similar to: R CMD check and interfacing packages

I was running R CMD check on Windows XP 2.0.1beta and got this: Error in parse(file, n, text, prompt) : syntax error on 602 After a lot of aggravation I finally discovered that if I did this: copy *.R allofthem.R and checked line 602 in allofthem.R that I could find the error. I noticed that there are repeated references in the help archives to this sort of error and how hard it is to locate

Dear Gabor, Thank your for helping me so much! I have loaded R the newest version 2.1.1. Then I setup it in the path of D:\program files\R\ 1. unpack tools.zip into c:\cygwin 2. install Active perl in c:\Perl 3. install the mingw32 in c:\mingwin 4. add "c:\cygwin; c:\mingwin\bin" in "Control Panel -> System -> Advanced -> Environment Variables -> Path ->

Dear All, The following code should return 1, but it returns 0: source("http://r-bc.googlecode.com/svn/trunk/R/bc.R") bc("9 % 2") Do you confirm this bug? Paul

I can't get the PERL subexpression translated to R. Following, for example, B. Ripley's http://finzi.psych.upenn.edu/R/Rhelp02a/archive/58984.html I am using sub, but it looks like an ugly substitute. Assume I want to extract the first alpha part and the first numeric part, but only if they are in sequence. Do I really have to use the sub twice, first extracting the first variable, then

Hi I'm using R 2.0 in SuSE 9.2. When I plot data as a boxplot, the boxes appear on the plot in alphabetical order (of group) rather than the order in which they appear in the data. So far, the only thing I can do to fix this is to prefix the group labels with a,b,c...etc to trick R into plotting them in the right order. Can sorting be turned off? How should I address this sensibly? Thanks

Consider the following example: # substitute a with b in the indicated function. Seems to work. > z <- substitute( function()a+1, list(a=quote(b)) ) > z function() b + 1 # z is an object of class call so use eval # to turn it into an object of class expression; however, # when z is evaluated, the variable a returns. > eval(z) function()a+1 Why did a suddenly reappear again

I have two vectors, a and b. b is a text file. I want to find in b those elements of a which occur at the beginning of the line in b. I have the following code, but it only returns a value for the first value in a, but I want both. Any ideas please. a = c(2,3) b = NULL b[1] = "aaa 2 aaa" b[2] = "2 aaa" b[3] = "3 aaa" b[4] = "aaa 3 aaa"

--- Prof Brian D Ripley <ripley@stats.ox.ac.uk> wrote: >A matrix list? R lists are just vectors with elements of different types, >and R matrices are just vectors with a dimension attribute. When I saw the above I tried to create a matrix from a list but could not get it to work: my.lm <- lm( rnorm(10) ~ I(1:10) ) my.list <- list(1, 2, 3, 4, 5, 6, my.lm, my.lm, my.lm)

Hi all, please see my code: > library(zoo) > a <- as.yearmon("March-2010", "%B-%Y") > b <- as.yearmon("May-2010", "%B-%Y") > > nn <- (b-a)*12 # number of months in between them > nn [1] 2 > as.integer(nn) [1] 1 What is the correct way to find the number of months between "a" and "b", still

Dear R-helpers, I am a beginner using R. This is the first question in this list. My question, Is there possible to make combinations with two part column? If I have a number 1,2,3,4,5,6,7,8. I need the result something like below: 1,2,3,4,5 6,7,8 1,2,3,4,7 5,6,8 2,3,4,5,6 1,7,8 1,2,3,6,7 4,5,8 1,2,3,4,8 5,6,7 3,4,6,7,8 1,2,5 .... I would be very happy if anyone could

Also why should that difference result in different behavior? On Tue, Nov 14, 2023 at 9:38?AM Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > > In that case identical should be FALSE but it is TRUE > > identical(a1, a2) > ## [1] TRUE > > > On Tue, Nov 14, 2023 at 8:58?AM Deepayan Sarkar > <deepayan.sarkar at gmail.com> wrote: > > > >

All: How do I obtain one step ahead out-of-sample forecasts from a model using "dyn" or "dynlm" ? Thanks! Best, John [[alternative HTML version deleted]]

What is wrong with you guys? I asked for a zip, like R Studio has for example. Totally clear. I cant execute exes. But I can unzip files. Thanks Gabor, I had that in mind, but can't execute the exe due to security restrictions. Geez, really, treating people who ask questions this way just makes you don't want to ask a single one. On Thu, Jan 25, 2018, 11:19 Gabor Grothendieck

Pretty good question Gabor. I can execute R once it is installed (if someone with rights installs it before) but not the installer. I can download the installer (with some pain). I know that some installers are actually compressed files in disguise, but I think this is not the case with R, right? I will study the exact nature of the restriction, and get back to you. Nevertheless, having a

On Tue, 14 Nov 2023 at 09:41, Gabor Grothendieck <ggrothendieck at gmail.com> wrote: > > Also why should that difference result in different behavior? That's justifiable, I think; consider: > d1 = data.frame(a = 1:4) > d2 = d3 = data.frame(b = 1:2) > row.names(d3) = c("a", "b") > data.frame(d1, d2) a b 1 1 1 2 2 2 3 3 1 4 4 2 > data.frame(d1,

Hi, Before I reinvent the wheel I wanted to kindly ask you for your opinion if there is a simple way to do it. I want to merge a larger number of tables from different data sources in R and the matching criterium are country names. The tables are of different size and sometimes the country names do differ slightly. Has anyone done this or any recommendation on what commands I

Hi all, Could anybody please recommend some hands-on books on classification, data-mining and machine learning with R? I would like to get a very good understanding of the statistical tools that are used in these areas, while reducing the learning curve. Thank you!

One can perform a for loop without indices over the columns of a dataframe like this: for( v in df ) ... some statements involving v ... Is there some way to do this for rows other than using indices: for( i in 1:nrow(df) ) ... some statements involving df[i,] ... If the dataframe had only numeric entries I could transpose it and then do it over columns but what about the general case?

On Thu, 18 Nov 2004 00:38:47 +0000 (UTC), Gabor Grothendieck <ggrothendieck@myway.com> wrote : >DIFFERENCE BETWEEN USING .RBUILDIGNORE AND NOT > >The reason that the processing is different according to whether one >uses .Rbuildignore or not is that > R CMD build >takes the .Rbuildignore file into account but > R CMD install > R CMD check > R CMD build

Hi all, I am using the zoo package to plot time series. I have a problem with formatting the axes. my zoo object (z) looks like the following. c1 1992-01-10 21 1992-01-17 34 1992-01-24 33 1992-01-31 41 1992-02-07 39 1992-02-14 38 1992-02-21 37 1992-02-28 28 1992-03-06 33 1992-03-13 40