Displaying 20 results from an estimated 10000 matches similar to: "Bug in ci.plot(HH Package) (PR#11163)"
2013 Nov 14
1
issues with calling predict.coxph.penal (survival) inside a function
Thanks for the reproducable example. I can confirm that it fails on my machine using
survival 2-37.5, the next soon-to-be-released version,
The issue is with NextMethod, and my assumption that the called routine inherited
everything from the parent, including the environment chain. A simple test this AM showed
me that the assumption is false. It might have been true for Splus. Working this
2009 Mar 12
3
help with predict and plotting confidence intervals
Dear R help,
This seems to be a commonly asked question and I am able to run examples that have been proposed, but I can't seems to get this to work with my own data. Reproducible code is below. Thank you in advance for any help you can provide.
The main problem is that I can not get the confidence lines to plot correctly.
The secondary problem is that predict is not able to find my object
2012 Oct 08
6
How to use Lines function to draw the error bars?
fit lwr upr
1 218.4332 90.51019 346.3561
2 218.3906 90.46133 346.3198
3 218.3906 90.46133 346.3198
4 161.3982 44.85702 277.9394
5 192.4450 68.39903 316.4909
6 179.8056 56.49540 303.1158
7 219.5406 91.52707 347.5542
8 162.6761 46.65760 278.6945
9 193.8506 70.59838 317.1029
10 181.3816 58.11305 304.6502
11 221.2871 92.14366 350.4305
12 164.2947 47.91081 280.6785
13
2010 Dec 25
2
predict.lrm vs. predict.glm (with newdata)
Hi all
I have run into a case where I don't understand why predict.lrm and
predict.glm don't yield the same results. My data look like this:
set.seed(1)
library(Design); ilogit <- function(x) { 1/(1+exp(-x)) }
ORDER <- factor(sample(c("mc-sc", "sc-mc"), 403, TRUE))
CONJ <- factor(sample(c("als", "bevor", "nachdem",
2010 Jul 27
1
problem with zero-weighted observations in predict.lm?
In modelling functions some people like to use
a weight of 0 to drop an observation instead of
using a subset value of FALSE. E.g.,
weights=c(0,1,1,...)
instead of
subset=c(FALSE, TRUE, TRUE, ...)
to drop the first observation.
lm() and summary.lm() appear to treat these in the
same way, decrementing the number of degrees of
freedom for each dropped observation. However,
predict.lm() does
2007 Nov 20
1
plotting confidence intervals of regression line
Hello,
I am trying to generate a confidence interval (90 or 95%) of a regression
line. This is primarily just for illustration on a scatter plot (i.e. I am
trying to make this
http://www.ast.cam.ac.uk/~rgm/scratch/statsbook/graphics/anima4.gif).
I have been trying to use the predict.lm function, with interval set as
"confidence", but this still seems to be giving me a prediction
2013 May 17
2
zigzag confidence interval in a plot
Dear All,
When I plot the values and linear regression line for one data set, it is fine. But for another one I see zigzags, when I plot the confidence interval
>cd
Depth CHAOsep12RNA
9,94 804
25,06 1476,833333
40,04 1540,561404
50,11 1575,166667
52,46 349,222222
54,92 1941,5
57,29 1053,507042
60,11 1535,1
70,04 2244,963303
79,97 1954,507042
100,31 2679,140625
>
2013 Jan 30
2
How does predict() calculate prediction intervals?
For a given linear regression, I wish to find the 2-tailed t-dist
probability that Y-hat <= newly observed values. I generate prediction
intervals in predict() for plotting, but when I calculate my t-dist
probabilities, they don't agree. I have researched the issues with variance
of individual predictions and been advised to use the variance formula
below (in the code).
I presume my
2008 Nov 08
4
Plotting Standard Regression Fit-Am I wrong or a bug?
I'm trying to plot a time series (quarterly observations, seasonal effect,
T=56),regression line and predicted point on the same plot.
I'm using following commands:
> plot(qdts,xlim=c(1982,1997))
> lines(fitted(m2)~time,data=qd,col="red")
> points(predict(m2,newdata=nqd),col="blue")
where:
qdts<-ts(qd$durables,start=c(1982,1),freq=4)
2011 Jan 16
1
Displaying ylab in mfrow
Dear R users,
I cannot display ylab with the following code while trying to stack 7 rows
of 3 histograms each. Thanks in advance!
par(mfrow=c(7,3))
par(mar=c(2,2,2,2))
par(oma=c(5,5,0,0))
with (newdata <- subset(table, Month1 == "1"), hist(newdata$CarapWid,
breaks=5*(0:80), col="gray80", main="All individuals", xlab="", xlim
=c(15,85), ylab="April
2017 Jun 12
0
plotting gamm results in lattice
Hi Maria
If you have problems just start with a small model with predictions and then plot with xyplot
the same applies to xyplot
Try
library(gamm4)
spring <- dget(file = "G:/1/example.txt")
str(spring)
'data.frame': 11744 obs. of 11 variables:
$ WATERBODY_ID : Factor w/ 1994 levels "GB102021072830",..: 1 1 2 2 2 3 3 3 4 4 ...
