similar to: segmentation fault: formula() with long variable names (PR#3680)

Displaying 20 results from an estimated 1000 matches similar to: "segmentation fault: formula() with long variable names (PR#3680)"

2003 Aug 08
1
covmat argument in princomp() (PR#3682)
R version: 1.7.1 OS: Red Hat Linux 7.2 When "covmat" is supplied in princomp(), the output value "center" is all NA's, even though the input matrix was indeed centered. I haven't read anything about this in the help file for princomp(). See code below for an example: pc2$center is all NA's. Jerome Asselin x <- rnorm(6) y <- rnorm(6) X <- cbind(x,y)
2003 May 07
0
frailty models in survreg() -- survival package (PR#2933)
I am confused on how the log-likelihood is calculated in a parametric survival problem with frailty. I see a contradiction in the frailty() help file vs. the source code of frailty.gamma(), frailty.gaussian() and frailty.t(). The function frailty.gaussian() appears to calculate the penalty as the negative log-density of independent Gaussian variables, as one would expect: >
2003 Jul 04
0
degrees of freedom in nlme() (PR#2384)
I would like to document my findings (with a potential FIX) regarding the issue of calculation of the degrees of freedom with nlme(). The program given at the bottom of this email generates and fit 20 data sets with a mixed-effects LINEAR model, but using the function nlme() instead of lme(). In each case, the correct number of degrees of freedom for the intercept parameter is 12. However, in
2003 Aug 30
3
fisher.test() gives wrong confidence interval (PR#4019)
The problem occurs when the sample odds ratio is Inf, such as in the following example. Given the fact that both upper bounds of the two 95% confidence intervals are Inf, I would have expected that the two lower bounds be equal, but they aren't. x <- matrix(c(9,4,0,2),2,2) x # [,1] [,2] #[1,] 9 0 #[2,] 4 2 rbind("two.sided.95CI"=fisher.test(x)$conf.int,
2003 May 20
1
legend() with option adj=1
Hi there, I want to justify to right the text of my legend. Consider this short reproducable example. x <- 1:5 y1 <- 1/x y2 <- 2/x plot(rep(x,2),c(y1,y2),type="n",xlab="x",ylab="y") lines(x,y1) lines(x,y2,lty=2) legend(5,2,c("1,000","1,000,000"),lty=1:2,xjust=1,yjust=1)
2003 Feb 27
2
interval-censored data in survreg()
I am trying to fit a lognormal distribution on interval-censored data. Some of my intervals have a lower bound of zero. Unfortunately, it seems like survreg() cannot deal with lower bounds of zero, despite the fact that plnorm(0)==0 and pnorm(-Inf)==0 are well defined. Below is a short example to reproduce the problem. Does anyone know why survreg() must behave that way? Is there an alternate
2003 May 21
1
axis() default values for "lty", "lwd", and "col"
Hi, I would like to recommend a minor modification in axis() which I believe can simplify the making of plots for publications. I am trying to define default values for par() in order to make labels bigger and lines thicker, so that the resulting plots look good when resized for publication purposes. I ran into the following problem... axis() does not use par() values as default for
2003 Aug 07
2
model.frame() call from inside a function (PR#3671)
R version: 1.7.1 OS: Red Hat Linux 7.2 Hi all, The formula object in model.frame() is not retrieved properly when model.frame() is called from within a function and the "subset" argument is supplied. foo <- function(formula,data,subset=NULL) { cat("\n*****Does formula[-3] == ~y ?**** TRUE *****\n") print(formula[-3] == ~y) cat("\n*****Result of model.frame()
2003 Feb 24
2
"trace" argument in legend() (PR#2578)
Full_Name: Jerome Asselin Version: 1.6.2 OS: RedHat Linux 7.2 Submission from: (NULL) (142.103.173.179) Should be an easy fix... Consider the examble below: plot(0,0) legend(0,0,c("Hello!","Hi!"),pch=1:2,lty=1:2,trace=T) It gives the following trace: > plot(0,0) > legend(0,0,c("Hello!","Hi!"),pch=1:2,lty=1:2,trace=T) xchar= 0.05178 ;
2003 Jun 05
2
Fwd: Re: legend() with option adj=1
Is there a simpler way then the solution to the one that was posted here? I'm not very proficient with legend, and I don't understand this solution. All I have is two or more lines on one plot that I want to put a legend on and I can't figure out how to do it from the examples. Can you give a very simple example? It does not have to be fancy!! I have never worked with a
2003 Feb 15
2
(no subject)
Hi, Are there some packages which can generate multi-normal, multi-t, etc multivariate sampling? thanks! Best wishes, Peng ******************************* Peng Zhang Department of Biostatistics Harvard School of Public Health 655 Huntington Avenue Boston, Massachusetts 02115 ******************************* I believe I can fly I believe I can touch the sky
2003 Feb 19
1
How to use Cox PH model to select genes from DNA gene expression profiles?
