Displaying 20 results from an estimated 20000 matches similar to: "formula(CO2)"
2017 Oct 08
2
Manipulations with CO2 dataset on R
Hi,
I just started a new course this semester on R, I never used it in my life and i'm stuck on these questions from 3 days, it would be really nice if someone could explain me the answers with the relative commands.
thanks a lot in advance
The following 7 questions are based on the CO2 dataset of R.
1) How many of the plants in CO2 are Mc2 for Plant?
2) How many are either Mc2 or Mn2?
2010 Dec 17
2
newbie question on str output
Hi!
Here is some output from an str command:
> str(CO2)
Classes ‘nfnGroupedData’, ‘nfGroupedData’, ‘groupedData’ and
'data.frame': 84 obs. of 5 variables:
$ Plant : Ord.factor w/ 12 levels "Qn1"<"Qn2"<"Qn3"<..: 1 1 1 1 1 1 1 2
2 2 ...
$ Type : Factor w/ 2 levels "Quebec","Mississippi": 1 1 1 1 1 1 1 1 1 1
...
$
2009 Jun 11
1
formula for degrees of freedom for nonlinear mixed model in nlme
Dear forum members,
What is the formula to calculate denominator degrees of freedom (den df) for nonlinear mixed-effect models with covariates? My model is similar to a CO2 uptake example from Pinheiro and Bates (2000, page 376). In this CO2 dataset, there are two treatments and two types (84 observations in total), but den df for each parameter of the model is 64. Isn’t it too high?
Your
2006 Jul 18
2
Using corStruct in nlme
I am having trouble fitting correlation structures within nlme. I would like to
fit corCAR1, corGaus and corExp correlation structures to my data. I either
get the error "step halving reduced below minimum in pnls step" or
alternatively R crashes.
My dataset is similar to the CO2 example in the nlme package. The one major
difference is that in my case the 'conc' steps are
2006 Mar 15
1
filtering in aggregate
Hello all,
I have a data frame with year, month, species, fishing gear and catch
(Y, M, S, F, C) and I want the sum of C by Y for species "A" and fishing
gear "trawl".
I tried things like aggregate(C[S=="A" & F=="trawl"], list (Year =
Y[S=="A" & F=="trawl"]), fun=sum), but it didn't worked.
To overcome this problem I did
2007 Jun 04
3
test for nested factors
Is there a conventional way to test for nested factors? I.e., if 'a'
and 'b' are lists of same-length factors, does each level specified by
'a' correspond to exactly one level specified by 'b'?
The function below seems to suffice, but I'd be happy to know of a more
succinct solution, if it already exists.
Thanks,
Tim.
---
"%nested.in%" <-
2011 Aug 20
1
Groups and bwplot
Dear R-users,
A while ago, Deepayan Sarkar suggested some code that uses the group
argument in bwplot to create some 'side-by-side' boxplots
(https://stat.ethz.ch/pipermail/r-help/2010-February/230065.html). The
example he gave was relatively specific and I wanted to generalize his
approach into a function. Unfortunately, I seem to have some issues
passing the correct arguments to the
2006 Aug 10
2
index.cond in xyplot
Dear R-users
I have 5 dependent variables (y1 to y5) and one independent variable (x) and
3 conditioning variables (m, n, and 0). Each of the conditioning variables
has 2 levels. I created 2*4 panel plots.
xyplot(y1+y2+y3+y4+y5 ~ x | m*n*o,layout = c(4,2))
I would like to reorder the 8 panels. I tried to use index.cond (e.g.,
index.cond = list(c(1,3,2,4,5,7,6,8)) but it didn't work out.
2004 Nov 29
1
Call to trellis.focus(); thenpanel.superpose()
The following works fine with the x11 device, though it
may well be that an initial plot is overwritten. With a pdf
or postscript device, I get two plots, the first of which
still has the red border from having the focus, while the
second is the plot that I want.
library(lattice); library(grid)
plt <- xyplot(uptake ~ conc, groups=Plant, data=CO2)
print(plt)
2009 Mar 15
2
xyplot of a specific ID number
Dear R list members,
I have a question regarding xyplot. I managed to make a xyplot of all the
IDs by using the syntax below:
xyplot(PA ~ CRPC + CRPT | ID, data = redinteract)
Now, I'd like to make a graph of a specific ID number (e.g., only ID number
301). I thought I could use "subset", but it seems to be not working.
