similar to: strsplit and the empty string

given what ?identical says, i find the following odd: x = 1:10 y = 1:10 all.equal(x,y) [1] TRUE identical(x,y) [1] TRUE y[11] = 11 y = y[1:10] all.equal(x,y) [1] TRUE identical(x,y) [1] FALSE y [1] 1 2 3 4 5 6 7 8 9 10 length(y) [1] 10 looks like a bug. platform i686-pc-linux-gnu arch i686 os linux-gnu system

Attached is a suggested patch for src/main/character.c. It does not fix a bug, but rather provides an improvement on the recent extension of do_grep. In essence, instead of four occurences of 'invert ^ LOGICAL(ind)[i]' that accommodate for the option 'invert' added to grep, there is one occurence of 'LOGICAL(ind)[i] ^= invert' that modifies in-place the logical vector of

The attached patch provides a modification to the recent fix/improvement to do_grep already included in the most recent development version. The original fix added new functionality to the grep function by adding a new parameter, 'invert'. In the source code for the underlying do_grep, the value of the parameter is used to invert the logical match-no match flag vector ind. The

Following Duncan's suggestion, I forward the below to R-devel. vQ -------- Original Message -------- Subject: Re: [R] Randomly remove condition-selected rows from a matrix Date: Fri, 02 Jan 2009 10:34:52 -0500 From: Duncan Murdoch <murdoch at stats.uwo.ca> To: Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> CC: R help <R-help at stat.math.ethz.ch>

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.110.161) In the following code: duplicated(data.frame(), incomparables=NA) # Error in if (!is.logical(incomparables) || incomparables) .NotYetUsed("incomparables != FALSE") : # missing value where TRUE/FALSE needed the raised error is clearly not the

Hello! I have the problem that in my function the passed variable is not used, but the variable name of the dataframe itself?- difficult to explain, but an easy example: TestFunc<-function(df, group) { ??? print(names(subset(df, select=group))) } df1<-data.frame(group="G1", visit="V1", value=0.9) TestFunc(df1, c("group", "visit")) Result: [1]

the following is a trivialized version of some functional code i tried to use in r: (funcs = lapply(1:5, function(i) function() i)) # a list of no-parameter functions, each with its own closure environment, # each supposed to return the corresponding index when applied to no arguments sapply(funcs, function(func) func()) # supposed to return c(1,2,3,4,5) there is absolutely nothing unusual in

Dear all, Myself Vijaykumar Muley working as senior research fellow. By training I am a computational biologist with not a strong knowledge of statistics. I have done some analysis which is explained as follows, I have 10340 (X) profiles of binary vectors with same length(N=845), I will call then "gene profiles" for example... v1 v2 v3 v4.....vN a 1 0 1 0 1 b 0

Dear R Gurus: How do I find the functions which are primitives, please? Thanks, Edna Bell

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48365 OS: Ubuntu 8.04 Linux 32bit Submission from: (NULL) (129.241.110.141) sprintf has a documented limit on strings included in the output using the format '%s'. It appears that there is a limit on the length of strings included with, e.g., the format '%d' beyond which surprising things happen (output modified for conciseness):

Full_Name: Wacek Kusnierczyk Version: 2.10.0 r48269 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (129.241.199.164) In the following example (and many other cases): quote(a=1) # 1 the argument matching is apparently incorrect wrt. the documentation (The R Language Definition, v 2.8.1, sec. 4.3.2, p. 23), which specifies the following algorithm for argument matching: 1. Attempt to

On Fri, Apr 24, 2009 at 14:40, Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> wrote: > maechler at stat.math.ethz.ch wrote: >> >> =A0 =A0 vQ> sprintf has a documented limit on strings included in the ou= tput using the >> =A0 =A0 vQ> format '%s'. =A0It appears that there is a limit on the leng= th of strings included >> =A0 =A0 vQ>

m = matrix(1:4, 2) apply(m, 1, cat, '\n') # 1 2 # 3 4 # NULL why the null? vQ

Hi all I have the following regular expression problem: I want to find complete elements of a vector that end in a repeated character but where the repetition doesn't make up the whole word. That is, for the vector vec: vec<-c("aaaa", "baaa", "bbaa", "bbba", "baamm", "aa") I would like to get "baaa" "bbaa"

Dear R Gurus: I read somewhere that functions are considered vectors. Is this true, please? thanks Edna Bell

Full_Name: Wacek Kusnierczyk Version: 2.8.0 and 2.10.0 r48242 OS: Ubuntu 8.04 Linux 32 bit Submission from: (NULL) (80.202.30.36) The following raises an error: if (as.raw(1)) 1 # error: unimplemented type 'raw' in 'asLogical' However, ?'if' says: " Arguments: cond: A length-one logical vector that is not 'NA'. Conditions of length

I wrote As a beginner, I agree .... the for loop is much clearer to me. Wacek Kusnierczyk <Waclaw.Marcin.Kusnierczyk at idi.ntnu.no> replied > >well, that's quite likely. especially given that typical courses in >programming, afaik, include for looping but not necessarily functional >stuff -- are you an r beginner, or a programming beginner? > Both. My PhD is in

Tested in R 2.8.1 Windows > ff <- formals(function(x)1) > ff1 <- as.list(function(x)1)[1] # ff1 acts the same as ff in the examples below, but is a list rather than a pairlist > dput( ff , control=c("warnIncomplete")) list(x = ) This string is not parsable, but dput does not give a warning as specified. > dput( ff ,

The explanation is that quote() is a primitive function and that the argument matching rules do not apply to primitives. That section of the R Language definition should say that primitives are excluded; it is documented in ?.Primitive. -thomas On Thu, 2 Apr 2009 waku at idi.ntnu.no wrote: > Full_Name: Wacek Kusnierczyk > Version: 2.10.0 r48269 > OS: Ubuntu 8.04 Linux 32 bit

Dear all, let's assume I have a vector of character strings: x <- c("abcdef", "defabc", "qwerty") What I would like to find is the following: all elements where the word 'abc' does not appear (i.e. 3 in this case of 'x'). Since I am not really experienced with regular expressions, I started slowly and thought I find all word were