similar to: all.equal() improvements (PR#8191)

--k1lZvvs/B4yU6o8G Content-Type: text/plain; charset=us-ascii Content-Disposition: inline The attached patch against R 2.2.0 makes the following improvements to the all.equal() function: 1. Check names! Stock R all.equal() (unlike S-Plus) ignores names completely on some objects. I consider this wrong - if the names are different, the object is NOT "the same". 2. When a

In R and S, the general idea is that data.frames must have unique row.names (aka dimnames(.)[[1]]). Several observations / problems (in R *and* S !). [Example code at the end] 1) Both in S and R, data.frame(..) (and e.g., also cbind(<data.frame>, ..) which dispatches to data.frame()) silently drops the whole row.names and replaces it by "1" "2" ...

<<insert bug report here>> > apply(array(1:20,c(2,2,5)),2:3,function(x) x) Error: length of dimnames must match that of dims > Changing: dimnames = if (is.null(dn.ans)) list(ans.names, NULL) else c(list(ans.names), dn.ans) To: dimnames = if (length(dn)==0) NULL else if (is.null(dn.ans)) list(ans.names, NULL) else c(list(ans.names), dn.ans) seems to fix this. Chuck

Hi everyone, I have the following problem: I want to perform a LDA with the function lda(). My data object mat.data is a matrix with dimensions > dim(mat.data) [1] 1228 44 and my grouping vector grp has length 1228: > length(grp) [1] 1228 Every time I call lda(), the following error message occurs: > lda(mat.data,grp) Error in lda.default(x, grouping, ...) : length of dimnames [2]

Hi, I think ExecutionEngine as a common interface for both Interpreter and MCJIT is almost useless in the current form. There are separated methods in ExecutionEngine for similar or the same features provided by Interpreter and MCJIT, i.e. to get a pointer to function you should call getPointerToFunction() for Interpreter or getFunctionAddress() for MCJIT. Personally, I'm using MCJIT and

This question appears to have been asked previously, but not answered. the last response I can find to this previous thread is here: http://tolstoy.newcastle.edu.au/R/help/04/07/0126.html. The asnwer was to provide debugging info, not an answer. So the problem is that I'm trying to use lda on my dataset. You can download my data here: http://northstar-www.dartmouth.edu/~jgilbert/nolda, I used

Here's a nasty one. The following has caused a segmentation fault and possibly also a bus error. fred <- 1:6 dim(fred) <- 6 dimnames(fred) <- list(LETTERS[1:6]) mm <- matrix(1:12, 2, 6) mm %*% fred # segmentation fault here In the case without the dimnames assignment the result is OK. Cheers, Jonathan. --please do not edit the information below-- Version: platform =

Created a new data set with 3 numeric variable to find correlation CR1<- mar%>% as_data_frame%>% select(AGE, OLD_CAR_PURCHASE_YRS, Total.Spend.With.AA) had to convert it to a data frame, code: as.matrix(as.data.frame(CR1)) Now i need to run a correlation plot for these 3 variables: corrplot(CR1, method = "circle") But i am getting this error: Error in

I'm assuming you are using the corrplot package. If so, your data object does need to be a matrix, not a data frame. Since it's already a data frame, your line of code: as.matrix(as.data.frame(CR1)) doesn't need the as.data.frame function, but more importantly, you didn't assign the result to anything: as.matrix() does not work in place. CR1 <- as.matrix(CR1) Now try. If

There's a non-compatibility between R and S-plus with the default argument of the locator() function. R has locator(n=1) S-plus has locator(n=500, type="n", noclick=F) S's default is ``better'' I think, insofar as it means in 99% of the cases ``user clicks <left> as many times as wanted and then clicks <right> to end'' Ross Ihaka and his grad

Hi Sarah, Thank you for your help. I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1, method = "circle") : The matrix is not in [-1, 1]!. I am using a corrplot library. Please find the reproducible example: dput(head(CR1,10)) structure(c(26L, 46L, 39L, 38L, 47L, 59L, 56L, 61L, 43L, 60L, 78L, 63L, 2L, 58L, 8L, 1L, 1L, 9L, 11L, 2L, 1037500L, 46747L, 346300L,

On Thu, 18-May-2017 at 05:46PM +0200, Martin Maechler wrote: |> ..... |> |> Being pretty "stretched" time wise currently, I'm happy for |> timezone-portable propositions to change the test. Meantime, anyone who lives where DST happpens in December who wants to get through the remaining tests can avoid this one by changing the line > stopifnot(length(fd) == 10,

Hello, all, I'm a new R user (new to any programming language in general, really), so I apologize if this is easy/has already been answered (I've attempted searching online but did not understand the pages I found). My data is stored in text files with the headers LANE, RNA_NAME, SEQ, and SEQCNT. I've been using x = "filename.txt" y = aggregate(x$SEQCNT, list(x$RNA_NAME),

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at

Last week, we've talked here about "xtabs(), factors and NAs", -> https://stat.ethz.ch/pipermail/r-devel/2017-January/073621.html In the mean time, I've spent several hours on the issue and also committed changes to R-devel "in two iterations". In the case there is a *Left* hand side part to xtabs() formula, see the help page example using 'esoph', it

>>>>> Martin Maechler >>>>> on Wed, 19 Feb 2020 18:06:57 +0100 writes: >>>>> Serguei Sokol >>>>> on Wed, 19 Feb 2020 15:21:21 +0100 writes: >> Hi, >> I was bitten by a little incoherence in dimnames assignment or may be I >> missed some point. >> Here is the case. If I assign row names

Due to a few problems I encountered I had a tiny look at the samba code and gut a few questions, statements and propositions. Please by all means, correct me if I got something wrong. 1. besides filestore for shares and config files samba uses ldb as an exclusive storage backend 1. LDB supports TDB, LDAP and SQLITE3 backend 2. Samba hard codes to TDB files like

I have two matrices, generated by R functions that I don't understand. I want to confirm that they're the same, but I know that they have different attributes. If I want to compare the dimnames, I can say > identical(attr(tm, "dimnames"), attr(tmm, "dimnames")) [1] FALSE or even: > identical(dimnames(tm), dimnames(tmm)) [1] FALSE But I can't find any

The "no factor combination" case is distinguishable by 'tapply' with simplify=FALSE. > D2 <- data.frame(n = gl(3,4), L = gl(6,2, labels=LETTERS[1:6]), N=3) > D2 <- D2[-c(1,5), ] > DN <- D2; DN[1,"N"] <- NA > with(DN, tapply(N, list(n,L), FUN=sum, simplify=FALSE)) A B C D E F 1 NA 6 NULL NULL NULL NULL 2 NULL NULL 3 6

On a related note, the storage mode should try to match ans[[1]] (or unlist:ed and) when allocating 'ansmat' to avoid coercion and hence a full copy. Henrik On Jan 26, 2017 07:50, "William Dunlap via R-devel" <r-devel at r-project.org> wrote: It would be cool if the default for tapply's init.value could be FUN(X[0]), so it would be 0 for FUN=sum or FUN=length, TRUE