similar to: empty array indexing with dimnames -> erroneous error (PR#2507)

On Thu, 30 Jan 2003 maechler@stat.math.ethz.ch wrote: > This is a bug that will not often trigger, and only happens for arrays > (but not matrices) ending up with 0 dimensions: The bug is a missing else branch of an if condition at line 431 of subset.c. I don't think the buglets are wrong. You don't drop length 0 dimensions. If you did, the object would be of the wrong length.

>>>>> Serguei Sokol >>>>> on Wed, 19 Feb 2020 15:21:21 +0100 writes: > Hi, > I was bitten by a little incoherence in dimnames assignment or may be I > missed some point. > Here is the case. If I assign row names via dimnames(a)[[1]], when > nrow(a)=1 then an error is thrown. But if I do the same when nrow(a) > 1 >

This message is in MIME format --_=XFMail.1.1.p0.Linux:971128122615:3052=_ Content-Type: text/plain; charset=us-ascii I have rounded up three buglets in R-0.50-a4. Two of them I can fix and a patch is supplied below. I hope this is useful for the current source (if these haven't been fixed already :) 1) cov cov() fails when it's argument is a matrix with one column and with column names

If we change the behavior NULL--[[--assignment from `[[<-`(NULL, 1, "a" ) # gives "a" (*not* a list) to `[[<-`(NULL, 1, "a" ) # gives list("a") then we have more consistency there *and* your bug is fixed too. Of course, in other situations back-compatibility would be broken as well. Would that change the result of L <-

>>>>> Martin Maechler >>>>> on Wed, 19 Feb 2020 18:06:57 +0100 writes: >>>>> Serguei Sokol >>>>> on Wed, 19 Feb 2020 15:21:21 +0100 writes: >> Hi, >> I was bitten by a little incoherence in dimnames assignment or may be I >> missed some point. >> Here is the case. If I assign row names

Is there a reason that array() silently ignores dimnames that are not a list but matrix() gives an error? > str(matrix(11:14, 2, 2, dimnames=c("Rows","Cols"))) Error in matrix(11:14, 2, 2, dimnames = c("Rows", "Cols")) : 'dimnames' must be a list > str(array(11:14, dim=c(2, 2), dimnames=c("Rows","Cols"))) int

Hello, I am encountering some problems when overloading the "[" operator for a new S4 class based on array. This is an example class definition: setClass("foo", representation("array"), prototype(array(NA, dim=c(3,3)), dimnames=list(age=1:3, year=10:12)) ) And this the corresponding setMethod with print estatements to see what is being passed:

Hi all, I have a three dimensional array with the corresponding dimension names. I would like to subset the array according to the dimension names. For example, suppose I want to extract the values corresponding to A=20, B=10, C=0. I know I can do: P2[dimnames(P2)$A==20, dimnames(P2)$B==10, dimnames(P2)$C==0] But is there a better way for doing this? Thanks for your help! Hanna >

Have you tried P2["20", "10", "0"] ? Jean On Thu, Jun 1, 2017 at 3:10 PM, li li <hannah.hlx at gmail.com> wrote: > Hi all, > I have a three dimensional array with the corresponding dimension names. > I would like to subset the array according to the dimension names. For > example, > suppose I want to extract the values corresponding to A=20,

Hi list, In a function I am writing, I need to extract the dimension names of an array. I know this can be acheived easily using dimnames() but my problem is that I want my function to be robust when the number of dimensions varies. Consider the following case: foo <- array(data = rnorm(32), dim = c(4,4,2), dimnames=list(letters[1:4], LETTERS[1:4], letters[5:6])) # What I want is to extract

Hello, I did send this message to r-help and got no reply, no I am resubmitting here in case this was a bit too specific for the other list. Many thanks, Iago From: Iago Mosqueira <imosqueira@suk.azti.es> To: r-help@stat.math.ethz.ch Subject: Subsetting using dimnames on S4 array-based class

Hi everyone, I have the following problem: I want to perform a LDA with the function lda(). My data object mat.data is a matrix with dimensions > dim(mat.data) [1] 1228 44 and my grouping vector grp has length 1228: > length(grp) [1] 1228 Every time I call lda(), the following error message occurs: > lda(mat.data,grp) Error in lda.default(x, grouping, ...) : length of dimnames [2]

Hello all, I'm trying to use the user-created multinomRob to make some models for my data. While documentation for that function is fine and I think I'm using it correctly, I'm getting the following error when I try to use my lists of variables. data <- read.csv("data.csv", header=FALSE) subj1 <- data.frame(radius=data$V3[9:11], x1=data$V4[9:11], x2=data$V5[9:11],

dear all i'm struggling with naming in an array diag.data is one of a series of 2x2 diagnostic testing arrays, with 'Outcome' columns (true/false) and 'Test' rows (High-risk, Low-risk), drawn from a larger list object of 'results' i can hard-code the names of the array using dimnames; diag.data<-array(c(19,2,125,50),c(2,2)) #example to run - actually comes out

Hello, I'm working with an array; I'm trying to make it so that an array of dim(42,2,2) has names whose length corresponds to that of the array, and am hoping someone with experience with this can see what I'm not doing correctly: data11 = array(0,c(41,2,2)) y = lsoda(x0,times,fhn$fn.ode,pars)#This is make.fhn() from colloc infer package# y = y[,2:3]

hello R-helpers, I have an array acuracia <- array(NA, dim = c(1, 1, A, B, C)) which is first defined and in the example above with dimensions 1x1xAxBxC. My array is then filled using 3 loops (I am not well familiar yet with lapply or sapply functions so I am still a loop-user): for (i in 1:A){ for (j in 1:B){ for (k in 1:C){ acuracia[,,i,j,k] <- correlacao / (sqrt(ac)) } } } then I

>>>>> William Dunlap >>>>> on Fri, 21 Feb 2020 14:05:49 -0800 writes: > If we change the behavior NULL--[[--assignment from > `[[<-`(NULL, 1, "a" ) # gives "a" (*not* a list) > to > `[[<-`(NULL, 1, "a" ) # gives list("a") > then we have more consistency there *and* your bug

Hello, all, I'm a new R user (new to any programming language in general, really), so I apologize if this is easy/has already been answered (I've attempted searching online but did not understand the pages I found). My data is stored in text files with the headers LANE, RNA_NAME, SEQ, and SEQCNT. I've been using x = "filename.txt" y = aggregate(x$SEQCNT, list(x$RNA_NAME),

I'm assuming you are using the corrplot package. If so, your data object does need to be a matrix, not a data frame. Since it's already a data frame, your line of code: as.matrix(as.data.frame(CR1)) doesn't need the as.data.frame function, but more importantly, you didn't assign the result to anything: as.matrix() does not work in place. CR1 <- as.matrix(CR1) Now try. If

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at