similar to: Wishlist: 'append' argument for write.ftable()

Displaying 20 results from an estimated 8000 matches similar to: "Wishlist: 'append' argument for write.ftable()"

2003 Mar 06
0
modifying ftable to allow percentages (wishlist) (PR#2606)
Full_Name: John Hendrickx Version: 1.6.2 OS: Windows XP Submission from: (NULL) (80.126.78.108) (This is not a bug report but a request to add a feature to future versions of R. Hope this is an appropriate place). I'd like to suggest adding an option to ftable to allow percentages. It would be easy to do and backwards compatible. Percentage tables are useful in educational contexts, whereas
2006 Jul 15
1
Some problems with latex(ftable)
The ftable structure is not an ordinary matrix. Instead, it has the body of the table with several cbind- and rbind-ed rows and columns of label information. The example in ?ftable has two row factors and two column factors. Continuing with the example in ?ftable, enter tmp <- ftable(mtcars$cyl, mtcars$vs, mtcars$am, mtcars$gear, row.vars = c(2, 4), dnn =
2008 Jul 02
1
exporting ftable
How can I export an ftable object in the same format that appears in R command window? For testing that i was using this example that is in help of this function. ## Start with a contingency table. ftable(Titanic, row.vars = 1:3) ftable(Titanic, row.vars = 1:2, col.vars = "Survived") ftable(Titanic, row.vars = 2:1, col.vars = "Survived") ## Start with a data frame. x <-
2012 Dec 17
2
Suggestion: 'method' slot for format.ftable()
Dear R-developers, I would like to suggest a 'method' slot for format.ftable() (see an adjusted 'format.ftable()' below, taken from the source of R-2.15.2). At the moment, format.ftable() contains several empty cells due to the way the row and column labels are printed. This creates problems (= unwanted empty columns/rows) when converting an ftable to a LaTeX table; see an
2011 May 27
1
How to convert an ftable object to a matrix including the row names?
Dear expeRts, What's the easiest way to convert an ftable object to a matrix such that the row names of the ftable object are shown in the first couple of columns of the matrix? This is (typically) required, for example, when the final goal is to print the matrix via xtable. Below is a rather complicated example of how to do it... Cheers, Marius ## Goal: convert an ftable() to a
2012 Jan 26
1
ftable.formula
I apologize in advance if this is the wrong forum for this report/request, and for the fact that I have not read the code for ftable.formula in any detail. >From reading the documentation for ftable.formula, I expected that the following two calls to ftable would produce the same results: data(UCBAdmissions) ftable(UCBAdmissions, row.vars = "Dept", col.vars = c("Gender",
2011 Jun 24
1
Converting an ftable (contingency table) to a dataframe in R
I am generating an ftable (by running ftable on the results of a xtabs command) and I am getting the following. ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?Var1? Var2 date ? ? ? ? ? ? ? ? group? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 2007-01-01? ? ? ? ? q1 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?1? ? 9 ? ? ? ? ? ? ? ? ? ? ?q2 ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?
2008 Mar 12
1
ftable and xtabs
Hoping someone can help me with xtabs and ftable. I'm trying to get a pair of ftables (possibly more) next to each other. For example: > dunhill_lights_xtab<-ftable(xtabs(grossedupobs ~ gender+age_group + dunhill_lights, data = ciggs)) > dunhill_lights_xtab dunhill_lights No Yes gender age_group Female
2007 Jun 23
2
latex of ftable (Hmisc?)
