similar to: converting #sec to POSIX* format

Wondered about the best way to control for input variables that have a large number of levels in 'rpart' models. I understand the algorithm searches through all possible splits (2^(k-1) for k levels) and so variables with more levels are more prone to be good spliters... so I'm looking for ways to compensate and adjust for this complexity. For example, if two variables produce

Hello R Users, How to convert decimal date to date as YYYY.mm.dd.hr.min.sec For example, I have decimal date in one column , and want to convert and write it in equivalent date(YYYY.mm.dd.hr.min.sec) in another next six columns. 1979.000000 1979.020833 1979.041667 1979.062500 Is it possible in R ? Kindly help, Regards, Yogesh -- Dr. Yogesh K. Tiwari, Scientist, Indian Institute

Hi all, I'm having difficulty converting a 'dates' object to a POSIXct object: testDATES<-c(35947,35971,36004,36008,36053,36066) testDATES<-chron(dates=testDATES, format = c(dates = "m/d/y"), origin=c(month = 12, day = 30, year = 1899)) >[1] 06/01/98 06/25/98 07/28/98 08/01/98 09/15/98 09/28/98 > as.POSIXct(testDATES) [1] NA NA NA NA NA NA

Dear all I try to make hourly average by cut() function, which almost works as *I* expected. What puzled me is that if there is only one item at the end of your data it results in NA. Example will explain what I mean datum<-seq(ISOdate(2004,8,31), ISOdate(2004,9,1), "min") cut(datum[1370:1381],"hour", labels=F) [1] 1 1 1 1 1 1 1 1 1 1 1 NA

Dear all, I have found the following (for me) incomprehensible behaviour of ISOdate (POSIXct): > ISOdate(1900,6,16) [1] "1900-06-15 14:00:00 Westeurop?ische Sommerzeit" > ISOdate(1950,6,16) [1] "1950-06-16 14:00:00 Westeurop?ische Sommerzeit" Note that in the first case I get the 15th of June back, not the 16th as I would have expected! This happened under R-1.7.1 on

On Mon, Mar 19, 2018 at 5:57 PM, Jayme <jaymef at gmail.com> wrote: > I'm spec'ing a new oVirt build using three Dell R720's w/ 256GB. I'm > considering storage options. I don't have a requirement for high amounts > of storage, I have a little over 1TB to store but want some overhead so I'm > thinking 2TB of usable space would be sufficient. > >

I have some data that was created for import into a Lotus 1-2-3 spreadsheet and on of the columns is time. The time is akin to Julian were the value 1 is mapped "01-Jan-00 12:00:00 AM" in Lotus 1-2-3. Is there a function in an R package that can convert this numeric vector to a POSIXct vector? With best wishes and kind regards I am Sincerely, Corey A. Moffet Instructor Department

Does R have a comparison operator similar to the Like function, for example: a<-"Is a Fish" b<-"Fish" if(b in a){c<-TRUE} Michael R Howard Micron Technology Inc. Boise ID. Fab C Engineering Software (FCES) Software Engineer

Dear R-people! I am using R 1.8.0, under Windows XP. While using ISOdate() and strptime(), I noticed the following behaviour when "wrong" arguments (e.g., months>12) are given to these functions: > ISOdate(year=2003,month=2,day=20) #ok [1] "2003-02-20 13:00:00 Westeurop?ische Normalzeit" > ISOdate(year=2003,month=2,day=30) #wrong day, but returns a value [1]

I am having a series of problems using date time data that has been converted into a POSIXt and POSIXlt classes. I have hourly time series data from 1900 that has been converted from text data. I assume most of my problems come from a mis-underdanding of the POSIX class. My matrix named (aa) for this year is approx 8700 by 4. When I try to calculate the length of posit column ( which is the

R developers, The "tzone" attribute is stripped from a POSIXct object when the subscript command is called ("[.POISXct"). This results in dates being printed in the locale specific format after a subscript operation is applied to a POSIXct object which has cause several problems for me in the past. Here is an example of this problem under R 1.9.1: > x <-

I have a monthly price index series x, the related return series y = diff(log(x)) and a POSIXlt date-time variable dp. I would like to apply annual blocks to compute for example annual block maxima and mean of y. When studying the POSIX classes, in the first stage of the learning curve, I computed the maximum drawdown of x: > mdd <- maxdrawdown(x) > max.dd <- mdd$maxdrawdown > from

Dear All, I have a data set containing year, month, day and counts as shown below: data <- read.table("data.txt", col.names = c("year", "month", "day", "counts")) Using the formula below, I converted the data to as date and plotted. new.century <- data$year < 70 data$year <- ifelse(new.century, data$year + 2000, data$year + 1900)

I am having problems with trying to run R from a crontab job. I have a c-shell file that calls the R script. I get an error concerning the X11 display (see below). I have included the c-shell file and the output from the crontab job. It appears that my DISPLAY environmental variable is not set. Is that necessary, even when the output of the plot command is to a png file? Can someone tell me how to

Attached is a patch for rsync 2.5.0 to fix the "make check" option. The find command was not being passwd the current directory in the hands.test and longdir.test testsuites, which caused them to fail on SunOS 4.X and Solaris 2.X systems. Tom -- Tom L. Schmidt, Manager/SysAdmin Characterization Equipment Micron Technology, Inc. 8000 S. Federal Way P.O. Box 6 Mail Stop 376 Boise,

I am a beginner in R with a background in SAS. Are there built-in R methods of reading dates for calculating elapsed days between two calendar dates? If so, are there any examples I can browse? Thanks in anticipation. John Byrne. Lecturer in Information Systems. Australian Catholic University.

I have a number of plots that I'm trying to do using the lattice package, unfortunately, they involve Posix values. A small sample of the data is as follows: Time TC.1 <Snipped> 1 2003-04-24 13:29:15 26.61 2 2003-04-24 13:29:30 26.48 3 2003-04-24 13:30:00 26.53 4 2003-04-24 13:30:30 27.85 <Snipped> where str(data) `data.frame': 415 obs. of

Hearing no opinions to the contrary, let's say Banger's 6pm (tomorrow). Address and web site below. I submitted online for a reservation early this morning, and I'll try to get an updated head count on Sunday morning. -Hal Sent from my Verizon Wireless 4G LTE DROID On Nov 14, 2015 11:21 AM, Chandler Carruth <chandlerc at google.com> wrote: Did this ever get settled? On Fri,

The interface for dates in R is a little confusing to me. I want to create a vector of Date objects from vectors of years, months, and days. One solution I found is: years <- c(1991, 1992) months <- c(1, 10) days <- c(1, 2) dates <- as.Date(ISOdate(years, months, days)) But, in this solution the ISOdate function converts the vectors into characters, which can cause serious

Dear all recently I tried to split vector of dates according to some particular date to 2 (more) chunks, but I was not able to perform correct setting. When I want split to 3 chunks it partially works however from help page I supposed to get result without NA. Details: Using both ?right = TRUE? and ?include.lowest = TRUE? will include both ends of the range of dates. dat <-