similar to: hist()

Hi All, When carrying out hist(samples,breaks=50,probability=TRUE), the column values are considerably greater than 1, which seams very unreasonable. The plot is attached. I think the column value of the hist plot should correspond to x$counts/sum(x$counts) (x=hist(samples,breaks=50,probability=TRUE)). The size of data is a little bit larger, causing failure of uploading. If you need the

Hello, I have a problem with the hist() function and showing densities. The densities sum to 50 and not to 1! I use R version 2.9.1 (2009-06-26) and I load the seqinR library. My data is the following vector: [1] 0.1400000 0.2000000 0.2200000 0.2828283 0.1600000 0.1600000 0.3600000 [8] 0.1600000 0.2200000 0.2600000 0.2000000 0.3000000 0.2200000 0.2342342 [15] 0.1800000 0.2200000 0.1600000

Hi all I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong... > hist.Date(dt_cycles) Error: couldn't find function "hist.Date" > hist.date(dt_cycles) Error: couldn't find function "hist.date" > cycles [1] 7 1

A quick question, please. x = c(0.0001, 0.0059, 0.0855, 0.9082) y = c(0.54, 0.813, 0.379, 0.35) where A = 1st set, B = 2nd set, C = 3rd set, D = 4th set respectivley. How do you make hist plot side by side for x & y? i.e. 0.0001 and then to the right 0.54, 0.0059 and then to the right 0.813, etc. thx much [[alternative HTML version deleted]]

Dear developers, the current implementation of hist.default() calculates 'density' (and 'intensities') as dens <- counts/(n*h) where h has been calculated before as h <- diff(fuzzybreaks) which results in 'fuzzy' values for the density, see e.g. > tmp <- hist(1:10,breaks=c(-2.5,2.5,7.5,12.5),plot=FALSE) > print(tmp$density,digits=15) [1]

hello, i need the data from hist() but i do not want the plot. e.g. z=hist(data)$counts #returns absolute frequency but when i execute this command the plot occurs also. is it possible to suppress the plot? many thanks, best regards gg -- --------------------------------------------------- Gottfried Gruber mailto:gottfried.gruber at terminal.at www: http://gogo.sehrsupa.net

Full_Name: Alex Deckmyn Version: 2.4.0 OS: linux Submission from: (NULL) (193.190.63.62) specifying the "right" option in hist results in a warning when plot=F. The option is taken into account correctly, but a warning is issued anyway. When plot=T there is no warning. > hist(c(1,1.5),breaks=0:4)$counts [1] 1 1 0 0 > hist(c(1,1.5),breaks=0:4,right=T)$counts [1] 1 1 0 0 >

Hello all, i announce you the gfxboot COMBOOT module which is written in assembler. Since i didn't find as much spare time as i have hoped last weekend it is far from complete. Nevertheless the module is able to interact with the bincode ([1] and [2]) in the bootlogo cpio archive from the openSUSE 10.2 mini cd. So far it is able to call the bincode gfxboot code and setup some menu entries.

On Sun, 11 Dec 2005 clausen at econ.upenn.edu wrote: > Full_Name: Andrew Clausen > Version: 2.1.0 > OS: Debian GNU/Linux > Submission from: (NULL) (71.242.192.73) > > > Hi, > > When I type > > hist(x, freq=F) > > I get a density function, as I expect. However, if I type > > plot(hist(x, freq=F)) > > then I get the same output as if I had

Hello, I urgently need a histogram of the vector geo1$ds1 but: > hist(geo1$ds1) Error in hist(geo1$ds1) : unused argument(s) ( ...) I can use density, summary, boxplot and stem with this vector but not hist ? Any suggestions ? Thanks in advance, Detlef Groth > density(geo1$ds1) Call: density(x = geo1$ds1) Data: geo1$ds1 (1412 obs.); Bandwidth 'bw' = 0.2805

Full_Name: Fran Rizzardi Version: 0.90.0 OS: Solaris, NT 4.0 Submission from: (NULL) (128.32.135.223) If you use the horiz= option with hist() you get the message: Warning: parameter "horiz" couldn't be set in high-level plot() function. and the plot comes out vertical. The documentation says this option comes from barplot() and it does work correctly in barplot(). This

I have seen that the hist() function plots an histogram of the frequency but I cannot find the value of the object hist that contains theese values... how is possible to get out them? thank you very mutch best regards Manuele -- Manuele Pesenti manuele a inventati.org amicogodzilla a jabber.linux.it http://mpesenti.polito.it

Hi, It seems that hist() has a buggy behavior when breaking over "days". The bug can be reproduced in a few steps: > d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02")) > d$date=as.Date(d$date) > d$date [1] "2009-01-01" "2009-01-02" "2009-01-02" > h=hist(d$date, "days") > h$count [1] 3

Full_Name: Reinhold Koch Version: 1.6.1 OS: redhat 8.0 Submission from: (NULL) (131.152.84.111) I came across rather weird behavior of the breaks in hist: hist(1:3) gives the expected result, besides an unnecessary gap between 2nd and 3rd column hist(1:4) always merges up the first two columns, also if I resort to hist.default(1:4,breaks=1:4). hist.default(1:4, include.lowest=F) gives an

Hi all, A friend send me a question on why does this: x<-rpois(100,1) sum( hist(x)$density ) Gives out "2" I tried this: sum( hist(x, freq =T)$density ) It didn't help. Then he came back with the following insight: # with breaks b<-c(0,0.9,1:8) sum(hist(x,breaks=b)$density) # Much more then 2 # but if we add weights according to the interval length

Running the following lines I got a strange plot from hist function: x<-0:30 hist(x,breaks=31) As you can see, the 0 value appears two times in the plot. The Y axis only presents 1 as the highest value when: hist(x,breaks=62) Nevertheless, it seems to have two bars between 0 and 1. Could someone please explain to me why it is happening? Many thanks in advance!

Can someone help me with a misunderstanding I'm having with hist? I expected, from the example below, that the number of bins would always be 10 and the length of the counts array the same. According to the help section 'breaks' can be a integer indicating the number of bins. From the example below, the number of bins (length of the counts array) varies. Am I wrong in expecting the

Hi, I want to use hist with non-equi-spaced breaks, picked such that the fraction of the data points falling in the cells (defined by 'breaks') is roughly equal accross all cells. Is there such a function that will automatically try to determine the breaks to fullfill this requirement? Something like.. hist( x, br = magic_function_to_pick_breaks()) For example, if x looked like

Hi, This is a very basic question, but I would like to undestand hist(). I thought that the hist( , freq=FALSE) should provide the relative frequencies (probabilities), and so they should sum 1, however: set.seed(2) ah <- hist(rnorm(100), freq=F) sum(ah$intensities) [1] 2 set.seed(2) bh <- hist(rlnorm(100), freq=F) sum(bh$intensities) [1] 0.4999996 I'm getting similar figures with

The command hist(c(2,2,2,4,5,6)) returns a histogram that looks incorrect -- 3 in the bin labeled 2 on the left, but 1 each in the bins labeled 3,4,5 on the left. Thanks! Pam Surko -------------------- > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor