similar to: BUG report : 'rnorm' (LINUX, R 1.6.2) (PR#2682)

Hello, i only got a small problem. i try to create automatic new dataframes, or png?s. the main problem i got is: how can i create automatic a new name for a file (read out by simply "for") - i tried to use "(paste...) but theres an errormessage, about a wrong declination. R told it is as.character, but need as.Real. Should i use another method than "paste"? i tried as

Hello Everyone, My name is Prashant and I head the placement division with ANZ Solutions. We work with close to 53 clients all over the country and help them with their staffing requirements. I like to network with strong technical people like you and like to associate myself with respect to your career plans. Please let me know and I will give you a call. We can help you for any kind of

Hello Speex Development Team, We have purchased many T-2000 phones from VAVAA ( Gold Score International Holdings Limited of China) which use the Speex V208 software. Many of these phones are being used by Vision Impaired people some of whom are totally blind. Do you have a version of your software that we could load which produces speech outpiut that communicates to the user each key selected

hello R users, I didn't find a solution for a special problem. I have two dataframes. dataframe1: X value row col ID 1 8.973498062 5512625 3460000 1 2 11.656658570 5501625 3464000 2 3 11.121777570 5495625 3473000 3 4 9.310465964 5508625 3477000 4 5 8.883483845 5515625 3496000 5 dataframe2: X value

Hi all, inside my * is a E400P. The machine is a PII 400Mhz with 256MB Ram. OS is Debian woody. * is the newest cvs co. I have written a little callgen script which make outgoing calls through my *: #! /bin/sh set -e n=$1 # Nummer anz=$2 # Anzhal der Versuche anz2=$3 # Kan?le sle=$4 # Timeout bis zum n?chsten Versuch if [ -z $4 ]; then sle=0 fi s=1

Hi there, I've been using the SMATR package to do standardized major axis (SMA) regression on allometric data, and I've been able to to pairwise comparisons of slope & elevation between multiple study sites. Now I'm trying to do the same thing using major axis (MA) regression, but I'm getting errors (SMATR should be able to do MA as well as SMA regression for everything,

Dear all: I have two larges files with 2000 columns. For each file I am performing a loop to extract the "i"th element of each file and create a data frame with both "i"th elements in order to perform further analysis. I am not extracting all the "i"th elements but only certain which I am indicating on a vector called "d". See an example of my code below

Most likely, yes. They should have a copy of the license agreement, and you can take a look at that and see what they have to say about using them apart from the VirtualIron product. The only open source PV drivers are the ones that James has released - search the list for "GPL PV drivers" and that should turn up some threads related to those. The drivers are still very much in the

Dear R-users, When I tried to import a text file (tab delimited) which has 2000+ rows with the following command (With the importData in S, it works though), x <- read.table(textfile, sep= "\t", skip=5, stringAsFactors=F) I received the following warning message: Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings,: number of items read is not a multiple of

Dear colleague, I not sure this R code is correctly ? I would to show the number of Sample Size at Sample Size Axis that line draw from Power Axis (80%) from R code. How I show this and select the most appropriate of this power (.79955687 - 80983575). Thank for your help and answer. Best Regards, Nikom Thanomsieng, Email: nikom at kku.ac.th .... #Power analysis: Sample size for

Hi, Not too sure what you're looking for, but Speex isn't a screen reader, it's a compression algorithm. Also, there's no with thing as Speex version V208. Cheers, Jean-Marc Byers, Robert wrote: > > Hello Speex Development Team, > > We have purchased many T-2000 phones from VAVAA ( Gold Score > International Holdings Limited of China) which use the Speex

All, I have some data on parasites on apple leaves and want to do a goodness of fit test to a Poisson distribution. This seems to do it: mites <- c(rep(0,70), rep(1,38), rep(2,17), rep(3,10), rep(4,9), rep(5,3), rep(6,2), rep(7,1)) tab <- table(mites) NSU <- length(mites) N <-

This came up on r-help but indicates a bug. dnbinom(x,n,p) calls dbinom_raw(n-1,...) which returns 0 for n<1. -thomas ---------- Forwarded message ---------- Date: Thu, 08 Feb 2001 17:10:23 +0000 From: Yudi Pawitan <yudi@stat.ucc.ie> To: Mark Myatt <mark@myatt.demon.co.uk> Cc: R-Help <r-help@stat.math.ethz.ch> Subject: Re: [R] Goodness of fit to Poisson / NegBinomial

Try changing your method to "ML" and try again. I tried the run the first example from the documentation and it failed with the same error. Changing the estimation method to ML worked. @List: Can anyone else verify the error I got? I literally ran the following two lines interactively from the example for goodfit: dummy <- rnbinom(200, size = 1.5, prob = 0.8) gf <- goodfit(dummy,

Dear R'ers, When I used S-plus i wrote a small program for a Mantel-Haenszel test for trend (I think it worked). Unfortunately I can't get it working in R. It appears as if my use of 'el' is the problem but I can't sort it out. Error in apply(array, c(, 2, 3), function(el) el * 1:s) : argument is missing, with no default Further down in the program I use 'el'

Hello, I need to fit a generalized linear model with a Chi2 (6 ddl) as error distribution and with "log" as link function. I have looked in help(family) and maybe I could use Gamma(link="log") but I do not know if I can, and where I can define the shape and the scale arguments of the gamma distribution. Maybe there is another may to do that? Could someone explain me how can I

Hi! I'm trying to do some ploytomous logistic regression using multinom() in the nnet package, but am a bit confused about interpretation of the results Is it possible to get the following quantities: I: maximum likelihood estimates to test for fit of model and significance of each predictor (I would like to produce a table of the following type) Analysis of Variance: MLE (values are

Dear All, I have just estimated this model: ----------------------------------------------------------- Logistic Regression Model lrm(formula = Y ~ X16, x = T, y = T) Model Likelihood Discrimination Rank Discrim. Ratio Test Indexes Indexes Obs 82 LR chi2 5.58 R2 0.088 C 0.607 0

Hi all, I have done a backward stepwise selection on a full binomial GLM where the response variable is gender. At the end of the selection I have found one model with only one explanatory variable (cohort, factor variable with 10 levels). I want to test the significance of the variable "cohort" that, I believe, is the same as the significance of this selected model: >

Hello, I want to use the quantile function so I read the doc but I don't understand with this > qchisq(seq(0.05,0.95,by=0.05),df=(length(don)-1)) [1] 62667.11 62795.62 62882.42 62951.47 63010.74 63064.00 63113.39 63160.27 63205.65 63250.33 63295.04 63340.48 63387.48 63437.03 63490.53 63550.14 63619.68 [18] 63707.24 63837.16 Can you help me please?