Displaying 20 results from an estimated 2000 matches similar to: "Can't interrupt R-processes in R OSX 2.6.2"
2010 Jun 11
1
glm-test?
Dear R-users,
I would like to test, whether a sample distribution differs significantly from a population distribution. They are not normally distributed. How should I proceed? Using somehow glm-models? How?
The population and the sample data are here. They can be loaded using the load-command.
http://users.utu.fi/attenka/D_Pop
http://users.utu.fi/attenka/D_Samp
Best regards,
Atte Tenkanen
2010 Apr 16
3
Is it ok to apply the z.test this way?
Dear R-users,
I want to check if certain values are from random distribution, that includes values between 0-1. So, it is not really normal even though shapiro.test says it is highly normal... Can I do something like this and think that the values given are right. z.test is from package TeachingDemos.
-------------------------------------------------------------------------------
2010 Jun 16
1
prcomp() and the lenght of PC:s
Hi,
I would like to know whether there is some deeper rationale behind or is it just an established practice that the lenghts of principal components, giving for example by prcomp-function, are normalised to 1?
Best regards,
Atte Tenkanen
University of Turku, Finland
Department of Musicology
+35823335278
http://users.utu.fi/attenka/
2008 Feb 01
2
Saving a big table or matrix
Dear R-users,
How do you save a big table or matrix as an independent object and attach it to your Rdata-project when needed?
Atte Tenkanen
University of Turku, Finland
Department of Musicology
+023335278
2006 Mar 18
2
How to divide too long labels?
Is there any possibility to divide too long text in a plot to two or more
lines, when using labels-parameter in the text()-command?
Here is an example picture:
http://users.utu.fi/attenka/253.jpeg
My example script is something like this:
text(1,0.7,labels=Chordnames[fnid(pcs%%12)]) # according to Larry
Solomon's table http://solomonsmusic.net/pcsets.htm
Chordnames is a long vector with
2006 Oct 06
4
Row comparisons to a new matrix?
Hi,
Can somebody tell me, which is the fastest way to make comparisons between all rows in a matrix (here A) and put the results to the new symmetric matrix? I have here used cosine distance as an example, but the comparison function can be any other, euclidean dist etc.
A=rbind(c(2,3),c(4,5),c(-1,2),c(5,6))
M=matrix(nrow=length(A[,1]),ncol=length(A[,1]))
for(i in 1:length(A[,1]))
{
for(j in
2006 Jun 19
3
Border line width?
Is there some way to change the line widths of plot borders?
I couldn't find any parameters for that purpose.
Atte Tenkanen
University of Turku, Finland
2006 Nov 19
4
The most common row in a matrix?
Hi,
How do you get the most common row from a matrix? If I have a matrix
like this
array(1:3,dim=c(4,5))
[,1] [,2] [,3] [,4] [,5]
[1,] 1 2 3 1 2
[2,] 2 3 1 2 3
[3,] 3 1 2 3 1
[4,] 1 2 3 1 2
in which rows 1 and 4 are similar, I want to find that vector c
(1,2,3,1,2).
Atte Tenkanen
University of Turku, Finland
2006 Aug 22
4
Successive subsets from a vector?
I'd like to pick every imbricated five character long subsets from a
vector. I guess there is some efficient way to do this without loops...
Here is a for-loop-version and a model for output:
VECTOR=c(1,4,2,6,5,0,11,10,4,3,6,8,6);
ADDRESSES=c();
for(i in 1:(length(VECTOR)-4)){
ADDRESSES[i]=paste(VECTOR[i:(i+4)],collapse="")
}
> ADDRESSES
[1] "14265"
2007 Jul 12
2
is.null doesn't work
Hi,
What's wrong here?:
> v=c(`-`,`+`,1,`^`,`^`,NA,NA,"X",9,"X",2)
> i2=16
> v[i2]
[[1]]
NULL
> is.null(v[i2])
[1] FALSE
Is it a bug or have I misunderstood something?
