similar to: Problem with hist(x, prob=T) (PR#947)

Hi, I am using the following R version: > R version 2.4.1 (2006-12-18) > Copyright (C) 2006 The R Foundation for Statistical Computing > ISBN 3-900051-07-0 I believe I found a bug in the 'hist' function, when 'probability=TRUE'. I looked in the archives and I came across problems with the 'hist' functions (e.g., bug PR# 944, posted in 2001), however, a

In the following, 'probability=T' is ignored, i.e. the vertical axis is labelled in frequencies. However hist(islands, freq=F) achieves the desired effect. > data(islands) > hist(islands, probability=T) # Vertical axis gives frequencies > hist(islands, freq=F) # Expected result --please do not edit the information below-- Version: platform = i386-pc-mingw32

I was using the hist() function to create a frequency table of some network traffic data. The range in values is rather large, from 0 till just under 10e12. Calling hist(x, breaks=c(0,1000,1e6,1e9,1e12),plot=F,freq=T) causes hist() to return : $breaks [1] -1.0000e+05 1.0100e+05 1.1000e+06 1.0001e+09 1.0000e+12 Is this recalculation of the breaks by hist() intended? Maarten van Gelder.

Full_Name: Stephan Schlueter Version: 1.9.0 OS: Submission from: (NULL) (217.184.109.24) During my studies, I found a fault in the hist()-function: If you have a vector x with values around zero and also bigger than 10,000,000 , there will be a shift of -max(x)/10,000,000 in the hist-datas. See my example: x<-runif(10000) hist(x,breaks=c(seq(-3,3,0.1)),prob=TRUE) #everything ok, but

Hi, I have a couple of observations, a question or two, and perhaps a suggestion related to the plotting of density on the y-axis within the hist() function when freq=FALSE. I was using the function and trying to develop an intuitive understanding of what the density is telling me. After reading through this fairly helpful post:

Hello! Up to now I have been using hist() to display the distributions. Howevere, I noteiced strange numbers on y (vertical) axis, if I used probability = T or freq = F option. I thought it is a bug and launched the R-bug system and found some posts on that matter. Brian Ripley responded to one, that one should look at truehist() for that. Ok I can use truehist() if I want to see the ratios

Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like

Hello, I'm trying to plot a historgram with a density plot superimposed: hist(x, seq(-1, 1, by = 0.1), prob = T, col = "blue") lines(density(x, bw = 0.1)) rug(x) I don't want to add rug(x) but the histogram will not be plotted unless rug(x) is there. It does not work if the "hist" line alone is present. Can you help? Thanks, Kim [[alternative HTML version

Hi all I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong... > hist.Date(dt_cycles) Error: couldn't find function "hist.Date" > hist.date(dt_cycles) Error: couldn't find function "hist.date" > cycles [1] 7 1

Can someone help me with a misunderstanding I'm having with hist? I expected, from the example below, that the number of bins would always be 10 and the length of the counts array the same. According to the help section 'breaks' can be a integer indicating the number of bins. From the example below, the number of bins (length of the counts array) varies. Am I wrong in expecting the

Hello Guys, I would like help in script R when I try to plot the histogram appears the error: Erro em hist.default some 'x' not counted; maybe 'breaks' do not span range of 'x' I using a file with more 1000 datas (vector) hist(dados[[1]], seq(0, 20, 0.5), prob=TRUE, xlab="chuva (mm/dia)",ylab="frequência", main="", cex.lab=1.6,

Full_Name: Alex Deckmyn Version: 2.4.0 OS: linux Submission from: (NULL) (193.190.63.62) specifying the "right" option in hist results in a warning when plot=F. The option is taken into account correctly, but a warning is issued anyway. When plot=T there is no warning. > hist(c(1,1.5),breaks=0:4)$counts [1] 1 1 0 0 > hist(c(1,1.5),breaks=0:4,right=T)$counts [1] 1 1 0 0 >

Dear all, I am a newbie in R and could not find help on this problem. I am trying to plot an histogram with probabilities in the y axis. This is the code I am using: #TLC uniform n=30 mi=1; mx=6 nrep=1000 xbar=rep(0,nrep) for (i in 1:nrep) {xbar[i]=mean(runif(n,min=mi,max=mx))} hist(xbar,prob=TRUE,breaks="Sturges",xlim=c(1,6),main=paste("n =",n), xlab="Média",

Dear developers, the current implementation of hist.default() calculates 'density' (and 'intensities') as dens <- counts/(n*h) where h has been calculated before as h <- diff(fuzzybreaks) which results in 'fuzzy' values for the density, see e.g. > tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE) > print(tmp$density,digits=15) [1]

Full_Name: Reinhold Koch Version: 1.6.1 OS: redhat 8.0 Submission from: (NULL) (131.152.84.111) I came across rather weird behavior of the breaks in hist: hist(1:3) gives the expected result, besides an unnecessary gap between 2nd and 3rd column hist(1:4) always merges up the first two columns, also if I resort to hist.default(1:4,breaks=1:4). hist.default(1:4, include.lowest=F) gives an

Hi, This is a very basic question, but I would like to undestand hist(). I thought that the hist( , freq=FALSE) should provide the relative frequencies (probabilities), and so they should sum 1, however: set.seed(2) ah <- hist(rnorm(100), freq=F) sum(ah$intensities) [1] 2 set.seed(2) bh <- hist(rlnorm(100), freq=F) sum(bh$intensities) [1] 0.4999996 I'm getting similar figures with

Hi there, # Consider the following example: A = 19 B = 20 A< B A==B hist(c(1:15,B,50),breaks=c(0,15,A,50),plot=F)$count hist(c(1:15,A,50),breaks=c(0,15,B,50),plot=F)$count # I was expecting the same results with the following values of A and B: A = 19.6019203953960 B = 19.6019204365543 A< B A==B hist(c(1:15,B,50),breaks=c(0,15,A,50),plot=F)$count# wrong

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Hi all, A friend send me a question on why does this: x<-rpois(100,1) sum( hist(x)$density ) Gives out "2" I tried this: sum( hist(x, freq =T)$density ) It didn't help. Then he came back with the following insight: # with breaks b<-c(0,0.9,1:8) sum(hist(x,breaks=b)$density) # Much more then 2 # but if we add weights according to the interval length

The following code is giving me problems. I want to export densities of a distribution to a csv file. At the bottom of the code I use the hist function to generate the densities. But hist is returning values greater than 1. I don't understand, why. Any help you can supply is greatly appreciated. # Set word path dir<-"~/Research/MR Distribution Analysis/" setwd(dir)