similar to: RE: cut.dendrogram (PR#1552)

>>>>> "MikG" == M GRUM <M.GRUM@CGIAR.ORG> writes: MikG> I'm resending this bug report with a new example. As MikG> seen below, cut.dendrogram gives an error message for MikG> some heights, but not for others and with some MikG> datasets adn not others. I can't see why. MikG> Last time I unwittingly sent my message with

I'm resending this bug report with a new example. As seen below, cut.dendrogram gives an error message for some heights, but not for others and with some datasets adn not others. I can't see why. Last time I unwittingly sent my message with HTML formatting. This time I'm travelling and using an e-mail system that I am unfamiliar with. As far as I can see, I am not using HTML.

This message is in MIME format. Since your mail reader does not understand this format, some or all of this message may not be legible. ------_=_NextPart_000_01C35A53.75780090 Content-Type: text/plain; charset="iso-8859-1" Anyone have a clue why hclust() and agnes() produce different results in the example below when both use method="average"?? I'm not able to reproduce

Can anyone tell me what's wrong with this command?? xx<-subset(x,LOCAL.NAME==c("Chifumbata","Chikota"),select=c(13,16,19,23,26,2 9,30,33:48)) Warning message: longer object length is not a multiple of shorter object length in: LOCAL.NAME == c("Chifumbata", "Chikota") both of the following commands work fine

First question: I have an Excel file with both character and numeric variables that I want to import to a data.frame, so I've saved the data to a tab-delimited text file. read.table : * Won't identify the mode of my character variables, as some of them contain only numbers and none of them are surrounded by quotes, * Won't allow me to specify the mode of my variables, * Doesn't

I'm trying to plot four different sorghum types on a plot using a different colour/symbol combination for each sorghum type (TYPBOTA in the script below). What am I doing wrong?: plot(xx$LATITUDE,xx$SFD1, points(xx$SFD1,xx$LATITUDE, col=1:4[codes(xx$TYPBOTA)],pch=c(4,3,1,2)[codes(xx$TYPBOTA)]) grid() I get the following error message Error in 1:4[codes(xx$TYPBOTA)] : NA/NaN argument

Is there a way of removing all rows with missing values from a data frame? I usually use subset(x, var1!="NA") and repeat for each variable. It would be nice to be able to do it in one fell swoop. Also, surprisingly, it doesn't always work. Sometimes I'm left with an empty set even though not all rows have missing values for the variable. Cheers, mikkel Mikkel Grum,

I'm trying to plot observations against observation dates and getting julian dates along the x-axis: library(date) Week<-as.date(c("05/02/03","05/09/03","05/16/03","05/23/03","05/30/03","06/0 7/03","06/14/03")) Leafminers<-c(0,2,5,10,4,6,5) Diglyphus<-c(0,0,4,5,7,3,1) LeafDig<-cbind(Week,Leafminers,Diglyphus)

Hi! I just discovered that cutree() and cut.dendrogram() do not assign the same cluster numberings when called on the same tree. More specifically, cutree() assigns cluster numbers by order of appearance in the data, while cut.dendrogram() sorts clusters by height (see example below). I guess this is for historical reasons? I'm hit by this difference when I want to get a vector of cluster

I have two problems where I've come up with some code that will do the analysis that I want, but it looks pretty clumsy. In the first case, I calculate the variance on five different columns for each of 14 clusters and get them into one matrix. I get the job done, but I would have thought that it could be done in one or two lines, not six, and be generalized so that it didn't matter how

Hi! In the example: hc <- hclust(dist(USArrests), "ave") dend1 <- as.dendrogram(hc) dend2 <- cut(dend1, h=70) Do the branches "Branch 1", "Branch 2", "Branch 2"...in dend2$upper str(dend2$upper) --[dendrogram w/ 2 branches and 4 members at h = 152] |--[dendrogram w/ 2 branches and 2 members at h = 77.6] | |--leaf "Branch 1" (h=

Is there a way of extracting mean distance or dissimilarity for a given strata from a 'dist' or 'dissimilarity' object, e.g. extract mean distances for each species in Anderson's iris data? data(iris) iris.dist<-dist(iris[,1:4]) then what? Mikkel Grum, PhD Genetic Diversity Scientist International Plant Genetic Resources Institute (IPGRI) Sub-Saharan Africa Group ***

When I use the function cutree(), the numbers of the clusters are not in the same order as the plotted dendrogram. Is there any way of sorting them so that they match the tree? Is it possible to plot a dendrogram horizontally, preferably with the branches to the right? This would enable some practical composite plots, e.g. labels that were an entire table with several columns of information, or

Any idea why clusters five and six fall off the scale in the following? library(cluster) library(maptree) data(flower) dfl2<-daisy(flower,type=list(asymm=c(1,3),ordratio=7)) hdfl2<-hclust(dfl2) prune.dfl2<-prune.clust(hdfl2,k=6) plot(prune.dfl2) Of course the following will display all six clusters, but without a scale: draw.tree(prune.dfl2) Best wishes, Mikkel Mikkel Grum

================================================= This is an automated summary of the status of the R-bugs repository. Note that this may be neither complete nor perfectly correct at any given instance: Not all bugs are reported, and some reported bugs may have been fixed, but the repository not yet updated. Some bug fixes are difficult to verify because they pertain to specific hardware or

plot.hclust: Setting up a window for a dendrogram assumes the first link is the shortest and the last is the longest. This is not always the case when the clustering was done with hclust, method="median" or method="centroid", and the dendrogram sometimes doesn't fit within the window. I propose the fix listed below. src/main/ --- plot.c Wed Sep 17 01:03:39 2003 +++

Hello, I've been clustering my data using hclust and cutting the resulting tree with cutree. Separately, I visualize the clusterings with heatmap. Is it possible to have the dendrogram on the heatmap reflect the cutree results? That is, instead of having one large dendrogram, it would have 4 or 25 in the example below. Any guidance on if that's possible or not, and what kinds of

Dear all, I have been trying the following without avail and would be very grateful for any help. From a dendrogram (recursive list of lists with some structure), I would like to obtain some information of the component lists and of the enclosing list at the same time. In dendrogram-speech I basically would like the label of the leaf and the height of the enclosing branch. A dendrogram example

Hi all, I'm having a problem where by I'm trying to use the NeatMap draw.dendrogram function as it is more versatile in placement/direction of dendrograms, instead of the limited plot function. Using plot I can get my dendrograms to display the species name for each leaf of the tree. But I cannot figure out how to make this happen using draw.dendrogram.. genetic<-

Dear I am using the 'as.dendrogram' function from the 'stats' library to convert from an hclust object to a dendrogram with a dataset of size ~30000 (an example code is below). I need the dendrogram structure to use the "dendrapply" and "attributes" functions and to access the child nodes, I do not need any of the plot properties. The problem is that it