Displaying 10 results from an estimated 10 matches similar to: "bug with rpois (PR#9106)"
2013 Apr 23
2
Tables package - remove NAs and NaN
Dear Rxperts,
q <- data.frame(p=rep(c("A","B"),each=10,len=30),
a=rep(c(1,2,3),each=10),id=seq(30),
b=round(runif(30,10,20)),
c=round(runif(30,40,70)))
The operation below...
tabular(((p=factor(p))*(a=factor(a))+1) ~ (N = 1) + (b + c)*
(mean+sd),data=q)
yields some rows of NAs and NaN as shown below
b c
p a N mean sd mean sd
A 1 10
2005 Aug 30
1
loglinear model selection
Hi R-masters!
I have a problem and need your help.
I have 9 discrete variables with 2 levels each.
In exploratory analisys I generate one matrix with chi-square for tables
with 2 ariables each with this script
setwd("F:/")
dados<-read.csv("log.csv")[,2:10]
dados.x<-matrix(NA,ncol=9,nrow=9)
for(i in 1:8){
for(j in (i+1):9){
tab<-table(dados[,i],dados[,j])
2002 Aug 02
1
Means of Monte Carlo simulated lists
Hello,
I am doing simulations, and I generate a list at each iteration (with
three component matrices in the example below), saving the results in
a list. For example, after two iterations, I have something like
> str(sim.theta)
List of 2
$ :List of 3
..$ : num [1:6, 1:4] -3.67 -1.07 -2.99 -18.38 -3.26 ...
..$ : num [1:6, 1:6] -7.56 -3.14 -4.99 1.03 2.79 ...
..$ : num [1:6, 1:4]
2017 May 10
1
regression? no more separate xscreens
Dear Devs,
The support for multiple xscreens (i.e. no xinerama, just separate :0.0
and :0.1 displays) in nouveau is broken.
It would be great if someone could confirm this. It is easily done, by
commenting the "xinerama" option from the xorg.conf file:
https://nouveau.freedesktop.org/wiki/MultiMonitorDesktop/
With the nvidia proprietary drivers separate xscreens work fine. Could
2012 Jun 13
2
asign variables in a "for" loop
Dear R-helpers,
I'm stuck with a little problem that surely has an easy solution but I
can't think of a way to solve it. I'd really appreciate any help you can
offer me!
I'll provide a small example. Given a dataframe data.txt that looks like
this:
ID freq Var Var_mean Ratio_mean Var_median
Ratio_median Var_sum Ratio_min Var_max Ratio_max Var_min
2009 May 15
1
help on Nan error
Hi guys
My data is Tasmania txt
There are *N *= 16 samples, consisting of 8 replicate cores (taken from
different areas across the sandflat) from each of 2 natural
'treatments' (either
disturbed "D" or undisturbed "U" by soldier crab burrowing activity. The
abundances of each of *p *= 56 species were recorded from each core
(variables 1 to 39 in the file are
2017 Oct 13
2
How to define proper breaks in RFM analysis
Hey,
i want to define 3 ideal breaks (bin) for each variable one of those
variables is attached in the previous email,
i don't want to consider quartile method because quartile is not working
ideally for that data set because data distribution is non normal.
so i want you to suggest another method so that i can define 3 breaks with
the ideal interval for Recency, frequency and monetary to
2017 Oct 13
0
How to define proper breaks in RFM analysis
Hi
Your statement about attaching data is problematic. We cannot do much with it. Instead use output from dput(yourdata) to show us what exactly your data look like.
We also do not know how do you want to split your data. It would be nice if you can show also what should be the bins with respective data. Unless you provide this information you probably would not get any sensible answer.
Cheers
2017 Oct 13
0
How to define proper breaks in RFM analysis
Hi
You expect us to solve your problem but you ignore advice already recieved.
Your data are unreadable, use dput(yourdata) instead. see ?dput
> test<-read.table("clipboard", heade=T)
Error in scan(file = file, what = what, sep = sep, quote = quote, dec = dec, :
line 115 did not have 6 elements
What is ?ideal interval? can you define it? Should it be such to provide eqal
2017 Oct 12
3
How to define proper breaks in RFM analysis
Hello,
I'm working on RFM analysis and i wanted to define my own breaks but my
frequency distribution is not normally distributed so when I'm using
quartile its not giving the optimal results.
so I'm looking for a better approach where i can define breaks dynamically
because after visualization i can do it easily but i want to apply this
model so that it can automatically define the