similar to: invalid regular expression after many grep's (PR#691)

How about this (I'm showing it as a pipe because it's easier to read that way): library(magrittr) "f 147/1315/587 2820/1320/587 3624/1321/587 1852/1322/587" %>% ? strsplit(' ') %>% ? unlist %>% ? sub('^[^/]*/*','',.) %>% ? sub('^[^/]*/*','',.) %>% ? paste(collapse = ' ') Georges Monette -- Georges Monette,

Hi Duncan, why not split on / and take the correct elements? It is not as elegant as regex but could do the trick. Best, Ulrik On Mon, 9 Oct 2017 at 17:03 Duncan Murdoch <murdoch.duncan at gmail.com> wrote: > I have a file containing "words" like > > > a > > a/b > > a/b/c > > where there may be multiple words on a line (separated by spaces). The

Hi all, > diff_operator <- "\\(" > strsplit(cond, diff_operator) [[1]] [1] "andsin" "log_angle_1_4)" > diff_operator <- "\\sin(" > strsplit(cond, diff_operator) Error in strsplit(cond, diff_operator) : invalid regular expression '\sin(', reason 'Missing ')'' When I am going to split with "("

I have a file containing "words" like a a/b a/b/c where there may be multiple words on a line (separated by spaces).? The a, b, and c strings can contain non-space, non-slash characters. I'd like to use gsub() to extract the c strings (which should be empty if there are none). A real example is "f 147/1315/587 2820/1320/587 3624/1321/587 1852/1322/587" which

Hi... I have come upon a problem with a regular expression which causes base-R to freeze. I have reproduced the phenomenon on several machines running R under Windows 10, and also under OSX on different Apple MACs. The minimal example is:- Oldterm is a vector of characters, e.g. "A", "B", "A", "*", "B" The regular expression is

Dear all, Is there a good way of doing the following conversion: [YYYY]-[MM]-[DD] [Time] [Day] [Name][Integer].[Extention] to become C:\test\[Name]\[YYYY]-[MM]-[DD] [Time] [Day]\[YYYY]-[MM]-[DD] [Time] [Day] [Name][Integer].[Extention] i.e. these 2009-04-10 1400 Fri Foo1.txt 2009-04-10 1400 Fri Universities2.txt 2009-04-10 1400 Fri Hitchhikers Guide To The Galaxy42.txt will become

can someone show me how to use a regular expression to break the string at the bottom up into its three components : (-0.791,-0.263] (-38,-1.24] (0.96,2.43] I tried to use strplit because of my regexpitis ( it's not curable. i've been to many doctors all over NYC. they tell me there's no cure ) but it doesn't work because there also dots inside the brackets. Thanks.

I tried this on a Linux (Ubuntu) server invoking R from the command line and the result was the same, except that I could kill the R session from another terminal window. From: Rui Barradas <ruipbarradas at sapo.pt> To: Chris Triggs <cm.triggs at auckland.ac.nz>; "r-devel at r-project.org" <r-devel at r-project.org> Cc: Thomas Lumley <t.lumley at

Dear R People: I have a data frame with the following column names: > names(funky) [1] "UHD.1" "UHD.2" "UHD.3" "UHD.4" "L..W..1" "L..W..2" "L..W..3" [8] "L..W..4" "B..W..1" "B..W..2" "B..W..3" "B..W..4" "W..B..1" "W..B..2" [15]

The issue seems related to R bug report 15012: https://bugs.r-project.org/bugzilla3/show_bug.cgi?id=15012 As mentioned in the comments there, a pull request to the TRE library has recently been made, but I don't know about its status. Daniel ________________________________________ Von: R-devel <r-devel-bounces at r-project.org> im Auftrag von Tomas Kalibera <tomas.kalibera at

Hi, Is there a way in R to get the string which matches the expression, where the expression is a substring of the parent string. Lets say, I have $i <- "transcript:ENST0000112334 pid:ENSP000012345" What I need is the string "pid:ENSP000012345" from $i using the query "ENSP". Appreciate your comments. Praveen Surendran School of Medicine and

Hello all, Let's say I have a character string "Race-ethnicity-----coding information" I want to extract all text before the multiple dashes, including the word "ethnicity." I wrote a handy function to extract the first matched text: grepcut <- function(pattern,x){ start.and.length <- regexpr(pattern,x) substring(x,start.and.length,start.and.length

Computer Friends, with the following example lines: [107] "98-610: Cell type: S; Surv(months): 6; STATUS(0=alive, 1=dead): 1" [108] "99-625: Cell type: S; Surv(months): 21; STATUS(0=alive, 1=dead): 1" i want to be able to isolate the number of months of survival for each row. is there a regular expression that can find the first instance of a ";", delete

If I have a text with 7 words per line and I would like to put first and second word joined in a vector and the rest of words one per column in a matrix how can I do it? First 2 lines of my text file: "2008/12/31 12:23:31 numero 343.233.233 Rodeo Vaca Ruido" "2010/02/01 02:35:31 palabra 111.111.222 abejorro Rodeo Vaca" Results: Vector: 2008/12/31 12:23:31 2010/02/01 02:35:31

Hi R, Again struck with regular expressions... Suppose, S=c("World_is_beautiful", "one_two_three_four","My_book") I need to extract the last but one element of the strings. So, my output should look like: Ans=c("is","three","My") gsub() can do this...but wondering how do I give the regular expression....

Hi, I guess the backslash should not be used as the separator for strsplit() in compareVersion(), because the period in [.] is no longer a metacharacter (no need to "escape" it using a backslash): https://github.com/wch/r-source/blob/trunk/src/library/utils/R/packages.R#L866-L867 > compareVersion function (a, b) { .... a <- as.integer(strsplit(a, "[\\.-]")[[1L]])

I have strings of the form TICKER.GGG.XXXXXX.dat but GGG is not always three characters so I can't use substr to pull it out of the string. Could someone tell me how to use sub to pull out the GGG but more generally the string between the dot after the R in TICKER and the next dot. I still don't have a very good understanding of regular expressions but I'm trying to get that

Hi, just curious, but does anyone know the source/reason of observing the following error on OSX but not on WinXP and Linux? I've tried with a few different versions of R (v2.5.1, v2.6.1, v2.6.2, v2.7.0devel). The locale does not seem to affect the error, i.e. I've tested a few different and it is still only OSX that gives the error but not the other two. > regexpr("[a-Z]",

Dear all, Lets say I have the following: > x <- c("Eve: Going to try something new today...", "Adam: Hey @Eve, how are you finding R? #rstats", "Eve: @Adam, It's awesome, so much better at statistics that #Excel ever was! @Cain & @Able disagree though :(", "Adam: @Eve I'm sure they'll sort it out :)", "blahblah") > x [1]

Dear r-help members, I have a number in the form of a string, say: a<-"-01020.909200" I'd like to extract "1020." as well as ".9092" Front<-grep(pattern="[1-9]+[0-9]*\\.", value=TRUE, x=a, fixed=FALSE) End<-grep(pattern="\\.[0-9]*[1-9]+", value=TRUE, x=a, fixed=FALSE) However, both strings give "-01020.909200", exactly