Displaying 20 results from an estimated 3000 matches similar to: "color of axis lines (PR#1470)"
2012 Dec 06
1
Anomalous outputs from rbeta when using two different random number seeds
Hi, in the code below, I am drawing 1000 samples from two beta
distributions, each time using the same random number seed.
Using set.seed(80) produces results I expect, in that the differences
between the distributions are very small.
Using set.seed(20) produces results I can't make sense of. Around half of
the time, it behaves as with set.seed(80), but around half of the time, it
behaves
2009 Feb 05
1
optimal control, maximization with several variables?
Dear all,
I would like to solve the following problem, which can be done with optimal control theory or dynamic programming:
max(x,y) a*u1+b*u2+c*f1(u2) s.t. 0<u1<x, 0<u2<f2(x,u2), x'=f3(u1,u2,x)
which can be rewritten if optimal control theory should be applied as
H=a*u1+b*u2+c*f1(u2)+lambda*(x') s.t. 0<u1<x, 0<u2<f2(x,u2)
The maximum principle
2013 May 16
2
A function that can modify an object? Or at least shows principles how to modify an object?
Hi, If I have an R object UUU, where the second element is U2, based on
"g" column of my.table
my.table of UUU is:
mmm ggg gindex map Info
aaa123 U1 1 1 1
aaa124 U1 1 2 1
bbb1378 U2 2 1 1
bbb8888 U2 2 2 0
bbb1389 U2 2 3
2020 Apr 29
1
grid 4.0 generates wrong results when adding two complex units by sum()
Hi,
In grid 4.0, adding two complex units by `sum()` seems to give wrong results.
In the following example, `u1 + u2` gives the correct result, but `sum(u1, u2)` also `sum(unit.c(u1, u2))` give the wrong results.
```
library(grid)
u1 = 0.4*sum(unit(1, "inch"), unit(1, "mm"))
u2 = 0.1*sum(unit(1, "inch"), unit(1, "mm"))
u1
# [1] 0.4*sum(1inches, 1mm)
2011 Mar 29
5
Integration with variable bounds
If this is posted elsewhere I cannot find it. I need to perform multiple
integration where some of the variables are in the bounds of the other
variables. I was trying to use R2Cuba function but cannot set the upper and
lower bounds. My code so far is :
int <- function(y){
u2 = y[1]
z2 = y[2]
u1 =y[3]
z1 = y[4]
ff <- u1*(z1-u1)*u2*(z2-u2)*exp(-0.027*(12-z2))
return(ff)
}
2016 Dec 07
4
You have not permission to view content of this location
OS: CentosOS 7
I have installed samba + openldap + smbldap-tools + pam by:
yum --enablerepo=extras install -y epel-release
yum install -y smbldap-tools
yum install -y samba openldap openldap-clients openldap-servers migrationtools
yum install -y nss-pam*
I know that smbldap-tools is a dead project, but I'm interested in it and would like research on it.
I create users and
2011 Sep 11
3
(no subject)
Dear all,
Can anyone take a look at my program below?
There are two functions: f1 (lambda,z,p1) and f2(p1,cl, cu).
I fixed p1=0.15 for both functions. For any fixed value of lambda (between
0.01 and 0.99),
I solve f1(p1=0.15, lambda=lambda, z)=0 for the corresponding cl and cu
values.
Then I plug the calculated cl and cu back into the function f2.
Eventually, I want to find the lambda value
2011 Jan 27
2
help for a loop procedure
Hello everybody!
I’m trying to define the optimal number of surveys to detect the highest
number of species within a monitoring season/session.
To do this I want to run all the possible combinations between a set of
samples and to calculate the total number of species for each combination of
2, 3, 4 …n samples events, so that at the end I will be able to define which
is the lowest number of
2018 Mar 12
0
subsetting comparison problem
> On Mar 11, 2018, at 3:32 PM, Neha Aggarwal <aggarwalneha2000 at gmail.com> wrote:
>
> Hello All,
> I am facing a unique problem and am unable to find any help in R help pages
> or online. I will appreciate your help for the following problem:
> I have 2 data-frames, samples below and there is an expected output
>
> R Dataframe1:
> C1 C2
2007 Mar 27
7
Replacement in an expression - can't use parse()
Dear all,
Suppose I have a very long expression e. Lets assume, for simplicity, that it is
e = expression(u1+u2+u3)
Now I wish to replace u2 with x and u3 with 1. I.e. the 'new'
expression, after replacement, should be:
> e
expression(u1+x+1)
My question is how to do the replacement?
I have tried using:
> e = parse(text=gsub("u2","x",e))
> e =
2006 Nov 21
2
Symbolic derivation using D in package stats - how do I properly convert the returned call into a character string?
Dear all,
I am using the function 'D' in the 'stats' package to perform symbolic
derivation.
This works very well and it is much faster than e.g. Mathematica (at
least for my purposes).
First, I would like to thank the development team for this excellent
function.
However, I run into trouble in some cases, particularly when I am to do
some operations on long expressions
2007 Apr 20
1
Estimating a Normal Mixture Distribution
Hi everyone,
I am using R 2.4.1 on a MacOS X ("Tiger") operating system. In the
last few day I was trying to estimate the parameters of a mixture of
two normal distributions using Maximum Likelihood.
The code is from Modern Applied Statistics with S (4th edition),
chapter 16 ("Optimization"), the dataset is available under MASS in
R. Unfortunately, when I tried out the
2018 Jan 15
1
"linkfile not having link" occurrs sometimes after renaming
There are two users u1 & u2 in the cluster. Some files are created by u1,
and they are read only for u2. Of course u2 can read these files. Later
these files are renamed by u1. Then I switch to the user u2. I find that u2
can't list or access the renamed files. I see these errors in log:
[2018-01-15 17:35:05.133711] I [MSGID: 109045]
[dht-common.c:2393:dht_lookup_cbk] 25-data-dht:
2003 Oct 29
1
grid: dividing units by numbers
How can I divide a unit by an number
or average a vector of units, e.g.:
u1 <- unit( 3, 'npc' )
u2 <- unit( 6, 'npc' )
u1 / 2
( u1 + u2 ) / 2
mean( unit.c(u1,u2) )
I would use that e.g. to to calculate the coordinates
of the midpoint of a line.
Wolfram
2010 Oct 06
4
loop in R
Dear all,
I need to do a loop in R, but I am not sure the software is generating "n" times the variables I request differently. When I ask to print the last matrix created, I just can see the loop for n=1.
To be more precise, supose I need to simulate 10 times one variable and I want to fit the 10 variables simulated in a matrix. I dont really know what I am doing wrong, but I just
2003 Apr 25
4
Kinderman-Ramage (PR#2846)
Hi,
Our department has detected a bug in the implementation of the
Kinderman-Ramage generator for normal random variates in version
1.7.0, which can be seen from the below R session.
(Consecutive calls for chisq.test(...) always gives p-values very
close to 0.)
We have already encountered this bug in version 1.6.2
The error is in file
R-1.7.0/src/nmath/snorm.c
Here is a patch for this file to
2018 Mar 11
4
subsetting comparison problem
Hello All,
I am facing a unique problem and am unable to find any help in R help pages
or online. I will appreciate your help for the following problem:
I have 2 data-frames, samples below and there is an expected output
R Dataframe1:
C1 C2 C3 C4...... CN
R1 0 1 0 1
R2 1 0 1 1
R3
1999 Sep 27
1
users access rights
Hello,
I'm running samba v2.0.5a and I have some problems with settings users access
rights to our Projects share.
We have a projects share with project directories:
\\XX\Projects\P1 ... P5
and 6 people : U1 ... U6
All users must have primary group "users".
I need to set permissions for each Px directory and each Ux user.
(For ex.: U1,U2 has rwx for P1/* U2,U3,U6 has
2001 May 06
1
deriv3 example on Venables/Ripley page 263
What does it require to run the example on page 263
of Venables/Ripley book using R 1.3.0?
I got the following error and I have no clue how to correct it.
Thank you very much. (If you reply to the list, please send a
copy to me.)
> lmix2 <- deriv3(
+ ~ -log(p*dnorm((x-u1)/s1)/s1 + (1-p)*dnorm((x-u2)/s2)/s2),
+ c("p", "u1", "s1", "u2",
2010 Jan 19
2
subfolder level restriction
hello
I have three users u1 ,u2 and u3
I have a share named "mrt" and it has two subfolder "mrt1" and "mrt2".
what i have to do is that when u1 logs in mrt
it should view all the contents inside mrt (including contents of its subfolderand all)
and when u2 logs into mrt it should view mrt1 and restrict mrt2 and in same way when u3 logs into mrt ,it could access mrt2