similar to: strsplit (PR#424)

Try the following with R 63.3: test <- function(z){ ch1 <- deparse(z,width=500) ch <- NULL for(i in 1:length(ch1))ch <- paste(ch,ch1[i],collapse=" ") a <- gsub("(\\[(0|1|2|3|4|5|6|7|8|9|:|,)+\\])|([][+*/^():!<>%&|~,{}\"\\\=-])|( [0-9]+)|(^[0-9]+)"," ",ch) print("here") strsplit(a," ") } test(glm) Jim

1. Try the following in 63.3 y <- rnorm(20) y1 <- y[2:20] y2 <- y[1:19] summary(glm(y1~offset(y2))) summary(glm(y1-y2~1)) Both are the same model, but the first gives the wrong s.e. I don't believe this was a problem in 63.2 2. Besides the strsplit buffer, there appear to be other memory problems causing seg faults. With vsize 12M in batch, I accumulated 9 glm objects in memory,

Full_Name: Charles Dupont Version: 2.2.0 OS: linux Submission from: (NULL) (160.129.129.136) when strsplit("", " ") returns character(0) where as strsplit("a", " ") returns "a". these return values are not constiant with each other. Charles Dupont

With 0.63.3, try test <- function(){ fn <- function(a) print("hello") print(is.function(fn)) print(names(formals("fn")))} test() if fn is not quoted in the last line of test, it works properly. test <- function(){ fn <- function() print("hello") formals(fn) <- alist(a=,b=) return(fn)} formals(test()) now try with line 3 of test changed to

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When I attempt to install the online help for R.99 on Intel RH5.2, I get the following message Substitution loop at /usr/local/src/R/etc/Rdconvlib.pl line 1589, <rdfile> chunk 171 and it stops after a few files. Each time I rerun it, it gets a bit further and gives a different number at the end. I commented out the line 1589 and it works.

When I attempt to install the online help for R.99 on Intel RH5.2, I get the following message Substitution loop at /usr/local/src/R/etc/Rdconvlib.pl line 1589, <rdfile> chunk 171 and it stops after a few files. Each time I rerun it, it gets a bit further and gives a different number at the end. I commented out the line 1589 and it works.

Hello - I cannot get to www.alpha.luc.ac.be/~jlindsey/rcode.html<http://www.alpha.luc.ac.be/%7Ejlindsey/rcode.html>to obtain and install the repeated library for use of glmm(). Is the web page not active? Can you give me an alternative location to obtain the repeated library? Thank you, Becky Parker [[alternative HTML version deleted]]

Dear all, I want to use string split to parse column names, however, I am having some errors that I don't understand. I see a problem when I try to rbind the output from strsplit. please let me know if I'm missing something obvious, thanks, alison here are my commands: >strsplit<-strsplit(as.character(Rumino_Reps_agreeWalign$geneid),"\\.") >

In R0.64.0, try as.numeric(is.na(c(NA,NA,1))) as.numeric(c(T,T,F)) Jim -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or "[un]subscribe" (in the "body", not the subject !) To: r-devel-request@stat.math.ethz.ch

strsplit() is a convenient way to get a list of items from a string when you have a regular expression for what is not an item. E.g., > strsplit("1.2, 34, 1.7e-2", split="[ ,] *") [[1]]: [1] "1.2" "34" "1.7e-2" However, sometimes is it more convenient to give a pattern for the items you do want. E.g., suppose you want to pull

Hi all, Came across an error in ?strsplit in the details section: Details: Arguments 'x' and 'split' will be coerced to character, so you will see uses with 'split = NULL' to mean 'split = character(0)', including in the examples below. I caught myself trying to use strsplit() on a factor and the coercion on 'x' is not done. According

Description: Split the Strings in `x' into substrings according to the presence of substring `split' within them. -------------------- > strsplit("acbdefgSPLIThigkilmnSpPqrst","SPLIT") [[1]] [1] "acbdefg" "higkilmn" "p" "qrst" -------------------- Apparently, it will Split the Strings in `x' into

Hi, As show in the code below, strsplit can be applied to a matrix but not a data.frame. I don't understand why R is designed in this way. Can somebody help me understand it? How to split all the strings in x$y? x=data.frame(x=1:10,y=rep("abc",10)) strsplit(x$y,'b') #Error in strsplit(x$y, "b") : non-character argument y=cbind(1:10,rep("abc",10))

\b is word boundary. But, unexpectedly, strsplit("dia ma", "\\b") splits character by character. > strsplit("dia ma", "\\b") [[1]] [1] "d" "i" "a" " " "m" "a" > strsplit("dia ma", "\\b", perl=TRUE) [[1]] [1] "d" "i" "a" " "

Hi, A pared down version of the dataset I'm working with: edm<-read.table(textConnection("WELLID X_GRID Y_GRID LAYER ROW COLUMN SPECIES CALCULATED OBSERVED w301_3 4428. 1389 2 6 18 1 3558 6490. w304_12 4836. 6627 2 27 20 1 3509 3228. 02_10_12080 3.6125E+04 13875 1 56 145 1

Hi there, I have a problem about lapply, strsplit, and accessing list elements, which I don't understand or cannot solve: I have e.g. a character vector with three elements: x = c("349/077,349/074,349/100,349/117", "340/384.2,340/513,367/139,455/128,D13/168", "600/437,128/903,128/904") The task I want to perform, is to generate a list,

Full_Name: John Brzustowski Version: R-devel-trunk, R-2.4.0 OS: linux, gcc 4.0.3 Submission from: (NULL) (206.248.157.184) This isn't a bug, but an easily-remedied performance issue. SYMPTOM > for (i in 1000 * (1:20)) { y <- paste(rep("asdf", times=i), collapse=" ") t <- system.time(strsplit(y, " ", fixed=TRUE)) cat(sprintf("i=%5d

Hi, I tried to use strsplit for separating a string with || like strsplit(string,"\\||") but it returned each single character was separated. For example: strsplit("a||bc","\\||") [[1]] [1] "a" "" "" "b" "c" where I want the result to be "a" and "bc". Any ideas? Thanks! Best,

Dear R People: I am trying to split a character vector into a set of individual letters: Ideal: x3 <- c("dog") "d" "o" "g" I tried the following: > strsplit(x3) Error in strsplit(x3) : argument "split" is missing, with no default > strsplit(x3,1) [[1]] [1] "dog" I know that this is incredibly simple, but what am I doing