I'm doing prediction of the survival cases using gene expression profiles(Affymetrix chips). Can somebody tell me how to use the Cox PH model to select genes and make a prediction of survival? Thanks. Guangchun
2003 Feb 27
2
epoch time conversion in R
I have a data file where each entry is indexed by the time in seconds since epoch (e.g. 1046315697). Is there an easy way to convert this time value into a more friendly time (such as Month-Year) when plotting it? I searched through the manual, mailing lists, and functions like as.POSIXct and strptime, but didn't find what I need. Thanks, Sharad.
2003 Apr 17
1
bit set or bit test
Hello, does R have functions for setting and testing bit values? I want to conserve memory for storing presence/absence data for large multiple arrays within a single array, using element values like present[x,y] <- ntharray[x,y]*(2^n) where presence is 1, non-presence is 0 and n is the nth array e.g. 1*(2^0) + 0*(2^1) + 0*(2^2) + 1*(2^3) + 0(2^4) for storing the value 9 for presence in
2003 Feb 24
2
fill prob. in legend
Hi, I'm trying to construct a legend which has four lines of text and associated symbols. The first two symbols need to be normal lines which vary only in colour. The second two symbols should have filled boxes. How do I suppress the fill boxes in the first two lines? J.
2003 Jul 15
2
"na.action" parameter in princomp() (PR#3481)
Full_Name: Jerome Asselin Version: 1.7.1 OS: Red Hat Linux 7.2 Submission from: (NULL) (24.77.125.119) Setting the parameter na.action=na.omit should remove incomplete records in princomp. However this does not seem to work as expected. See example below. Sincerely, Jerome Asselin data(USArrests) princomp(USArrests, cor = TRUE) #THIS WORKS USArrests[1,3] <- NA princomp(USArrests, cor =
2003 Oct 24
2
Segmentation fault in .Call() (PR#4761)
Full_Name: Jerome Asselin Version: 1.8.0 OS: RedHat Linux 7.2 Submission from: (NULL) (142.103.177.13) I would not expect a segmentation fault; perhaps an error message. > .Call("log") Segmentation fault This is always reproducable for me. Sincerely, Jerome Asselin
2003 Apr 14
7
functions in a package
Hello, I have a beginner's Q: if i want to know all the functions provided by a package, what is command for that? in another word, Is there a command to list all the commands available in a packege? thanks a lot, yan
2003 May 16
2
Efficient subsetting
Hi, I'm facing this problem quite a lot, so it seems worthwhile to check to see what the most efficient solution is. I've two vectors x (values ordered) and y. I've ranges x < x0, x0 <= x < x1, x1 <= x < x2, x2 <= x < x3, x > xn and want to construct a subvector yprime of y which consists of the first/last value of y whose x values are in the range. For
2002 Nov 22
1
Segmentation fault using "survival" package (PR#2320)
Full_Name: Jerome Asselin Version: 1.6.1 OS: RedHat Linux 7.2 Submission from: (NULL) (142.103.173.179) Hello, I get a segmentation fault when I run the following code. I wouldn't expect meaningful results because my response variable contains only missing values. However, I would expect something like a regular error (not a segmentation fault). library(survival) data <-