Displaying 20 results from an estimated 4000 matches similar to: "summary.table parameter bug (PR#2514)"
2003 Feb 03
1
summary.table bug in parameter (and fix) (PR#2526)
I sent this in with an old version, but it's in latest version as well. The fix is simple.
In the summary.table function, the parameter is calculated incorrectly
for a test of independence among all cells when the table is more than
2-way table.
Example:
Consider X:
> X
a b c
1 A1 B2 C1
2 A3 BA3 C2
3 A2 B1 C4
4 A1 B2 C3
5 A3 BA3 C2
6 A1 BA3 C1
7 A2 BA3 C2
8 A1
2004 Jan 29
2
Loglienar models
Hello,
I'm planning to start using R. Before getting into it, I'd like to
ask a couple of questions. Does R carry out loglinear model analysis?
That is, will it provide the chi-squared goodness of fit test statistic
for a given hierarchical loglinear model? Maybe even do a model
selection procedure (like Brown's two-step procedure, or
forward/backward selection)? Thanks
2012 Jun 08
1
Fwd: How to best analyze dataset with zero-inflated loglinear dependent variable?
Dear netters,
Sorry for cross-posting this question. I am sure R-Help is not a
research methods discussion list, but we have many statisticians in
the list and I would like to hear from them. Any function/package in R
would be able to deal with the problem from this researcher?
---------- Forwarded message ----------
From: Heidi Bertels
Date: Tue, Jun 5, 2012 at 4:31 PM
Subject: How to best
2009 Apr 20
4
automatic exploration of all possible loglinear models?
Is there a way to automate fitting and assessing loglinear models for
several nominal variables . . . something akin to step or drop1 or add1
for linear or logistic regression?
Thanks.
--Chris
--
Christopher W. Ryan, MD
SUNY Upstate Medical University Clinical Campus at Binghamton
40 Arch Street, Johnson City, NY 13790
cryanatbinghamtondotedu
"If you want to build a ship, don't drum
2011 Jan 19
3
question about result of loglinear analysis
Hi all:
Here's a question about result of loglinear analysis.
There're 2 factors:area and nation.The raw data is in the attachment.
I fit the saturated model of loglinear with the command:
glm_sat<-glm(fre~area*nation, family=poisson, data=data_Analysis)
After that,I extract the coefficients:
result_sat<-summary(glm_sat)
result_coe<-result_sat$coefficients
I find that all the
2014 Dec 04
2
[PATCH v2] v2v: When picking a default kernel, favour non-debug kernels over debug kernels (RHBZ#1170073).
---
v2v/convert_linux.ml | 18 +++++++++++++++---
1 file changed, 15 insertions(+), 3 deletions(-)
diff --git a/v2v/convert_linux.ml b/v2v/convert_linux.ml
index f670812..39a520c 100644
--- a/v2v/convert_linux.ml
+++ b/v2v/convert_linux.ml
@@ -49,13 +49,14 @@ type kernel_info = {
ki_modules : string list; (* The list of module names. *)
ki_supports_virtio : bool; (* Kernel has
2000 Jul 25
1
glm and capture-recapture
Hello,
I am almost new in R, so perhaps my question will be silly.
I try to use R for analyzing capture-recapture data in epidemiology. A cancer registry has different sources of patients. We know in each list, patients already known in all other list. The aim is to use capture-recapture models for estimating the number of patients unknow of all the sources.
Because no order in sources, one
2009 May 19
1
loglinear analysis
Dear R Users,
A would like to fit a loglinear analysis to a three dimensional contingency
table. But I Don't want to run a full saturated modell. Is there any package
in R that could handle somekind of stepwise search to choose out the best
soultion? And how can I fit a non fully saturated modell, which only use the
important interactions?
Best Regards
Zoltan Kmetty
[[alternative HTML
2014 Dec 04
1
[PATCH] v2v: When picking a default kernel, favour non-debug kernels over debug kernels (RHBZ#1170073).
---
v2v/convert_linux.ml | 18 +++++++++++++++---
1 file changed, 15 insertions(+), 3 deletions(-)
diff --git a/v2v/convert_linux.ml b/v2v/convert_linux.ml
index f670812..420aba5 100644
--- a/v2v/convert_linux.ml
+++ b/v2v/convert_linux.ml
@@ -49,13 +49,14 @@ type kernel_info = {
ki_modules : string list; (* The list of module names. *)
ki_supports_virtio : bool; (* Kernel has
2017 Apr 06
1
Re: [PATCH v4 3/9] v2v: linux: Replace 'ki_supports_virtio' field.
On Thursday, 6 April 2017 12:04:21 CEST Richard W.M. Jones wrote:
> Previously the kernel_info field 'ki_supports_virtio' really meant
> that the kernel supports virtio-net. That was used as a proxy to mean
> the kernel supports virtio in general.
