similar to: Preliminary version of ts package

Dear helpers, I am trying to write a function to return prediction values using package ts. I have written three different versions since I am not sure what's wrong with my func2. func and func1 return the same results.But func1 and func2 don't. In particular, the only difference between "func1" and "func2" is the function variable name being y and data, respectively.

Marcus Eger <marcus.eger@physik.uni-marburg.de> writes: > > time(sqrt(arrts)) > Time Series: > Start = c(1, 1) > End = c(5, 1) > Frequency = 1 > [1] 1 2 3 4 5 Looks like a bug... > ---------------------------------------------------------------------------- > 2. (At least) boolean indexing with matrices does not seem to work > properly: >

This seems like a FAQ, but I can't figure it out. I have a mv ts object: R > tsp(pg) [1] 1982 2003 1 R > dim(pg) [1] 22 12 and a univariate ts: R > tsp(rw) [1] 1690 1996 1 Yet, when I try to intersect them: R > tsp(ts.intersect(rw, pg)) [1] 1982 2176 1 the process goes awry. How to I get rw and pg to be one ts that runs from 1982 to 1996 and has 13 univariate time

I have a suggestion for kernapply for ts objects. When we choose the option circular=F, the returned series don't have the correct dates. The removed dates are all at the beginning instead of half at the beginning and half at the end. It is particularly useful when we need to smooth the series (or remove a trend using a filter) before estimating a model (like in macroeconomics) or simply

I'm trying to convert a column of a table into a ts object. The data is monthly, so I want the ts frequency to be 12. I did this ... > filings.ts = as.ts(Filings.100K, frequency=12) > filings.ts Time Series: Start = 1 End = 311 Frequency = 1 [1] 246.9336 305.6789 ... ... > tsp(filings.ts) [1] 1 311 1 > tsp(filings.ts) <- c(1,311,12) Error in attr(x, "tsp")

Paul wrote to R-devel : PaulG> ts() is giving me problems on Solaris: PaulG> R : Copyright 1999, The R Development Core Team PaulG> Version 0.64.0 (April 8, 1999) PaulG> ... >> z <- ts(matrix(1:20,10,2), start=c(1969,1), frequency=12) >> max(abs(z-z)) PaulG> Error: invalid time series parameters specified >> traceback()

Hi all. Currently, if you try: > lag.plot(1:10) you get superposed labels '1' and '10'. Things go worse in more extreme cases: x <- ts(1:10) x1 <- lag(x, 4) plot(x1, x) This is due to a mistake in plot.ts. My suggestion is the following really minimal patch to plot.ts: @@ -530,7 +530,7 @@ plot.ts <- text(xy, labels =

Thanks for the very detailed explanation. I did not create the series using structure(), that was the result of dump() on an intermediate object created within tsdisagg::ta(), which is where I found the error in the first place. ta() indeed manipulates .Tsp directly, rather than using ts. I guess this is a bug in tsdisagg then. Thanks! -- Andrea Altomani On Sat, Sep 2, 2017 at 12:31 AM

can you recommend a good manual for R that starts with a data set and gives demonstrations on what can be done using R? I downloadedR Langauage definition and An introduction to R but haven't found them overly useful. I'd really like to be able to follow some tutorials using a dataset or many datasets. The datasets I have available on R are Data sets in package 'datasets':

R version 2.12.0, 64 bit on Windows. Here is a short script that illustrates the problem: library(tseries) library(xts) setwd('C:\\cygwin\\home\\Ted\\New.Task\\NKs-01-08-12\\NKs\\tests') x = read.table("quotes_h.2.dat", header = FALSE, sep="\t", skip=0) str(x) y <- data.frame(as.POSIXlt(paste(x$V2,substr(x$V4,4,8),sep=" "),format='%Y-%m-%d

I'm probably apporaching this all wrong to start but.... Suppose I have a monthly time series and I want to compute the mean of months 6,7, and 8. I want to plot the original time series and the seasonal time series, one above the other. When I do that as below the time series don't line up for reasons that are obvious. How can I change the base of the seasonal time series so I can make

The following seems confused (0.65 snapshot) > x <- ts(1:20) > window(x, 1, 1) Time Series: Start = c(1, 1) End = c(1, 1) Frequency = 1 [1] 1 Warning message: Not returning a time series object in: [.ts(x, i) (it of class ts, as the print method shows). Under 0.64.2 it is even more confusing: > x <- ts(1:20) > window(x, 1, 1) Warning: Not returning a time series object

On Fri, 1 Sep 2017, Andrea Altomani wrote: > I should have formulated my question in a more specific way. > > 1. I suspect this is a floating point precision issue. I am not very > knowledgeable about R internals, can someone else confirm it? Yes. If you represent a series with increment 1/12 it depends on how you do it. As a simple example consider the following two descriptions

{all recent versions of R} Problem / design bug : diff.default() doesn't deal with "ts" objects properly, diff.ts() does, but that is only available from package "ts" where as the constructor function ts() is in base. It's not sufficient to just move diff.ts() to package base, since it relies itself on lag & lag.default which are also only in package ts.

Dear R-users, I am facing a trivial problem when trying to parameterise the start date of a time series object. I am working with monthly data (104) performing n-steps-ahead (6) forecasts and using a fixed window size (36). At the end of calculations I have a list that contains 69 forecasts. I have no problems in fixing the window size by parametrization, e.g. k<- control variable in a for

>>>>> On Fri, 02 Jul 1999, Adrian Trapletti <Adrian.Trapletti@wu-wien.ac.at> said: Adrian> There seems to be a problem with plot.ts (R Version 0.64.2) > x<-cbind(1:10,2:11) > x<-as.ts(x) > plot(x) Adrian> Error: subscript (20) out of bounds, should be at most 10 This is definitely a bug --> CC: R-bugs ALL NOTE : This is *not* new

I should have formulated my question in a more specific way. 1. I suspect this is a floating point precision issue. I am not very knowledgeable about R internals, can someone else confirm it? 2. Should this be considered a bug or not, because it is "just a precision issue"? Should I report it? 3. How can it happen? From a quick review of ts.R, it looks like the values of the time

Dear all, I think I have found a buglet in plot.ts plot.ts(x=1,type="n") # correct: does not show the plot plot.ts(x=1,y=1,type="n") # not correct: does show the plot I did not investigate the problem in depth but it could be related to the switch xy.labels, in fact plot.ts(x=1,y=1,type="n",xy.labels=TRUE) # does show the plot

I think this is another one of the same kind of bugs in ts: Version 0.64.1 (May 8, 1999) ... > z <- ts(matrix(1:20,10,2), start=c(1969,1), frequency=12) > (z > 5) | (z < 2) Error: invalid time series parameters specified > Paul -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read

Hi all- I am trying to use the time function for ts class objects and do not understand the return value. I want to use it to set up a time trend in arima fits. It does not seem to return a correct linear sequence that matches the underlying time series. I am running: R version 2.8.1 (2008-12-22). For example: R> ## create a time series R> x <- rnorm(24) R> (xts <-