similar to: "[<-" plus drop-type extra argument

Displaying 20 results from an estimated 7000 matches similar to: ""[<-" plus drop-type extra argument"

2006 Oct 31
1
setReplaceMethod
Hi If x <- 1:10 then x[5] <- 1i will promote x to be a complex vector. Suppose I have an S4 class "brob", and have functions is.brob(), as.brob(), as.numeric() and so forth (minimal self-contained code below). If x is numeric (1:10, say) and y is a brob, what is the best way to make x[5] <- y promote x to a brob in the same way as the complex example? Or is
2008 May 07
1
optional setValidity()
Hi Suppose I have an S4 class "foo" and a validity checking function ".checkfoo()": setClass("foo", representation=representation("numeric")) setValidity("foo" , .checkfoo) is fine; in my application, .checkfoo() verifies that a bunch of necessary conditions are met. But .checkfoo() is very time consuming and I want to give users the option
2005 Jun 13
3
extracting components of a list
Hi how do I extract those components of a list that satisfy a certain requirement? If jj <- list(list(a=1,b=4:7),list(a=5,b=3:6),list(a=10,b=4:5)) I want just the components of jj that have b[1] ==4 which in this case would be the first and third of jj, viz list (jj[[1]],jj[[3]]). How to do this efficiently? My only idea was to loop through jj, and set unwanted components to NULL,
2004 Sep 08
3
do.call("[", ...) question
Hi again everyone I have an arbitrarily dimensional array "a" and a list "jj" of length length(dim(a)). The elements of jj are vectors of indexes. How do I use do.call() to extract a[ jj[[1]], jj[[2]], jj[[3]], ...] ? Toy example follows: a <- matrix(1:30,5,6) jj <- list(5:1,6:1) I want the following a[ jj[[1]],jj[[2]] ] How do I do this? OBAttempts:
2007 Apr 17
1
no visible binding for global variable
Hello everyone I am trying to get one of my packages through R's QC. The package is clean for me under R-2.4.1, R-2.5.0, and R-devel, but Kurt gets > > * checking R code for possible problems ... WARNING > hypercube: no visible binding for global variable ?f? Function hypercube() [cut-&-pasted below] is intended to return an adjacency matrix for an n-dimensional
2004 Jan 14
1
arrows on contour lines
Hello everybody I'm using contour() to draw streamlines of potential flow, eg jj <- seq(from= -4, to=4,len=20) jj <- outer(jj,jj,function(x,y){x})+1i*outer(jj,jj,function(x,y){y}) f <- function(x){x^2} contour(Im(f(jj)), nlevels=44 , labels="") How best to put arrows on the contour lines to show the direction of flow? (ie I want contour lines looking like
2020 Feb 11
3
[v 2.3.4.1][quota] recalculation
Hello, I can't find the information on the wiki :( When is the quota recalculated after a mail deletion ? For instance, I am running low of storage and I use Thunderbird to delete large mail. I only notice a recalculation when I quit Thunderbirdb and I relaunch it. Even, with doveadm CLI, as long as Thunderbird is not disconnected on the client side, the server didn't recalculate the
2005 Dec 05
1
apply() and dropped dimensions
Hi I am having difficulty with apply(). I want apply() to return a matrix, but sometimes a vector is returned. Toy example follows. Function jj() takes a couple of matrices m1 and m2 as arguments and returns a matrix with r rows and c columns where r=nrow(m2) and c=nrow(m1). jj <- function(m1,m2,f,...){ apply(m1, 1, function(y) { apply(m2, 1, function(x) { f(x, y, ...)
2008 Mar 26
5
S4 slot with NA default
Hi How do I specify an S4 class with a slot that is potentially numeric, but NA by default? I want the slot to be NA until I calculate its value (an expensive operation, not needed for all applications). When its value is known, I will create a new object with the correct value inserted in the slot. I want "NA" to signify "not known". My attempt fails because
2015 Aug 21
3
Would a spreadsheet be a good project using LLVM?
