similar to: replicating lists

Hi everyone, Is there any reason why we should not automatically coerce a factor supplied as an argument to col in a plotting function? The following modification (to R-1.6.1) seems pretty harmless > plot.xy function (xy, type, pch = 1, lty = "solid", col = par("fg"), bg = NA, cex = 1, ...) { if (is.factor(col)) col <- codes(col)

Hi Everyone, I have modified my version of R-1.4.1 to include choleski with pivoting (like in Splus). I thought R-core might consider including this in the next version of R, so I give below the steps required to facilitate this. 1. Copied Linpack routine "dchdc.f" into src/appl 2. Inserted line F77_SUBROUTINE(dchdc) in src/appl/ROUTINES 3. Inserted "dchdc.f" into

Hi everyone, There is no mention in ?new.env (R-1.6.0) of what the effect of setting the hash argument of new.env() actually does. What does it mean in performance terms to say that "the environment will be hashed"? Thanks, Jonathan. -- Jonathan Rougier Science Laboratories Department of Mathematical Sciences South Road University of Durham

Filed as a bug, as suggested by Brian R., Jonathan. Jonathan Rougier Science Laboratories Department of Mathematical Sciences South Road University of Durham Durham DH1 3LE tel: +44 (0)191 374 2361, fax: +44 (0)191 374 7388 http://www.maths.dur.ac.uk/stats/people/jcr/jcr.html ---------- Forwarded message ---------- Date: Wed, 11 Apr 2001 09:15:26 +0100

I find this a bit puzzling ... > solve(matrix(c(5, 2, 3, 1), 2, 2), c(Inf, 3)) [1] NaN Inf > solve(matrix(c(5, 2, 3, 1), 2, 2)) %*% c(Inf, 3) [,1] [1,] -Inf [2,] Inf I would expect the answer to be c(-Inf, Inf), so why has the -Inf been replaced by NaN in solve? Cheers, Jonathan. --please do not edit the information below-- Version: platform = sparc-sun-solaris2.7 arch = sparc

Hi everyone, I encountered unexpected behaviour when calling "missing" within a "local" environment, namely fred <- function(x, y) { x <- as.vector(x) local({ dontwantme <- 1:100 if (missing(y)) print("No \"y\" today") }) x } whereupon I get > fred(1:10) Error in eval(expr, envir, enclos) : "missing" illegal use of

This is the result of my make check, could anyone help me out on this one? Formats: text example running code in 'base-Ex.R' ...*** Error code 1 make: Fatal error: Command failed for target `base-Ex.Rout' Current working directory /apps/R/R-1.6.0/tests/Examples *** Error code 1 make: Fatal error: Command failed for target `test-Examples-Base' Current working directory

In the optim() documentation, the control parameter "maxit" says "There is no other stopping criteria." That should be "are", or "criterion" ... While I'm at it -- poking at the code a little bit, it looks as if the initial simplex is set from the initial point by displacing each parameter value by max(0.1,0.1*pmax(fabs(Bvec))), where Bvec is the

Hi all, is it possible to create a multidemensional list? Haven't found anything in the list() help page. Thanks, Sven -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !)

Dear list I have a simple question that I have a mental block on: Having used a loop (from i = 1 to n) to assign some numerical values to row.list[[i]] e.g. row.list[[3]]= 0 1 I am wanting to combine the output into a simple matrix. for example, if I combine the output from persons 1 to 3 into a matrix, I thought I could do : h<-rbind(row.list[[1]]:row.list[[3]]) However, I get the

Okay, I stumped. I'm trying to build a matrix or data.frame that consists of values by group. For example, resid, group 574 0.536196370873122 E 575 0.93191093696265 E 576 -1.27116094894117 A 577 -1.05159666055027 A 578 0.398273458301184 D 579 0.586373126102573 E 580 0.806575304513802 E 581 0.897258393118338 E 582 0.342393324256838 D 583 0.781245511773227 E I

I was surprised to find that the variance of a scalar, using var(), is NA. Surely this should be zero? Cheers, Jonathan. --please do not edit the information below-- Version: platform = sparc-sun-solaris2.7 arch = sparc os = solaris2.7 system = sparc, solaris2.7 status = Patched major = 0 minor = 99.0 year = 2000 month = February day = 9 language = R Search Path: .GlobalEnv,

Dear R users, Suppose i have an A square matrix rxr. I want to obtain a block matrix B (pxr,pxr) where the p diagonal blocks are A and the others values are 0. I would like to do something like : diag(A,ncol=pr, nrow=pr) How can i do it ?? Thanks in advance, Olivier. -- -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- Olivier MARTIN PhD student phone: (33) 04

Hello all - If I want to put mean value of a matrix into the title or subtitle of a graph, how would I do this? For example, in a set of commands like below, > m.mean<-mean(m) > gplot (m, thresh=m.mean) > title (main="A2. Block Density of Matrix m\nplotted based on MDS", + sub="lines below mean density (**0.435**) suppressed") I want to ask [R] to put the

I'm just back from a computer practical where we ran into > "f" <- function(x) 2(x^2) # for 2 * x^2 This definition was taken as legitimate, although using the function generated the error message > f(3) Error in f(3) : attempt to apply non-function Am I right in thinking that in prevous versions of R this definition would have been declared as a syntax error? Surely a

The "bug" is that it doesn't print anything; one might argue that this is not a bug, since such an array *is* empty, but I don't buy that argument. It *does* print if #{columns} (= last dimension) > 0 : > array(NA,dim=c(2,0)) > array(NA,dim=c(2,1,0)) > array(NA,dim=c(0,2)) [,1] [,2] > array(NA,dim=c(0,2,1)) , , 1 [,1] [,2] >

Dear R guru's, I'd like to sort the columns of a matrix according to the elements in the first row, and in case of a tie according to the second row, etc. In case of a 3xn matrix woppa, something like colorder _ order(woppa[1,], woppa[2,], woppa[3,]) I just cannot seem to find a way to do this for a variable number of rows, e.g. if woppa has 10 or 15 rows I now manually cut and paste to

Is there a quick way to make boxplots groups by two variables? By that I mean, that if x axes have values ("A","B","C"), than at each value there would be a few boxplots each for a value of second variable (say ("1","2","3")). Thank You. -- Vadim Kutsyy http://www.kutsyy.com vadim at kutsyy.com The University of

Is there a quick way to make boxplots groups by two variables? By that I mean, that if x axes have values ("A","B","C"), than at each value there would be a few boxplots each for a value of second variable (say ("1","2","3")). Thank You. -- Vadim Kutsyy http://www.kutsyy.com vadim at kutsyy.com The University of

Is there any routine to obtain a g-inverse of a matrix in R or S-PLUS? Tapio Nummi University of Tampere Finland -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: