similar to: Yates' correction for continuity in chisq.test (PR#8265)

Full_Name: nobody Version: 2.2.0 OS: any Submission from: (NULL) (219.66.34.183) 2 x 2 table, such as > x [,1] [,2] [1,] 10 12 [2,] 11 13 > chisq.test(x) Pearson's Chi-squared test with Yates' continuity correction data: x X-squared = 0.0732, df = 1, p-value = 0.7868 but, X-squared = 0.0732 is over corrected. when abs(a*d-b*c) <= sum(a,b,c,d), chisq.value

Dear all: I need to perform a Yates analysis of a 2-level full factorial experiment design. My question is: how i can do it with R, or best, what's the package who i need to use for this purpose. Thanks. ,__ __ /\ /| | | | | __ ,_ __, _ | | | | | / \_/ | / | |/ | | | \_|/\__/ |_/\_/|/|__/ |

I can't hardly accept the result of cor function with pairwize.colplete.obs or complete.obs insert print statements in cor function, + if (method != "pearson") { + Rank <- function(u) if (is.matrix(u)) + apply(u, 2, rank, na.last = "keep") + else rank(u, na.last = "keep") + x <- Rank(x) +

Hi, I have a text mining project and currently I am working on feature generation/selection part. My plan is selecting a set of words or word combinations which have better discriminant capability than other words in telling the group id's (2 classes in this case) for a dataset which has 2,000,000 documents. One approach is using "contrast-set association rule mining" while the

Hello, I was using the mantelhaen.test function (2x2 J tables for conditional independence testing). I noticed that the option for the continuity correction (correction=T or correction=F) sometimes made a difference while sometimes it did give the same results regardless of correction=T or correction=F. Does the continuity correction apply only in certain cases or in certain strata with some

The cells are interpreted as counts, so by scaling you're analyzing a different experiment (one with fewer observations). So the chi-squared value will change (the terms (O-E)^2/E in the statistic scale linearly ignoring rounding and "Yates' continuity correction"). The chisq.test on the original data is a test of association. Conventionally you decide ahead of time on a

I don't quite understand the difference between the two methods for performing a chi-squared test on contingency tables: summary(table()) and chisq.test() They may different results. E.g.: aa <- gl(2, 10) bb <- as.factor(c(1,2,2,2,1,2,1,2,2,2,1,2,2,2,1,1,1,2,1,1)) aa <- c(aa, aa) bb <- c(bb, bb) table(aa, bb) summary(table(aa, bb)) chisq.test(aa, bb) Could somebody give me

Hello all, Let say I have 2-way contingency table: Tab <- matrix(c(8, 10, 12, 6), nr = 2) and the Chi-squared test could not reject the independence: > chisq.test(Tab) Pearson's Chi-squared test with Yates' continuity correction data: Tab X-squared = 1.0125, df = 1, p-value = 0.3143 However I want to get all possible contingency tables under this independence

Hello I have the matrix a<-matrix(c(2,1,0,1,2,2,1,5,7,2,5,12),nrow=6) a [,1] [,2] [1,] 2 1 [2,] 1 5 [3,] 0 7 [4,] 1 2 [5,] 2 5 [6,] 2 12 Suppose that in the first row we have 3 men of England, 2 with hair, and 1 no In the second we have 6 italian men, 1 with hair and 5 no ... I want to find if there is a dependence between men withouth hair and

R 2.12 windows 7 I am summary data that I would like to make into a 2x2 table representing counts positive vs. negative counts: 28/289 20/276 My table should look something like the following: group1 group2 Positive 28 20 Negative 289 276 How can a (1) create the 2x2 table (2) run a chi square test on the table? I have tried the following code, but I

Colleagues, I have created a list in the following manner: TEST <- list(c("A1", "A2"), c("B1", "B2"), c("C1", "C2")) I now want to delete one element from the list, e.g., the third. The command TEST[[3]] yields (as expected): [1] "C1" "C2" The command TEST[[-3]] yields: Error:

I've run into a problem with dir.create on R2.2.0 Windows XP 2002 SP 2. setwd("d:/") print(dir.create("d:\\otis-sim\\rdata", recursive=T)) print(dir.create("d:\\otis-sim\\", recursive=T)) Both return false and fail to create the directories. setwd("c:/") print(dir.create("d:\\otis-sim\\rdata", recursive=T)) Returns true and succesfully

TOPIC My question regards the philosophy behind how R implements corrections to chi-square statistical tests. At least in recent versions (I'm using 2.13.1 (2011-07-08) on OSX 10.6.8.), the chisq.test function applies the Yates continuity correction for 2 by 2 contingency tables. But when used as a goodness of fit test (GoF, aka likelihood ratio test), chisq.test does not appear to implement

Yesterday, I installed R2.2.0 for Windows [Version 2.2.0 (2005-10-06 r35749)]. Unfortunately, 'install.packages("Matrix")' produced the following message: Warning in download.packages(pkgs, destdir = tmpd, available = available, : no package 'Matrix' at the repositories I installed lme4, maps, mapproj, CircStats, scatterplot3d, gregmisc, Hmisc without

Can anyone tell me how to calculate a mid-p value for a chi-squared test in R? Many thanks, Andrew Wilson

Jean-Marc Valin <jean-marc.valin at usherbrooke.ca> writes: > Quality and bit-rate are different ways of specifying exactly the same > thing. Complexity is orthogonal. That clears it up - thanks. Is this in the manual? --Randy > > Jean-Marc > > On 2010-04-03 08:28, Randy Yates wrote: >> Jean-Marc: I know you're seeing these - how about a response? >>

Jean-Marc: I know you're seeing these - how about a response? --Randy Randy Yates <yates at ieee.org> writes: > If I understand these terms correctly, you cannot specify simultaneously > all three, e.g., high quality, low bitrate, and low complexity. > > It seems that specifying any two implies the third. For example, > specifying a high quality and low bitrate will

Randy Yates <yates at ieee.org> writes: > The speexenc.c example has a "--bitrate n" command line option, but I > can't find in the Speex Codec manual where the default bitrate is > defined. > > What is the default bitrate for 16 kHz mono? Also here are a few other bitrate-related questions: 1. Does average bitrate mode ==> variable bitrate mode? 2.

Saju Palayur <saju_pa at hotmail.com> writes: > Hi > > > > We have ported the Narrow band 8 Khz Speex encoder and decoder on to TI DSP 5505 > > > > To compress 20ms of 16 bit audio sampled at 8Khz it takes 4.2ms. > > Is there any optimizations I can do to make it run faster. The first thing to do would be to profile the code (I assume you're using

Saju Palayur <saju_pa at hotmail.com> writes: > Hi > > > > When we run the profiler these 3 functions take more than 8500 cycles. > > > > split_cb_search_shape_sign_N1() 22782 > pitch_search_3tap() 19208 > lpc_to_lsp() 16007 > > So can I configure these in a different way so it takes less cycles. I am not familiar with the code, so I can't