I am thinking about writing a new open source spreadsheet application since I think the spreadsheet applications out there (Microsoft Excel, LibreOffice Calc, etc.) do not have some features that I would really like to use. I would like the spreadsheet to recalculate very fast and wondered if it would make sense to use LLVM to calculate the cell values quickly. Each cell of a spreadsheet
2007 Jun 27
1
inherits() and virtual classes
Hi How do I test for an object having a particular virtual class? In the following, "onion" is a virtual class, and "octonion" is a non-virtual class contained in onion. The last call to inherits() gives FALSE [R-2.5.0], when inherits.Rd led me to expect TRUE. setClass("onion", representation = "VIRTUAL" )
2015 Aug 21
3
Would a spreadsheet be a good project using LLVM?
Mats, Thanks for your feedback. I guess I should elaborate on one of the features I would like to implement. In today's spreadsheets if you want to crunch a lot of data, you usually put the data in rows and put expressions in cells to the right of the data and repeat those cells for every row of the data. I would like to create a spreadsheet system that can process the same quantity of
2007 Dec 19
3
array addition
Hi suppose I have two arrays x1,x2 of dimensions a1,b1,c1 and a2,b2,c2 respectively. I want x = x1 "+" x2 with dimensions c(max(a1,a2), max(b1,b2),max (c1,c2)) with x[a,b,c] = x1[a1,b1,c1] + x2[a2,b2,c2] if a <=min(a1,a2) , b<=min (b1,b2), c<=min(c1,c2) and the other bits either x1 or x2 or zero according to whether the coordinates are "in range" for
2005 Oct 05
2
eliminate t() and %*% using crossprod() and solve(A,b)
Hi I have a square matrix Ainv of size N-by-N where N ~ 1000 I have a rectangular matrix H of size N by n where n ~ 4. I have a vector d of length N. I need X = solve(t(H) %*% Ainv %*% H) %*% t(H) %*% Ainv %*% d and H %*% X. It is possible to rewrite X in the recommended crossprod way: X <- solve(quad.form(Ainv, H), crossprod(crossprod(Ainv, H), d)) where quad.form() is a little
2004 Oct 26
1
persp(), scatterplot3d(), "..." argument
Hello list. I very often need 3d scatterplots, and use scatterplot3D quite a lot. I am trying to modify persp() to plot scatterplots, and make use of the theta and phi arguments that persp() offers. I am having some difficulty passing the correct arguments to persp(). Here is my function so far. Much of it is copied from the persp() manpage. points3d <- function(x,y,z,
2004 Oct 26
1
persp(), scatterplot3d(), "..." argument
Hello list. I very often need 3d scatterplots, and use scatterplot3D quite a lot. I am trying to modify persp() to plot scatterplots, and make use of the theta and phi arguments that persp() offers. I am having some difficulty passing the correct arguments to persp(). Here is my function so far. Much of it is copied from the persp() manpage. points3d <- function(x,y,z,
2004 Oct 01
2
multiple dimensional diag()
Hi I have two arbitrarily dimensioned arrays, "a" and "b", with length(dim(a))==length(dim(b)). I want to form a sort of "corner-to-corner" version of abind(), or a multidimensional version of blockdiag(). In the case of matrices, the function is easy to write and if a=matrix(1,3,4) and b=matrix(2,2,2), then adiag(a,b) would return: [,1] [,2] [,3] [,4] [,5]
2009 Jan 13
2
particulars of importing/loading libraries
Dear List: Sorry for posting maybe a trivial question, but I have a basic understanding problem. If I have say pack1 and pack2, two R packages, and pack2 depends on and imports pack1 fully (as in the code below), is there a way to make all the functionality of pack1 available for the global and other environments (not only for the functions called from withing pack2) by loading pack2 only? I
2008 Apr 07
3
Overriding axis formatting with custom Axis method, Axis.numeric etc
Dear list: I would like to override the default way R formats plot axes with a custom method(s). Obviously I would prefer to define it as general as possible avoiding writing a custom method for each individual class where possible. The plot.default method (and I assume other methods as well) calls Axis(...) to produce the axis layout depending on data. In this sense it seems reasonable to
2005 Feb 07
4
proportional matrix rows
Hi I have a two-column integer matrix like this: R> jj [,1] [,2] [1,] -1 1 [2,] -2 2 [3,] -7 6 [4,] -8 7 [5,] -6 5 [6,] -9 8 [7,] -5 4 [8,] 3 -3 [9,] -10 9 [10,] -4 3 I want a diagnostic that detects whether a row is a multiple of the first row or not. In this case, this would be rows 1,2, and 8. How to do this