similar to: [debug] package - Error in all.levs (PR#9638)

Displaying 20 results from an estimated 800 matches similar to: "[debug] package - Error in all.levs (PR#9638)"

2008 Aug 26
1
Dramatic slowdown of R 2.7.2?
Dear R users/developers, simple comparison of code execution time of R 2.7.1 and R 2.7.2 shows a dramatic slowdown of the newer version. Rprof() identifies .Call function as a main cause (see the code below). What happened with R 2.7.2? Kind regards Marek Wielgosz Bayes Consulting ######### Probably useful info ############### ### CPU: Core2Duo T 7300, 2 GB RAM ### WIN XP ### both standard
2009 May 18
1
S4 method dispatch and namespaces: why is default method selected
Hi, I ran into the following peculiarity involving S4 method dispatch and namespaces. I develop a package which have a namespace and which depends on 'pixmap' package, which itself does not have a namespace. Now, in my package I have a class which has a slot for objects from class "pixmap" and I want to have a "plot" method for this new class. Not to clutter the
2007 Jul 25
2
initalizing and checking validity of S4 classes
Dear useRs and wizaRds, I am currently developing a set of functions using S4 classes. On the way I encountered the problem exemplified with the code below. For some reason the 'validity' method does not seem to work, i.e. does not check for errors in the specification of the slots of the defined class. Any hints? My understanding of the whole S4 system was that validity checks are made
2012 Aug 30
1
How to modify the values of the parameters passing via ...
Dear Friends, Let's assume there are three parameters that were passed into fun1. In fun1, we need to modify one para but the remains need to be untouched. And then all parameters were passed into fun2. However, I have failed to achieve it. Please see the following code. ########################################## fun1 <-function(x, y, z=10) {x+y+z;} fun2 <-function(aa, ...) {
2002 Sep 17
3
[LLVMdev] questions
Sorry I got really overwhelmed by so many classes and member functions in LLVM. So would you please clarify some problems I have? 1. If I see this instruction in the function. %S.i = alloca %struct.SimpleStruct Suppose SimpleStruct is as following: struct.SimpleStruct = type { int, double } When I read the instruction, how can I know the type of simplstruct, should I use 'getType'
2004 Mar 25
1
mlocal/mtrace inside a loop
Hello I need some help in figuring Bravington’s debugger out. Ok I have 2 functions, fun1 and fun2 saved in a ASCII file say filename is funs. Fun1 has a loop which calls fun2, fun2 has a loop which fails and I need to find out the value of the variables of the fun2 and fun1 loops at the specific iteration that fails. Both fun1 and fun2 loops will iterate thousands of times so line by line debug
2006 Aug 09
3
objects and environments
Dear list, I have two functions created in the same environment, fun1 and fun2. fun2 is called by fun1, but fun2 should use an object which is created in fun1 fun1 <- function(x) { ifelse(somecondition, bb <- "o", bb <- "*") ## mymatrix is created, then myresult <- apply(mymatrix, 1, fun2) } fun2 <- function(idx) { if (bb == "o) { #
2009 Oct 01
1
pass "..." to multiple sub-functions
Dear list, I know I have seen this discussed before but I haven't been successful in searching for "ellipsis", "dots", "..." in the archives. I would like to filter "..." arguments according to their name, and dispatch them to two sub-functions, say fun1 and fun2. I looked at lm() but it seemed more complicated than I need as it modifies the calling
2017 Apr 30
1
`match.call` and dots substitution
I'm noticing some interesting behavior in `match.call` in some corner-ish cases that arise when you try to use `match.call` to match a "grandparent" function and there are dots involved: fun0 <- function(a, ...) fun1(...) fun1 <- function(b, ...) fun2() fun2 <- function() match.call( fun1, sys.call(sys.parent()), expand.dots=FALSE,
2011 Apr 07
2
Two functions as parametrs of a function.
