Displaying 20 results from an estimated 30000 matches similar to: "Reading Inf and NaN values under windows (PR#1072)"
2005 Jul 06
1
Error message NA/NaN/Inf in foreign function call (arg 6) when using knn()
I am trying to use knn to do a nearest neighbor classification. I tried using my dataset and got an error message so I used a simple example to try and understand what I was doing wrong and got the same message. Here is what I typed into R:
try
[,1] [,2] [,3] [,4]
r "A" "A" "T" "G"
r "A" "A" "T" "G"
f
2011 May 26
2
NaN, Inf to NA
Hi,
I want to recode all Inf and NaN values to NA, but I;m surprised to see the
result of the following code. Could anybody enlighten me about this?
> df <- data.frame(a=c(NA, NaN, Inf, 1:3))
> df[is.infinite(df) | is.nan(df)] <- NA
> df
a
1 NA
2 NaN
3 Inf
4 1
5 2
6 3
>
Thanks!
Cheers!!
Albert-Jan
2011 May 26
2
NaN, Inf to NA
Hi,
I want to recode all Inf and NaN values to NA, but I;m surprised to see the
result of the following code. Could anybody enlighten me about this?
> df <- data.frame(a=c(NA, NaN, Inf, 1:3))
> df[is.infinite(df) | is.nan(df)] <- NA
> df
a
1 NA
2 NaN
3 Inf
4 1
5 2
6 3
>
Thanks!
Cheers!!
Albert-Jan
2011 Sep 11
2
how to remove NA/NaN/Inf in a matrix??
Hi all..
I'm very new R, and i'm analyzing microarray data using Bioconductor..
Recently i was given microarray data to analyze. The problem is whenever i
run MAS5 presence calls algorithm,
it throws an error saying NA/NaN/Inf in foreign function. How do i remove
such NA/NaN/Inf's ??
I tried na.omit(dataframe) but stil problem exists.
dimension of matrix (data) is 35556 7.
>
2011 Dec 13
1
NA/NaN/Inf in foreign function call question
Dear all,
I have a datafile where I run haplo.GLM analyses using several variables (a
matrix). However, when I include a certain binary variable (0,1) I get this
message
Error: NA/NaN/Inf in foreign function call (arg 4)
I don't get an error when I include another binary variable, again with only
0,1.
Both variables don't have missing values, they only have 0 and 1.
Why do I get an
1998 Jul 22
1
R-beta: NaN & Inf
Can someone explain what this words (NaN and Inf) mean ? I get then as a
result of some matrix operations, in the end I have a matrix without any
figures just this words.
regards
ernesto
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2008 Oct 25
1
0 ^ NaN == Inf, why?
In R, 0 ^ NaN yields Inf. I would have expected NaN or perhaps 0. Is this
behaviour intended?
>sessionInfo()
R version 2.8.0 (2008-10-20)
i386-pc-mingw32
locale:
LC_COLLATE=English_United States.1252;LC_CTYPE=English_United
States.1252;LC_MONETARY=English_United
States.1252;LC_NUMERIC=C;LC_TIME=English_United States.1252
attached base packages:
[1] stats graphics grDevices utils
2010 May 13
1
results of pnorm as either NaN or Inf
I stumbled across this and I am wondering if this is unexpected behavior
or if I am missing something.
> pnorm(-1.0e+307, log.p=TRUE)
[1] -Inf
> pnorm(-1.0e+308, log.p=TRUE)
[1] NaN
Warning message:
In pnorm(q, mean, sd, lower.tail, log.p) : NaNs produced
> pnorm(-1.0e+309, log.p=TRUE)
[1] -Inf
I don't know C and am not that skilled with R, so it would be hard for me
to look into
2006 Jul 14
1
dweibull retuns NaN instead of Inf (PR#9080)
Full_Name: G?ran Brostr?m
Version: 2.3.1
OS: Linux, ubuntu
Submission from: (NULL) (85.11.40.53)
> dweibull(0, 0.5, 1)
[1] NaN
Warning message:
NaNs produced in: dweibull(x, shape, scale, log)
should give Inf (and no Warning). Compare with
> dgamma(0, 0.5, 1)
[1] Inf
This happens when 'shape' < 1.
2011 Feb 14
1
Error en lm.fit NA/NaN/Inf en llamada a una función externa
Hello, I am new with R, and I'm trying to fit a linear model, I did the
following and obtein this result, can anybody help? Thanks,
> logdftodos7925vi <- log(dftodos7925vi)
> logALTURA7925<- log(dftodos7925$ALTURA7917)
> logtodos7925.lm <- lm (logALTURA7925~., data= logdftodos7925vi)
Error en lm.fit(x, y, offset = offset, singular.ok = singular.ok, ...) :
NA/NaN/Inf en
2011 Dec 15
2
Random Forest Reading N/A's, I don't see them
After checking the original data in Excel for blanks and running Summary(cm3)
to identify any null values in my data, I'm unable to identify an instances.
