright (C) 2008 The R Foundation for Statistical Computing ISBN 3-900051-07-0 R is free

Hello, I'm trying to build a for loop, where I estimate a series of models with different sets of (time series) data. However my for loop doesn't recognize the "i" ##################### code################ window.1=anomalies.CAK[(positions(anomalies.CAK)>=timeDate("1/1/1971") & positions(anomalies.CAK)<=timeDate("6/30/1991") )] ....

Dear R Experts: I am trying to convert a date and time character field to timeDate where the month is presented as three letters, such as "JUN" for June, etc. This is an example of the full character field: "04-MAY-11 1428" What is the proper format syntax? I've tried timeDate("04-MAY-11 1428",format="%d-%m-%y %H%M") but only get GMT [1]

Hello, I must be doing something wrong that's very obvious. But I just don't see it. I changed my Windows Time Zone to GMT and my Financial Center to Montreal. But I still get several warnings. >Sys.timezone() [1] "GMT Daylight Time" >myFinCenter [1] "Montreal" >Sys.timeDate() [1] "Montreal" [1] [2005-04-19 10:55:02] Warning messages: 1: Set

Anybody know how to invoke control panel applets? What I really want to do is make Wine use my default Date format that I used in Windows, but it's reverted to the goddawful American usage (with two digit years, no less). wine timedate.cpl (or wine C:/windows/system/timedate.cpl) fails with an error 193 and nothing in the log -- derek

I couldn't find anything in the chron or timeDate packages, and a good search yielded rounding to the nearest half hour, which I don't want. The data: structure(list(Date = structure(c(1209625080, 1209641460, 1209652500, 1209676800, 1209682860, 1209692100, 1209706980, 1209722580, 1209726300, 1209739620, 1209762780, 1209765720, 1209770520, 1209791040, 1209812580, 1209829920,

Hello! I am trying to identify which ones of a vector of dates are US holidays. And, ideally, which is which. And I do not know (a-priori) which dates those should be. I have, for example: x<-seq(as.Date("2011-01-01"),as.Date("2011-12-31"),by="day") (x) I think chron should help me here - but maybe I am not using it properly: library(chron) is.holiday(chron) #

I have a daily time series and have two questions to get some help with. Firs,t I have dates in simple numeric values. e.g. ymd [1] 20050104 20050105 20050106 20050107 20050110 20050111 20050113 20050114 [9] 20050118 20050120 20050121 20050124 20050125 20050126 20050127 20050128 [17] 20050201 20050202 20050203 20050204 Now, I'd like to compute statistics, e.g. acf, by business days. So, I

I wasn't even aware I was using midnightStandard. You won't find it in my script. Here is the relevant loop: date1 = timeDate(charvec = Sys.Date(), format = "%Y-%m-%d") date1 dow = 3; for (i in 1:length(V4) ) { x = read.csv(as.character(V4[[i]]), header = FALSE, na.strings=""); y = x[,1]; year = V2[[i]]; week = V3[[i]]; dtstr =

what package should I include to use timeDate? I want to convert a double (num of millis) into date object.

Hi All : I am attempting tomove a large amount of code from Splus to R and I was hoping that there was an equivalent in R of the Splus functions timeSeq and timeDate ? I did an RSiteSearch but nothing came up ? If the equivalent functions are part of some package, that's fine. Thanks a lot. Mark

Dear all, I am writing to ask for help to find R code to do the same thing as the following Splus code: dates <- c("02/27/1992", "02/27/1992", "01/14/1992", "02/28/1992", "02/01/1992") timeDate(as.character(dates),in.format="%m/%d/%Y","%a") [1] Thu Thu Tue Fri Sat Could anyone give me some R codes to get the

Dear R users, I have problem with the library fCalendar. I am not using the US standard format notations. It seems like it is not possible to have different format than the US standards. Anyone how knows a way to go around this problem? Here is the code I enter: myDate = "12.03.2005" timeDate(myDate, format = "%d.%m.%Y") And I get following error message: Error in if