similar to: NaN in crossprod

Hello, I have been running linear regressions on large data sets. As 'lm' saves a great deal of extraneous (for me) data including the residuals, fitted.values, model frame, etc., I generally set these to NULL within the object before saving off the model to a file. In the below example, however, I have found that depending on whether or not I run 'lm' within another function or

R-help, Given a simple linear model, say lm(x ~ y + z), I would like to remove model terms that are factors with only one level. Thus, if 'z' were a factor with only one level, lm(x ~ y + z) becomes lm(x ~ y + 1). Likewise, if both 'y' and 'z' are one-level factors, then the resulting calculation is simply lm(x ~ 1). Unfortunately, I have not been able to come up with an

Hello, I wanted to suggest that the below method for split.Date be added to the base library to significantly speed up splits with values of class Date. In the below example I show a speed improvement of 175x for 1000 data points. On a vector of size 1e6, the time difference was 22 minutes for split.default versus 0.3 seconds for the split.Date function below (!). Note that this improvement will

Hello, I was playing around with the newly implemented 'incomparables' argument in 'match' and realized the argument does not behave anything like I expected. Can someone explain what is going on here? Sorry if I'm misreading the documentation. > match(1:3, 1:3, incomparables=1) [1] NA 2 3 # This seems right, the 1 in 'x' is 'incomparable' >

I glanced at the .leap.seconds object and noticed that it has not been updated for the most recent leap second that occurred 2005 December 31, 23h 59m 60s. See the IERS bulletin here: http://hpiers.obspm.fr/iers/bul/bulc/bulletinc.dat Moreover, after a more careful glance at the .leap.seconds object, I noticed that there are two incorrect entries. First, there was not a leap second on 1986 June

Hello, I've decided to take the leap and try my hand at the lattice package, though I am getting stuck at what one might consider a trivial problem, plotting text at a point in a graph. Apologies in advance if (that) I'm missing something extremely basic. Consider in base graphics: > plot(1:10) > text(2, 4, "Text") In the above you will see text centered at the point (2,

Hello all, I just upgraded to R 2.7.0 and found that the behavior of 'var' and 'sd' have changed in the presence NAs (this wasn't explicit in the NEWS file, though I see it probably has to do with the change for cor/cov). Anyway, I just want to make sure that it was intentional to produce an error when there was all NAs and na.rm=TRUE, rather than returning an NA (like R

FYI,=20 I've tried posting the below message twice to the bug tracking system, once by email (below), and the second time 5 days later directly to the bugs.r-project.org website. As far as I can tell, the bug tracking system hasn't picked this up. Also it looks like the latest "incoming" bug is dated 25 May 2008, so perhaps others are having difficulty as well. (cc: r-bugs)

?"=", ?"==", ?"!=", ?">=", and ?"<=" sends me to the documentation for ?help on Windows, while returning the correct documentation on Linux. Robert > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 2 minor

R-devel, I discovered a segfault in my R code that boiled down to my incorrect use of the Recall() function embedded within a with() function. Since segfaults are generally bad things, even when it's the user's fault for writing nonsense code, I thought I'd pass along the offending code. I've tested the crash on R 2.11.1 (on Linux and Mac), but not in devel versions of R. HTH,

Shouldn't this work? > .a <- 5 > exists(".a") [1] TRUE > getAnywhere(".a") Error in exists(x, envir, mode, inherits) : invalid first argument getAnywhere doesn't seem to like the "." prefix. Is this a bug? Thanks, Robert Robert McGehee Geode Capital Management, LLC 53 State Street, 5th Floor | Boston, MA | 02109 Tel: 617/392-8396

I have found a solution to the new("call") problem that I believe produces the correct behavior for the default call object, and am also reclassifying this as a bug, as I believe the current behavior to be incorrect. Recap, the following error occurs: > new("call") Error in print("<undef>"()) : couldn't find function "<undef>" It looks

There seems to be a bug in seq.Date such that it will not allow the user to pass in length.out =3D NULL, despite the fact that this is the = default argument. For example: > dt1 <- as.Date("2004-12-31") > dt2 <- as.Date("2005-12-31") > seq.Date(dt1, dt2, length.out =3D NULL, by =3D "month") Error in seq.Date(dt1, dt2, length.out =3D NULL, by =3D

R Developers, 1000000000000000000 %% 11 [1] -32 I now understand that integers cannot be larger than .Machine$integer.max, but because the above produces a result than is patently wrong instead of an error, I'm reporting this as a bug. Thank you for the incredible contributions all of you have made in developing the R platform. Best, Robert Robert McGehee Geode Capital Management, LLC 53

R-developers, I've encountered another perl library regex bug that causes a segmentation faults on my Linux/Windows R session. I reduced the script to the snippet below. (Apologies if this was fixed with bug 7479, but this bug seems quite different). string <- paste(rep("=", 10000), collapse = " ") crash <- function(x) { for (i in 1:5) { x <-

Hello, I'm trying to convert times in the EST/EDT (New York) format to times in the GMT/BST (London) and UTC+9 format (Tokyo). That is, if I know what time it is in New York, what is local time in London and Tokyo? Ex: Here's the conversion from New York EST/EDT time to London's GMT/BST time zone for three days in 2007. Note that the US and London change to daylight savings on

I had some fun this afternoon coding up a 'maze generator' in R. I thought I'd pass along the fruits of my labor for everyone's amusement. As written, every point is connected to every other point, so feel free to 'start' and 'finish' anywhere you like. Have fun! --Robert PS. Feel free to pass along suggestions or comments.

Is it correct (by its lack of mention in the R-Language Definition Manual) that it is impossible to create a user-defined unary operator? Ex: (This doesn't work, but it's an example of what I'm looking for) > "%PLUSONE%" <- function(x) x + 1 > %PLUSONE% 2 [1] 3 And if the above is impossible, am I limited to only the + - ~ ! unary operators for overloading? On

I'm trying to build a recursive set of functions that take a set of arguments, change some of the arguments and recursively call the same (or different) function. For example here's a stupid recursive counting function that prints back all integers from x to 0 (and ignores arguments y and z) cnt <- function(x, y, z) { stopifnot(is.numeric(x)) print (x) recursionFUN <-

Hello, I have a system command that occasionally fails and writes output to standard error, which R will print to the screen when ignore.stderr = FALSE. For example: > system("BadCommand") sh: line 1: BadCommand: command not found I would like to know if the above command fails, and can presumably do this by parsing the stderr message that R prints to the screen. My (hopefully