Could anyone let me know how I can make a graph of a
2007 Jan 29
6
Loop with string variable AND customizable "summary" output
Dear All,
I am using R for my research and I have two questions about it:
1) is it possible to create a loop using a string, instead of a numeric vector? I have in mind a specific problem:
Suppose you have 2 countries: UK, and USA, one dependent (y) and one independent variable (y) for each country (vale a dire: yUK, xUK, yUSA, xUSA) and you want to run automatically the following regressions:
2012 Oct 22
3
Error: object 'CO2' not found
Hello:
I am new on R, this is the first time I work with it,
I am trying to run some R example to get learn of them,
but, I have a problem when running the example below:
http://stat.ethz.ch/R-manual/R-patched/library/datasets/html/zCO2.html
CO2.Qn1 <- CO2[CO2$Plant == "Qn1", ]
SSasympOff(CO2.Qn1$conc, 32, -4, 43) # response only
Asym <- 32; lrc <- -4; c0 <- 43
2005 Mar 09
3
from long/lat to UTM
Hi:
Is there any function in R which can convert the
long/lat to UTM(Universal Transverse Mercator)?
There are quite a few converters on Internet.
However, the interface is designed as input->output
which I can not convert lots of locations at the same
time.
Another question is whether there is a function in R
which can tell the time zone from the location's
lat/long?
Thank you!
2006 Oct 06
1
Sum of Bernoullis with varying probabilities
Hi Folks,
Given a series of n independent Bernoulli trials with
outcomes Yi (i=1...n) and Prob[Yi = 1] = Pi, I want
P = Prob[sum(Yi) = r] (r = 0,1,...,n)
I can certainly find a way to do it:
Let p be the vector c(P1,P2,...,Pn).
The cases r=0 and r=n are trivial (and also are exceptions
for the following routine).
For a given value of r in (1:(n-1)),
library(combinat)
Set <- (1:n)
2013 Jul 01
2
Problem with anova and the new abbreviation restrictions
An unwanted side effect of the new restrictions on abrreviated names.
The anova.coxph command, in a slavish copy of anova.lm etc, returns a data frame with
column labels of
loglik Chisq Df Pr(>|Chi|)
If one tries to extract the final column of the table errors result since it is not a
standard R variable name.
> afit <- anova(lm(conc ~ uptake, CO2))
> afit$P
[1]
2005 Dec 08
1
Listing all possible samples of size n form a population of size N
Dear useRs!
I would like to list all possible samples of size n form a population of
size N. Obviously, N must be small (up to 20??) for this to be possible.
For example, let say that N = 3 and n = 2. Therefore, we can say we have
units 1, 2 and 3. I believe all possible samples are : {1,2},{2,3} and
{1,3}.
I would like to emphasize that I am not looking for the number of different
2010 Jul 23
2
re-ordering bwplot
Dear list:
I'm using bwplot to compare concentrations by location and treatment as in:
# using built in data
bwplot( conc ~ Type : Treatment, data = CO2 )
I would like the order of the plots to be: 3,4,1,2. I can't seem to figure this out with index.cond or permc.cond.
Any help is appreciated!
Brad Eck
[[alternative HTML version deleted]]
2006 Aug 22
1
summary(lm ... conrasts=...)
Hi Folks,
I've encountered something I hadn't been consciously
aware of previously, and I'm wondering what the
explanation might be.
In (on another list) using R to demonstrate the difference
between different contrasts in 'lm' I set up an example
where Y is sampled from three different normal distributions
according to the levels ("A","B","C")
2006 Apr 01
2
(no answer)
I have never taken a statistics class nor read a statistics text, but
I am in dire need of help with a trivial data analysis problem for
which I need to write a report in two hours. I have spent 10,000
hours of study in my field of expertise (high frequency noise-making
plant biology) but I've always thought that statistics is something
that can be mastered on short notice.
Briefly, I have
2006 Nov 09
2
Algorithm needed
I have a matrix of size "n" and I want to create a new one in which the columns
are sums of the original matrix, with some order in the sums. For example, if
matrix A has 4 columns, then the new matrix should have 6 columns with the
following info from the columns of A: 1+2, 1+3, 1+4, 2+3, 2+4, 3+4. If matrix A
has 5 columns, then the new matrix has 10 columns: 1+2, 1+3, 1+4, 1+5, 2+3,