similar to: understanding and resolving seg faults

Dear R-devel, I am trying to alter rpart so that it makes additional calculations when growing the tree. In the "rpart.s" there is a call to the C routine: rp <- .C("s_to_rp2", as.integer(nobs), as.integer(nsplit), as.integer(nodes), as.integer(ncat),

Hi everyone, I am having a bit of trouble correctly structuring an equation in R. Here is the equation Here is what I thought for(i in 1:numItem)for(x in 1:numCat) Ptheta[,i,x]<-(exp(-1.702*a[i]*(theta-b[i,x+1])) My problem is that I am not sure how to get it to read the equation as having two indexing points (i and x). Right now it is trying to read it as a matrix, but

Running on an Alpha machine which reports (uname -a) OSF1 bsdx01.bs.ehu.es V4.0 878 alpha and using the binary distribution put together by Albrecht Gebhardt (in http://cran.at.r-project.org/bin/osf/osf4.0/tar/alpha_ev5/) I obtain core dumps whenever I try to use package rpart. I have R REMOVE'd the rpart package, downloaded the source rpart_1.0-7.tar from CRAN and

Dear members of R-list, I need to reproduce the rules of a decision tree. For that I need to use the csplit information from the rpart.object. But I cannot uderstand the information because from my example I get: > rpart.tree$csplit [,1] [,2] [,3] [,4] [,5] [,6] [,7] [1,] 1 3 3 1 3 3 3 [2,] 2 3 3 1 2 2 2 [3,] 1 3 3 1 3 3 3

I write about R every weekday at the Revolutions blog: http://blog.revolution-computing.com In case you missed them, here are some articles from last month of particular interest to R users. http://bit.ly/11YkB0 listed seven reasons of an anthropology professor for using R. http://bit.ly/9sbno linked to an intro of the ply package for performing SQL-like "group by" operations on data

I have wrote a small Linux Shell command for implementing Interlock Protocol which is known as a cryptographic protocol that resistant to man-in-the-middle attack. Here is the steps of interlock protocol: *(1)* Alice send her public key to Bob *(2)* Bob send his public key to Alice. *(3)* Alice encrypts her message using Bob's public key. Then she sends half of that encrypted message to

Hello, I am attempting to create several plots based on "site" (~300 total) and am having trouble with the code. I simply want to create a plot using the code, plot(year, peak), for the following dataset. I would like for each site to be plotted on a separate page and the plots saved in a directory. Would a "foreach" loop work? I tried a "by" statement, but

I have a class with 732 members, so using rpart.plot is giving me a tiny plot in the middle of the window. Is there a good way to modify the plot, or replace the long list with something like "group1"? -- View this message in context: http://r.789695.n4.nabble.com/Plotting-rpart-trees-with-long-list-of-class-members-tp4635671.html Sent from the R help mailing list archive at

I am rsyncing and remotely doing some work based on a logfile from a windows box from a centos backup server. I get the output from a vss snapshot that has a section like this: * SNAPSHOT ID = {639ef5df-c933-4496-878a-ed57b9d52876} ... - Shadow copy Set: {427ac5db-21be-4c53-8ca4-24e7bac86a1d} - Original count of shadow copies = 2 - Original Volume name:

I have a data frame with about 10^6 rows; I want to group the data according to entries in one of the columns and do something with it. For instance, suppose I want to count up the number of elements in each group. I tried something like aggregate(my.df$my.field, list(my.df$my.field), length) but it seems to be very slow. Likewise, the split() function was slow (I killed it before it completed).

Not a CentOS specific question, although I am running grep on CentOS 4.3 but how would you grep out a series of lines in a file starting at a specific point. For instance, if I have a file named foo and I want to grep out the next 5 lines after the first and only instance of the string "bar" how could I pull that off? Thanks so much.

Hi folks, Here's the situation. I have a group of engineers who love to save things to disk. Now that the filer is getting full, they are interested in archiving some of those things to DVD. The tress containing the things they want to archive are specified like so: /path/path/path/A/04?? /path/path/path/B/04?? /path/path/path/A/05?? /path/path/path/B/05?? /path/path/path/A/06??

I am a rank newbie to Linux and wine. I am running Ubuntu Dapper on an AMD 1800 mhz machine, wine 0.9.15 Everything I have read says use the installer to load windows programs. Where is the installer? Thanks, -- Ron Thompson On the Beautiful Florida Space Coast, right beside the Kennedy Space Center, USA http://www.plansandprojects.com My hobby pages are here:

Hi, Suppose i have generated an object using the following : fit <- rpart(Kyphosis ~ Age + Number + Start, data=kyphosis) And when i print fit, i get the following : n= 81 node), split, n, loss, yval, (yprob) * denotes terminal node 1) root 81 17 absent (0.7901235 0.2098765) 2) Start>=8.5 62 6 absent (0.9032258 0.0967742) 4) Start>=14.5 29 0 absent (1.0000000