$ SITE_ID
2012 Apr 20
1
predictOMatic for regression. Please try and advise me
I'm pasting below a working R file featuring a function I'd like to polish up.
I'm teaching regression this semester and every time I come to
something that is very difficult to explain in class, I try to
simplify it by writing an R function (eventually into my package
"rockchalk"). Students have a difficult time with predict and newdata
objects, so right now I'm
2008 Nov 24
1
Discrepancy in the PBC data set
The data set in R is wrong. I've found mistakes on 2 lines in a quick look.
I don't know if the data is incorrect in the Appendix of Fleming and
Harrington as well (someone seems to have borrowed my copy), which is where the
data set appears to have been taken from, given all the "-9" codes in it. (Note,
Tom Fleming originally got the data from me, so I'm fairly
2016 Apr 21
5
Calcular Error en modelo lineal
Enun ejemplo real estoy viendo como el intervalo de confianza usando lo que me comentas me ha salido mucho más pequeño de lo que la realidad luego refleja. ¿Cómo es esto posible??
Es decir, veo que para valores de 2,70 obtengo una respuesta de entre 2,69 y 2,90 y sin embargo luego en la realidad tengo valores entre 2,20 y 3
Gracias
Jesús
From: jorgeivanvelez en gmail.com
Date: Thu, 21 Apr
2006 Mar 11
2
how to create analog stripchart plots of x vs t (t=mm/dd/yyyy hh:mm:ss)
Hello r-experts,
I sure could us a little help.
I have an ever updating text file with timestamped data in it. I can
reformat in anyway I want if need be but currently I have chosen to make
columns of date, time and measuresed value (comma delimeted and with the
dates and times in quotes to interpret them as strings).
Here is a small section of my text data file:
2010 Aug 13
1
subsetting data points within confidence limit
Dear R-list
Suppose I have a data set stored in hmet, for which I did get confidence
limit on a linear regression as shown below.
My question is how I can subset only data points which are within the
confidence limit.
Thank you.
Keun-Hyung
---------------------------------------------------------------
Al=rnorm(100, 3)
Cd=rnorm(100, 0.2)
hmet=data.frame(Al=Al, Cd=Cd)
plot(Al,
2017 Jun 12
2
plotting gamm results in lattice
Dear all,?
I hope that you can help me on this. I have been struggling to figure this out but I haven't found any solution.
I am running a generalised mixed effect model, gamm4, for an ecology project. Below is the code for the model:
model<-gamm4(LIFE.OE_spring~s(Q95, by=super.end.group)+Year+Hms_Rsctned+Hms_Poaching+X.broadleaved_woodland? ? ? ? ? ? ?+X.urban.suburban+X.CapWks,
2013 Sep 22
2
colores
Como usas la función image puedes consultar la ayuda ?image o help(image) y
encontrarás el siguiente ejemplo donde se usa un diferente color Palette
(mencionada por pepeceb en su respuesta).
x <- 10*(1:nrow(volcano))
y <- 10*(1:ncol(volcano))
image(x, y, volcano, col = terrain.colors(100), axes = FALSE)
# O puedes usar directamente el número para indicar el color
image(x, y, volcano, col =
2005 Jul 21
1
About object of class mle returned by user defined functions
Hi,
There is something I don't get with object of class "mle" returned by a
function I wrote. More precisely it's about the behaviour of method
"confint" and "profile" applied to these object.
I've written a short function (see below) whose arguments are:
1) A univariate sample (arising from a gamma, log-normal or whatever).
2) A character string
2007 Jun 19
1
help w/ nonlinear regression
Dear All,
I'd like to fit a "kind" of logistic model to small data-set using nonlinear least-squares regression. A transcript of R-script are reproduced below. Estimated B and T (the model's coeff, herein B=-8,50 and T=5,46) seem appropriate (at least visually) but are quite diff from those obtained w/ SPSS (Levenberg-Marquardt): B=-19,56 and T=2,37. Am I doing something wrong in