Hi R users: I'm trying to make a function where two of the parameters are functions, but I don't know how to put each set of parameters for each function. What am I missing? I try this code: f2<-function(n=2,nsim=100,fun1=rnorm,par1=list(),fun2=rnorm,par2=list()){ force(fun1) force(fun2) force(n) p1<-unlist(par1) p2<-unlist(par2) force(p1) force(p2)
2012 Nov 20
2
correct function formation in R
Dear list! ? I have question of?'correct function formation'. Which function (fun1 or fun2; see below) is written more correctly? Using ''structure'' as output or creating empty ''data.frame'' and then transform it as output? (fun1 and fun1 is just for illustration). ? Thanks a lot, OV ? code: input <- data.frame(x1 = rnorm(20), x2 = rnorm(20), x3 =
2013 Jul 02
2
cache most-recent dispatch
Hi, S4 method dispatch can be very slow. Would it be reasonable to cache the most recent dispatch, anticipating the next invocation will be on the same type? This would be very helpful in loops. fun0 <- function(x) sapply(x, paste, collapse="+") fun1 <- function(x) { paste <- selectMethod(paste, class(x[[1]])) sapply(x, paste,
2009 May 01
1
integrate with large parameters
Dear R-users, i have to integrate the following function `fun1` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a)) } but if l1 is large, i get the "non-finite function value" error, so my idea is to rescale with exp(-l1) `fun2` <- function (a, l1, l2) { exp(log(l1) * (a - 1) - l2 * lgamma(a) - l1) } but it seems this doesn't solve the problem, when
2014 Jan 25
1
package NAMESPACE question
Hello, I'm building a package. My code is stored in foo.R. This code has two functions FUN1 and FUN2. FUN1 calls FUN2. FUN1 is listed in export() under the package NAMESPACE but NOT FUN2. After building the package when I call FUN1 is giving me an error that cannot find FUN2. I solved this by adding FUN2 in the export() NAMESPACE. However, what is puzzling me is that I have other examples
2006 Aug 16
1
Problem with the special argument '...' within a function
I'm not sure if this is what you want, but simply add ... to the list of arguments for fun1 and fun2 would eliminate the error. Andy From: Hans-Joerg Bibiko > > Dear all, > > I wrote some functions using the special argument '...'. OK, it works. > > But if I call such a function which also called such a > function, then I get an error message about unused
2009 Jun 16
1
ifelse(is.na), with function inside
Hi, I have a vector a=c(NA, 3, 4, 4, NA, NA, 3) and I would like to use is.na(a) function to get a vector like this: wy=(1,2,2,2,1,1,2) - you know, this vector create 1 or 2 depends on value in vector "a" This is my short code but something is wrong and I don't know what... for (i in 1:7){ a=c( NA, 3, 4, 4, NA, NA, 3) fun1=function(x){ x=1 print(x) } fun2=function(x){
2008 Nov 11
1
Retrieving x argument name from a trellis object in R 2.8.0
Dear all, let consider the following function: Fun1 <- function() { library(lattice) plot1 <- 1:10~1:10 pl1 <- xyplot(plot1) return(pl1$call$x) } In R 2.5.0 (or older version) we have > Fun1() plot1 but starting from R 2.5.1 until the latest R 2.8.0 we obtain instead > Fun1() NULL because pl1$call seems to be equal to xyplot() without arguments. Something like
2010 Aug 11
2
storing the results of an apply call
Hi R-users, I have a function (myfun) that I want to apply to the rows of a matrix. Basically, "myfun" takes the values from the matrix ("exp.des"), which represent the different combinations of my experimental design, and pass them as arguments to some other functions (fun1 and fun2). As I want to replicate the results of fun1 and fun2 a certain number of time (e.g. 5), I
2015 Feb 26
1
iterated lapply
> On Feb 25, 2015, at 5:35 PM, Benjamin Tyner <btyner at gmail.com> wrote: > > Actually, it depends on the number of cores: Under current semantics, yes. Each 'stream' of function calls is lazily capturing the last value of `i` on that core. Under Luke's proposed semantics (IIUC), the result would be the same (2,4,6,8) for both parallel and serial execution. This is
2006 Jan 06
1
Problem with Integral of Indicator Function
Hi.. i was trying to integrate the indicator funtion but had problems when limits where negative or equal to the indicator condition my function is ________________________ fun1<-function(x){ as.numeric(x>=2) } _________________________ which should be Ind(x>=2)*x seems to work for the following two cases