Atte Tenkanen
University of Turku, Finland
2006 Sep 08
8
Weighted association map
Could somebody program this kind of plot type to R, if none exists,
based on mds or correlation tables or some more suitable method? What
do you think about idea? Does it work? None similar or better exists?
http://weightedassociationmap.blogspot.com/
Atte Tenkanen
University of Turku, Finland
2006 Aug 16
5
How to remove similar successive objects from a vector?
Is there some (much) more efficient way to do this?
VECTOR=c(3,2,4,5,5,3,3,5,1,6,6);
NEWVECTOR=VECTOR[1];
for(i in 1:(length(VECTOR)-1))
{
if((identical(VECTOR[i], VECTOR[i+1]))==FALSE){
NEWVECTOR=c(NEWVECTOR,VECTOR[i+1])}
}
> VECTOR
[1] 3 2 4 5 5 3 3 5 1 6 6
> NEWVECTOR
[1] 3 2 4 5 3 5 1 6
_______________________________
Atte Tenkanen
University of Turku, Finland
2010 Jun 23
3
Wilcoxon signed rank test and its requirements
Hi all,
I have a distribution, and take a sample of it. Then I compare that sample with the mean of the population like here in "Wilcoxon signed rank test with continuity correction":
> wilcox.test(Sample,mu=mean(All), alt="two.sided")
Wilcoxon signed rank test with continuity correction
data: AlphaNoteOnsetDists
V = 63855, p-value = 0.0002093
alternative hypothesis:
2006 Jun 15
1
How to change the margin widths in png-plots?
Hello,
I have tried to change the margin widths so that mtext (here "sd of
consecutive pc intervals", look at the picture) and
plot(...,xlab="bar") fits to the picture.
Here is an example:
http://users.utu.fi/attenka/margins.png
This doesn't help:
par(mar=c(5.1, 7.1, 4.1, 2.1))
And here are the commands:
png(filename="/Users/kone/Vaitostutkimus/Pictures/
2006 Aug 19
2
A matrix problem
Hi,
I have a matrix with two columns. The first column means "indexes", the second one contents of those indexes. If I have a MATRIX like this,
> MATRIX
[,1] [,2]
[1,] 1 3
[2,] 5 1
[3,] 2 1
[4,] 1 5
I'd like to get as a result vector the sums of these indexes, something like this:
> c(8,1,0,0,1)
How to do this?
I did solved it this way, but is
2007 Jan 23
1
Scatterplot3d-proposal
Hi,
Does somebody know if there is some trick to betoken the starting points ("on the floor") of the vertical lines in scatterplot3d-plots.
I'd prefer something like that one in the example here
http://users.utu.fi/attenka/proposal3d.jpg
If this is not possible, could this option be added? Sometimes it is not easy to distinguish objects behind the others and for instance in this
2007 Jul 15
2
Break during the recursion?
Hi,
Is it possible to break using if-condition during the recursive function?
Here is a function which almost works. It is for inorder-tree-walk.
iotw<-function(v,i,Stack,Indexes) # input: a vector and the first index (1), Stack=c(), Indexes=c().
{
print(Indexes)
# if (sum(i)==0) break # Doesn't work...
if (is.na(v[i])==FALSE & is.null(unlist(v[i]))==FALSE)
{Stack=c(i,Stack);
2012 Dec 17
3
How to test whether is.element() returns only TRUE's
Hi,
How can I test, whether all the values that is.element() -function returns are TRUE's
Eg.
> (is.element(c(1,4,2),c(1,2,3)))
[1] TRUE FALSE TRUE
This doesn't work:
> (is.element(c(1,4,2),c(1,2,3)))==TRUE
[1] TRUE FALSE TRUE
Best,
Atte Tenkanen, FT, MuM
http://users.utu.fi/attenka/
2007 Jul 07
1
from character string to function body?
Dear R users,
I wonder if it is possible to form a function from a character string. Here is an example:
> x=3
> `-`(`+`(`^`(x,3),`^`(x,2)),1) # Here is my function evaluated.
[1] 35
>
2016 Apr 16
2
Mean of hexadecimal numbers
... and if you need to convert back: ?as.hexmode
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Sat, Apr 16, 2016 at 8:20 AM, Bert Gunter <bgunter.4567 at gmail.com> wrote:
> ?strtoi
>
> You'll have to remove