Dear latexRs, I tried to make a latex printout of a simple categorial ftable. It should look like the output of print.ftable. Any ideas how to get the syntax of summary.formula right. Or some alternative? As far I see, xtable does not have method for ftable. Dieter library(Hmisc) n=500 sex <- factor(sample(c("m","f"), n, rep=TRUE)) treatment <-
2004 Feb 04
3
Scoping bug in ftable() (PR#6541)
This bug shows up in ftable() in both r-patched and r-devel: > x <- c(1,2) > y <- c(1,2) > z <- c(1,1) > ftable(z,y) y 1 2 z 1 1 1 > ftable(z,x) x 1 z 1 2 Since x and y are identical, the two ftable results should be the same, but they are not. I've only been able to see this when the column variable is named "x", so it looks like a
2001 Sep 05
3
Bug in ftable?? (Was: Two-way tables of data, etc)
Further to the discussion between Murray Jorgensen and Brian Ripley, it seems to me better to choose tabulations that will not come and bite you. Suppose your data are sligtly irregular, e.g. (for the sake of the argument): data( warpbreaks ) warpbreaks$variant <- rep( 1:5, len=54 ) attach( warpbreaks ) tb <- table( wool, tension, variant ) tb # in this case you would like to see: tp
2001 Sep 05
3
Bug in ftable?? (Was: Two-way tables of data, etc)
Further to the discussion between Murray Jorgensen and Brian Ripley, it seems to me better to choose tabulations that will not come and bite you. Suppose your data are sligtly irregular, e.g. (for the sake of the argument): data( warpbreaks ) warpbreaks$variant <- rep( 1:5, len=54 ) attach( warpbreaks ) tb <- table( wool, tension, variant ) tb # in this case you would like to see: tp
2007 Nov 26
2
ftable as latex (with Hmisc?)
Dear List, possibly called Frank, I tried to create an ftable lookalike of the following data set in LaTeX/Sweave with summary(formula,..), but I could not get it to work for count tables; numeric tables work fine. summary(formula,...,fun="table") does not give the full cross breakdown. Other suggestions welcome. Note that in the output there should be empty fields on repeated
2010 Jun 22
2
constructing a data frame from ftable
Dear R People: I have the following data set with the columns DATE, GENDER, and Co. Co has 8 possible options. > a.df[1:10,] DATE GENDER Co 1 2009-04-16 F Rash 2 2009-04-16 F Other 3 2009-04-16 M Botulinic 4 2009-04-16 M Other 5 2009-04-16 M Constitutional 6 2009-04-16 F Other 7 2009-04-16
2008 Nov 24
1
weighted ftable
I need to do some fairly deep tables, and ftable() offers most of what I need, except for the weighting. With smaller samples, I've just used replicate to let me have a weighted data set, but with this data set, I'm afraid replicate is going to make my data set too big for R to handle comfortably. That being said, is there some way to weight my table (similar to wtd.table) but offer the
2017 Jul 09
2
Help with ftable.svyby
Hi all, When I try the following with pkg Survey it returns the error below: ftable(svyby(~INCOME, ~AGECL+RACECL, svymean, design=q50), rownames=list(AGECL=c("<35", "35-44", "45-54", "55-64", "65-74", ">=75"), RACECL=c("white non hispanic", "non white or
2010 Jun 08
2
constructing a contingency table (ftable, table)
Dear all, an hopefully quick table question. I have the following data: Two objects that are 2*9 matrix with nine column names (Dis1, ..., Dis9) and the row names (2010,2020). The content are frequencies (numeric). In want to create a table that is along the lines of ftable(UCBAdmissions) and should looks like this: Dis1 | ...| Dis9 2010|2020|....|2010|2020 (first row,first column is the value
2017 Jul 09
0
Help with ftable.svyby
try resetting your factor levels and re-run? q50 <- update( q50 , INCOME = factor( INCOME ) , AGECL = factor( AGECL ) , RACECL = factor( RACECL ) ) On Sun, Jul 9, 2017 at 2:59 PM, Orsola Costantini via R-help < r-help at r-project.org> wrote: > Hi all, > > When I try the following with pkg Survey it returns the error below: > > ftable(svyby(~INCOME, ~AGECL+RACECL,
2020 May 13
7
justify hard coded in format.ftable
Dear all, I haven't received any feedback so far on my proposal to make "justify" argument available in stats:::format.ftable Is this list the appropriate place for this kind of proposal? I hope this follow-up to my message won't be taken as rude. Of course it's not meant to be, but I'm not used to the R mailing lists... Thank you in advance for your comments, Best,
2005 Aug 30
1
Convert ftable to latex?
Dear list, I cannot make the latex command to output a ftable objet the way I want it. Is it posible? I found a post in the archives saying that one should use the rgroup and n.rgroup arguments to supply the row names, but so far I have been unsuccessful. This is what I have: >