similar to: Pre-built kernel 2.6.20 for CentOS 5?

Can anyone point me at a yum repository containing a CentOS 5 version of bacula? thanks -- Kevin Thorpe

I was just wondering what recommendations you have on migrating a CentOS 5 install between servers? I've done similar in the past by setting up a minimal install in the new server, use tar to copy over the old install and reboot. I was thinking of rsync this time. Is that an acceptable thing to do or have I missed something important? thanks -------------- next part -------------- An

Hi all, I've set SELinux to disabled using the security and firewall widget but I'm still getting a lot of messages in Logwatch.... NULL security context for user, but SELinux in permissive mode, continuing () So it looks like SELinux is still operating. Can anyone tell me how to turn it off completely? It's my development server under my desk so I reallly don't care

Hi all, I have a permissions problem with a samba share which I really can't fathom out. I'm trying to create a fully group writable share. Easy or so I thought. As you can see from my config I am trying all the options to set files group writable, however when I create a file from the client I'm always getting the mode 0644. Does anyone have a clue why? Thanks! client:

Hi all, My only encounter with tape-backup was with Windows 2000. With it, when we backup things using windows' backup tool, it will create a 'catalog', then the catalog contains all the backup operations we do based on date. So, with this we can "append" many backups into one tape. Next time we want to restore a backup, we can choose what date available in that

It looks like you made a copy/paste error below. Your ata.frame should be data.frame. Kevin On 05/04/2018 08:18 AM, Bill Poling wrote: > Good morning. > > Novice usR. Here. > > I am following this string, among many, learning as I go. > > Quick question please? > > I thought that perhaps ata.frame was part of the zoo pkg, b/c when I > searched it came up in

Good morning. Novice usR. Here. I am following this string, among many, learning as I go. Quick question please? I thought that perhaps ata.frame was part of the zoo pkg, b/c when I searched it came up in help? However, evidently not or I am not using it properly. Please advise, thank you. x <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) x2 <- do.call(rbind,

Typo: dat[[z]] should be x[[z]]: x2 <- do.call(rbind, lapply(names(x), function(z) data.frame(type=z, x[[z]]))) x2 type x y 1 A 1 3 2 A 2 4 3 B 5 7 4 B 6 8 David C -----Original Message----- From: R-help <r-help-bounces at r-project.org> On Behalf Of David L Carlson Sent: Wednesday, May 2, 2018 3:51 PM To: William Dunlap <wdunlap at tibco.com>; Kevin E.

Or add the type column first and then rbind: x <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) x2 <- do.call(rbind, lapply(names(x), function(z) data.frame(type=z, dat[[z]]))) ---------------------------------------- David L Carlson Department of Anthropology Texas A&M University College Station, TX 77843-4352 -----Original Message----- From: R-help

Hi Kevin, There is probably a better way, but it can be done in two steps like this temp <- list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) temp <- lapply(names(temp), function(n, temp) { temp[[n]]$type <- n return(temp[[n]]) }, temp = temp) do.call(rbind, temp) On Wed, May 2, 2018 at 1:11 PM, Kevin E. Thorpe <kevin.thorpe at utoronto.ca> wrote: > I suspect

>>>>> David L Carlson <dcarlson at tamu.edu> >>>>> on Wed, 2 May 2018 21:43:52 +0000 writes: > Typo: dat[[z]] should be x[[z]]: > > x2 <- do.call(rbind, lapply(names(x), function(z) > data.frame(type=z, x[[z]]))) > x2 > type x y > 1 A 1 3 > 2 A 2 4 > 3 B 5 7 > 4 B 6 8 > >

> x1 <- do.call(rbind, c(x, list(make.row.names=FALSE))) > x2 <- cbind(type=rep(names(x), vapply(x, nrow, 0)), x1) > str(x2) 'data.frame': 4 obs. of 3 variables: $ type: Factor w/ 2 levels "A","B": 1 1 2 2 $ x : int 1 2 5 6 $ y : int 3 4 7 8 Bill Dunlap TIBCO Software wdunlap tibco.com On Wed, May 2, 2018 at 10:11 AM, Kevin E. Thorpe

If the slope coefficients sum to a constant, the regressors are dependent and so a unique solution is impossible (an infinity of solutions would result). So I think you have something going on that you don't understand and should consult a local statistician to help you formulate your problem appropriately. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people

I suspect this is pretty easy, but I'm having trouble figuring it out. Basically, I have a list of data frames such as the following example: list(A=data.frame(x=1:2, y=3:4),B=data.frame(x=5:6,y=7:8)) I would like to turn this into data frame where the list elements are essentially rbind'ed together and the element name becomes a new variable. For example, I would like to turn the

Hi all, I hope you are doing well? I?m currently using the lm() function from the package stats to fit linear multifactor regressions. Unfortunately, I didn?t yet find a way to fit linear multifactor regressions with constraint coefficients? I would like the slope coefficients to be all inside an interval, let?s say, between 0 and 1. Further, if possible, the slope coefficients should add up to

Ok, and if I would just like to force my slope coefficients to be inside an interval, let's say, between 0 and 1? Is there a way in R to formulate such a constraint regression? Thanks in advance and kind regards, Aljosa Aljosa Aleksandrovic, FRM, CAIA Quantitative Analyst - Convertibles aljosa.aleksandrovic at man.com Tel +41 55 417 7603 Man Investments (CH) AG Huobstrasse 3 | 8808

I'm sure this is simple enough, but an R site search on my subject terms did suggest a solution. I have a numeric vector with many values that I wish to create a factor from having only a few levels. Here is a toy example. > x <- 1:10 > x <-

There is also the package solrad that might do some of this. It is more intended for calculating solar radiation, which is probably not what you want, but may do other things you may find helpful. > On Jan 30, 2024, at 5:44?AM, Enrico Schumann <es at enricoschumann.net> wrote: > > On Tue, 30 Jan 2024, Richard O'Keefe writes: > >> Given >> - UTC timestamp

Folks; I couldn't find anything on my archive of the mailing list on this, and it may just be my mis-understanding, but: When I "ssh machine1 -l user1" as user2 on machine2, if user2 has the same uid on machine1, then user2's name ends up in lastlog, instead of user1's. This is a bit disconcerting when user2 is root, and root isn't allowed to remotely log in on

This is a quadratic programming problem that you can solve using either a quadratic programming solver with constraints or a general nonlinear solver with constraints. See https://cran.r-project.org/web/views/Optimization.html for more info on what is available. Here is an example using a nonlinear least squares solver and non-negative bound constraints. The constraint that the coefficients sum