>
> This change splits the field so we explicitly test for both virtio-blk
> and virtio-net drivers, and store the results
2014 Dec 04
0
Re: [PATCH v2] v2v: When picking a default kernel, favour non-debug kernels over debug kernels (RHBZ#1170073).
On Thursday 04 December 2014 10:21:40 Richard W.M. Jones wrote:
> ---
> v2v/convert_linux.ml | 18 +++++++++++++++---
> 1 file changed, 15 insertions(+), 3 deletions(-)
>
> diff --git a/v2v/convert_linux.ml b/v2v/convert_linux.ml
> index f670812..39a520c 100644
> --- a/v2v/convert_linux.ml
> +++ b/v2v/convert_linux.ml
> @@ -49,13 +49,14 @@ type kernel_info = {
>
2009 Oct 20
1
2x2 Contingency table with much sampling zeroes
Hi,
I'm analyzing experimental results where two different events ("T1"
and "T2") can occur or not during an experiment. I made my experiments
with one factor ("Substrate") with two levels ("Sand" and "Clay").
I would like to know wether or not "Substrate" affects the occurrence
probability of the two events. Moreover, for each
2014 Dec 04
2
[PATCH v3 0/2] v2v: When picking a default kernel, favour non-debug
Since v2:
- Use string_suffix kernel_name "-debug" || string_suffix kernel_name "-dbg"
- This requires addition of the string_suffix function and some tests
2008 Jun 24
2
How to solve empty cells in the contingency table?
Hi,Dear all R experts,
I am trying to do the 2-way contingency table analysis by fitting the loglinear models. However, I found my table has several empty cells which are theoretically missing values.I have no idea of how to solve them coz we cannot compute the simulated p-value with zero marginals.Does someone have some suggestions? Please help me out, thanks a lot!
Cheers,
Yan
2012 Apr 02
2
linear-by-linear association model in R?
Dear all, can somebody give me some pointer how I can fit a
"linear-by-linear association model" (i.e. loglinear model for the
ordinal variables) in R? A brief description can be found here
'https://onlinecourses.science.psu.edu/stat504/node/141'.
Thanks for your help
2003 Jan 29
3
Analyzing an unbalanced AB/BA cross-over design
I am looking for help to analyze an unbalanced AB/BA cross-over design by
requesting the type III SS !
# Example 3.1 from S. Senn (1993). Cross-over Trials in Clinical
Research
outcome<-c(310,310,370,410,250,380,330,270,260,300,390,210,350,365,370,310,380,290,260,90,385,400,410,320,340,220)
subject<-as.factor(c(1,4,6,7,10,11,14,1,4,6,7,10,11,14,2,3,5,9,12,13,2,3,5,9,12,13))
2016 Sep 25
3
Variable Progresiva
Hola Comunidad,
Tengo una duda,
Queria que en un For si fuese ejecutando un proceso desde 1 hasta 5 por poner un ejemplo , y que el resultado se fuese guardando en variables que se llamar Ki, es decir k1, k2, k3...
Un ejemplo de como crei que funcionaria y no lo hizo xD
for (i in 1:3) {
paste("k", i, sep = "") <- sum(1:i)
}
Esperaba se crearan las variables k1 =
2017 Apr 06
0
[PATCH v4 3/9] v2v: linux: Replace 'ki_supports_virtio' field.
Previously the kernel_info field 'ki_supports_virtio' really meant
that the kernel supports virtio-net. That was used as a proxy to mean
the kernel supports virtio in general.
This change splits the field so we explicitly test for both virtio-blk
and virtio-net drivers, and store the results as separate fields.
The patch is straightforward, except for the change to the
2005 Aug 30
1
loglinear model selection
Hi R-masters!
I have a problem and need your help.
I have 9 discrete variables with 2 levels each.
In exploratory analisys I generate one matrix with chi-square for tables
with 2 ariables each with this script
setwd("F:/")
dados<-read.csv("log.csv")[,2:10]
dados.x<-matrix(NA,ncol=9,nrow=9)
for(i in 1:8){
for(j in (i+1):9){
tab<-table(dados[,i],dados[,j])
2011 Mar 10
2
identical values not so identical? newbie help please!
Hi there!
I'm not sure I can create a minimal example of my problem, so I'm linking to
a minimal .RData file that has only two objects: obs and exp, each is a 6x9
matrix. http://dl.dropbox.com/u/10364753/test.RData link to dropbox file
(I hope this is acceptable mailing list etiquette!)
Here's what happens:
> obs[1, 1]
[1] 118
> exp[1, 1]
[1] 118
> obs[1, 1]-exp[1, 1]
[1]