Yet when I attempted to use the data in Random Forest, I get the following
error. Is there something that Random Forest is reading as null which is not
actually null? Is there a better way to check for this?
> library(randomForest)
>
2024 Sep 05
1
BUG: atan(1i) / 5 = NaN+Infi ?
> complex(real = 0, imaginary = Inf)
[1] 0+Infi
> Inf*1i
[1] NaN+Infi
>> complex(real = 0, imaginary = Inf)/5
[1] NaN+Infi
See the Note in ?complex for the explanation, I think. Duncan can correct
if I'm wrong.
-- Bert
On Thu, Sep 5, 2024 at 3:20?PM Leo Mada <leo.mada at syonic.eu> wrote:
> Dear Bert,
>
> These behave like real divisions/multiplications:
>
2005 Sep 26
2
nls and na/Nan/Inf error
I am trying to it a particular nonlinear model common in Soil Science to
moisture release data from soil. I have written the function as shown
below according to the logist example in Ch8 of Pinheiro & Bates. I am
getting the following error (R version 2.1.1)
*Error in qr(attr(rhs, "gradient")) : NA/NaN/Inf in foreign function
call (arg 1)*
Below is the function and data.
/#
2024 Sep 06
1
BUG: atan(1i) / 5 = NaN+Infi ?
I expect that atan(1i) = (0 + infinity i) and that atan(1i)/5 = (0 +
infinity i)/5 = (0 + infinity i).
Here's what I get in C:
(0,1) = (0, 1)
atan((0,1)) = (0, inf)
atan((0,1))/5 = (0, inf)
Note the difference between I*infinity = (0,1)*infinity =
(0*infinity,1*infinity) = (NaN,infinity)
and (0,infinity)/5 = (0/5,infinity/5) = (0,infinity).
The former involves multiplying 0 by infinity, which
2015 Nov 30
1
Inconsistency in treating NaN-results?
As a side note, Splus makes sin(x) NA, with a warning, for
abs(x)>1.6*2^48 (about
4.51e+14) because more than half the digits are incorrect in sin(x)
for such x. E.g.,
in R we get:
> options(digits=16)
> library(Rmpfr)
> sin(4.6e14)
[1] -0.792253849684354
> sin(mpfr(4.6e14, precBits=500))
1 'mpfr' number of precision 500 bits
[1]
2015 Nov 26
2
Inconsistency in treating NaN-results?
This question is more out of curiosity than a complaint or suggestion, but
I'm just wondering.
The behavior of R on calculations that result in NaN seems a bit
inconsistent.
# this is expected:
> 0/0
[1] NaN
# but this gives a warning
> sin(Inf)
[1] NaN
Warning message:
In sin(Inf) : NaNs produced
# and this again does not
> exp(NaN)
[1] NaN
Conceptually, I like to think that R
2024 Sep 05
2
BUG: atan(1i) / 5 = NaN+Infi ?
atan(1i) -> 0 + Inf i
complex(1/5) -> 0.2 + 0i
atan(1i) -> (0 + Inf i) * (0.2 + 0i)
-> 0*0.2 + 0*0i + Inf i * 0.2 + Inf i * 0i
infinity times zero is undefined
-> 0 + 0i + Inf i + NaN * i^2
-> 0 + 0i + Inf i - NaN
-> NaN + Inf i
I am not sure how complex arithmetic could arrive at another answer.
I advise against messing with infinities... use atan2() if you don't
2003 Oct 02
4
using a string as the formula in rlm
Hi,
I am trying to build a series of rlm models. I have my data frame and
the models will be built using various coulmns of the data frame.
Thus a series of models would be
m1 <- rlm(V1 ~ V2 + V3 + V4, data)
m2 <- rlm(V1 ~ V2 + V5 + V7, data)
m3 <- rlm(V1 ~ V2 + V8 + V9, data)
I would like to automate this. Is it possible to use a string in place
of the formula?
I tried doing:
fmla
2024 Sep 05
1
BUG: atan(1i) / 5 = NaN+Infi ?
Dear Bert,
These behave like real divisions/multiplications:
complex(re=Inf, im = Inf) * 5
# Inf+Infi
complex(re=-Inf, im = Inf) * 5
# -Inf+Infi
The real division / multiplication should be faster and also is well behaved. I was expecting R to do the real division/multiplication on a complex number. Which R actually does for these very particular cases; but not when only Im(x) is Inf.
2004 Aug 26
1
EM norm package (NA/NaN/Inf in foreign function call (arg 2))
Greetings!
I am bootstrapping and I am using EM in the norm package to fill in missing
data for a financial time series with each step of the loop. For the most
part EM works fine for me, but the following error message is guaranteed
before I hit the 200th scenario:
Iterations of EM:
1...2...3........348...349...Error: NA/NaN/Inf in foreign function call
(arg 2)
The following code should