similar to: Multiple Intersections

useR's, First, I would like to say thanks to John Fox for providing this segment of code to perform intersection for multiple sets: intersection <- function(x, y, ...){ if (missing(...)) intersect(x, y) else intersect(x, intersection(y, ...)) } I want to execute this function on the rows of a matrix I have: Ik.mat.test <- matrix(c(2,3,6,1,2,6,6,1,2),byrow=T,nrow=3) > Ik.mat.test

Hi, I understand that the glm.fit calls LINPACK fortran routines instead of LAPACK because it can handle the 'rank deficiency problem'. If my data matrix is not rank deficient, would a glm.fit function which runs on LAPACK be faster? Would this be worthwhile to convert glm.fit to use LAPACK? Has anyone done this already?? What is the best way to do this? I'm looking at very

v1<-c("a","b","c","d") v2<-c("a","b","e") v3<-c("a","f","g") I want to get the intersection of v1,v2,v3,ie "a" How can I do then? What I know is only for 2 vectors via "intersect" function,but don't know how to deal with multiple vectors. Many thanks

Hi, Sorry for the very short explanation about the problem of intersection. I have a wave function monitored from the heart beat in a particular interval of times.?Apart?fom that, there is?a line with positive slope (e.g: y = x+2) which lies across the wave and intersect on a number of points. My problem is i have no exact equation for?such a?complex harmonic wave produced by the heart

Hi, I would like to find out the coordinates of the intersection points of 2 density curves. I did a search but i didn't get any significant results. I really hope some of you have some ideas. here it is an example: set.seed(123) x1 <- rnorm(100, 1, 1) x2 <- rnorm(100, 0, 1) d1 <- density(x1) d2 <- density(x2) plot(d1, col = 2) lines(d2, col = 4) Now i would like to know

Hi I have probably a very simple question but I'm going crazy trying to find the solution. I have two data.frames with headers and I'm doing an intersection between them by names, such that the intersected data.frames are returned by: df1[intersect(names (df1), names(df2))] and the same for df2 Now, I want to have all the opposite data that did not intersect. I tried to do:

Hello group, I am learning R and I am new to many concepts.I face the following errors when I am trying to execute the following. I have 4 text files with protein accession numbers. I wanted to represent them in a venn diagram and for that I using intersect and setdiff functions. My data looks like this: file1.txt (c): NP_000005 NP_000020 NP_000030 NP_000053 file2.txt(e): NP_000005 NP_000020

Hi all, The ?intersect entry kindly points out that it discards duplicate entries. I'm looking, however, to get the intersection while KEEPING duplicate entries, and there are no instructions on how to accomplish this using intersect(). Does anybody have any idea how this might be done, or am I going to need to program something from scratch (something like ordering the vectors and then

Hello all, I manually created an hclust object. Now I am looking to reorder the leafs so they won't intersect with each other, and would be happy for advises on how to do that. Here is an example code: #------------------------------------- a <- list() # initialize empty object # define merging pattern: # negative numbers are leaves, # positive are merged clusters (defined by row

Hi, Suppose I have two vectors, not necessarily the same length (in fact, they usually are different lengths): y.1 that has increasing values between 0 and 1; y.2 that has decreasing values between 1.0 and 0. You can picture these as being supply (= y.1) and demand (= y.2) curves from economics. I typically plot these vectors on the same graph against a common x variable, which happens to

Hi everyone, I am pretty new to R, so be patient. I am trying to intersect 2 columns and in the rows that intersect, I want information from the 3rd column to be brought with it. I think it will be easier to explain with an example example.csv <http://r.789695.n4.nabble.com/file/n4675136/example.csv> . In my example, I have a reference list of fruit (first column), and my fruit of

Hi, I searched the archives and did not find a good solution to that. assume I have 10 sets and I want to have the common character elements of them. how could i do that? -- Weiwei Shi, Ph.D Research Scientist GeneGO, Inc. "Did you always know?" "No, I did not. But I believed..." ---Matrix III

Hi, I''ve been playing with Arel for a few days, but I feel really confused about predicates / arrays intersection. Let''s say I have 3 models: users, (bank) accounts and transfers. An account belongs to a user, and a transfer is made of a source and target accounts (see the snippets below). Given a user, I want to query his transfers. I can go this way in the User class: def

Hi all, As far as I can tell, the only canned way to do an intersect between two vectors of ints is the intersect(vec1, vec2) function -- is there another function I'm missing for intersecting more than two vectors?? TIA, Ken

Dear R-help subscribers, I'm trying to write a function to generate data simulating the image created by a point radiation source in a plane on a screen where there is filter with a single circular aperture in it between the source and the screen. Following some guides (including Intro to R and some I found online) and examples I have specified the function (full code below question) with

How can I create intersections of vectors? a <- c(1,2,3) b <- c(1,5,6) the intersected list c should contain c(1)... Ralf

Hi all, I am wondering if this is a bug in the Matrix package or if it something that I am just getting wrong...here is an example: > m = matrix(0,4,4) > dimnames(m) = list(letters[1:4], letters[5:8]) > r = c("a","b","a","d") > m[r,2] = 1 > m e f g h a 0 1 0 0 b 0 1 0 0 c 0 0 0 0 d 0 1 0 0 > M = Matrix(0,4,4) > dimnames(M) =

Hello. I have a problem with 2 dataframes. There are 2 columns - "value" and "dates". These dataframes have different dimension. Some dates coincide. And I need to intersect them by dates and have on output two dataframes with identical columns "dates" and new dimension . "value" have to recieve in compliance with dates. Regards, Aleksander. [[alternative

Dear list, Given a list of elements like: aa <- list(one=c("o", "n", "e"), tea=c("t", "e", "a"), thre=c("t", "h", "r", "e")) Is there a function that returns the intersection between all? Both match() and intersect() only deal with two arguments, but sometimes I

This code gives an error: a <- ts(1:10, start=0, freq=10) b <- ts(1:10, start=1, freq=10) ts.intersect(a,b) This one works normally (and correctly): a <- ts(1:10, start=0) b <- ts(1:10, start=1) ts.intersect(a,b) Antonio, Fabio Di Narzo. P.S. How to switch off italian error messages to post on r-help? > version _ platform i386-pc-mingw32 arch i386 os