similar to: count data without NA in certain time intervals and plot it

Displaying 20 results from an estimated 300 matches similar to: "count data without NA in certain time intervals and plot it"

2012 Sep 17
6
count NAs per week
Even though I work with R since a year or so I still struggle with simple problems. I hope someone can help me with this. Been trying for days and am a little frustrated now. I have a data frame somewhat like the one bellow: dattrial<-data.frame(a=c(1,NA,rnorm(4,10)), Week=c(3,3,3,4,4,4)) I want to know how many NAs I have in week 3 and in week 4. -- View this message in context:
2013 Oct 04
2
Subsetting Timestamped data
Hi, I have a data frame, data, containing two columns: one- the TimeStamp (formatted using data$TimeStamp <- as.POSTIXct(as.character(data$TimeStamp), format = "%d/%m/%Y %H:%M") ) and two- the data value. The data frame has been read from a .csv file and should contain 48 values for each day of the year (values sampled at 30 minute intervals). However, there are only
2012 Sep 26
2
average environmental data if AnimalID and Time is duplicated
Hello, I tried for about three hours now to solve this problem but I can't figure it out. I am sure someone knows how do it. At least I hope so. I have a data frame somewhat like this: myframe <- data.frame (ID=c("Ernie", "Ernie", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 09:00", "24.09.2012 10:00",
2012 Nov 27
5
loop with date
Hello, I tried to construct my very first loop today and completly failed :-( Maybe someone can help me? I have a dataframe somewhat like this one: myframe <- data.frame (Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00", "25.09.2012 09:00", "25.09.2012 10:00", "25.09.2012
2012 Nov 09
3
if between 500-600 give 550
I have a data frame somewhat like this: myframe <- data.frame (ID=c(2,3,4,5), Hunger =c(415,452,550,318 )) myframe Now I would like to add a column to the right which summarizes the values for Hunger somewhat to reduce the number of values: If the values for Hunger are between 300-400 I would like to insert the number 350, between 400-500 insert 450 between 500-600 insert 550 Does
2012 Oct 25
2
mean of a value of the last 2 hours
Hello, I have a data frame somewhat like that: myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert", "Bert"), Timestamp=c("24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00"), Hunger=c(1,1,1,2,2,1) ) myframestime <- as.POSIXct (strptime(as.character(myframe$Timestamp),
2017 Aug 19
4
My very first loop!! I failed. May I have some start-up aid?
Dear all, I have a data similar to this: myframe<- data.frame (ID=c("Ernie", "Ernie","Ernie","Ernie"), Timestamp=c("24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", "25.09.2012 10:00"), Longitude=c("8.481","8.482","8.483","8.481"),
2017 Aug 19
0
My very first loop!! I failed. May I have some start-up aid?
Thank you for providing the example code... for the request of running it multiple times it would have helped if you could have confirmed that the example ran through without errors... there were a lot of mistakes in it. Look into using the reprex package to check your example next time. I don't do this kind of analysis... I really don't know what to expect from the functions. The
2012 Dec 17
2
calculate a "rolling mean" including standard deviation
Hello everyone, I have a data frame somewhat like this one: myframe <- data.frame (Timestamp=c( "24.09.2012 06:00", "24.09.2012 07:00", "24.09.2012 08:00", "24.09.2012 09:00", "24.09.2012 10:00", "24.09.2012 11:00", "24.09.2012 12:00",
2008 Jan 02
2
strange behavior of cor() with pairwise.complete.obs
Hi all, I'm not quite sure if this is a feature or a bug or if I just fail to understand the documentation: If I use cor() with pairwise.complete.obs and method=pearson, the result is a scalar: ->cor(c(1,2,3),c(3,4,6),use="pairwise.complete.obs",method="pearson") [1] 0.9819805 The documentation says that " '"pairwise.complete.obs"' only
2004 Jan 23
5
Levels number of a factor object
Hi all! How to retrieve the levels number of a factor object? See this code: groups<-gl(4,10) I want to retrieve the number of levels (4) of my object "groups" I tried groups.levels but this don't work Thanks Laurent Houdusse Analyste Programmeur
2012 Oct 26
0
mean of a value of the last 2 hours using plyr (Thank you)
Hi dear three helpers, Thanks a lot! Your solutions worked great. Again I learned a lot. Tagmarie Am 25.10.2012 18:36, schrieb Felipe Carrillo: > Another option using plyr, > library(plyr) > myframe <- data.frame (ID=c("Ernie", "Ernie", "Ernie", "Bert", "Bert", > "Bert"), Timestamp=c("24.09.2012 09:00",
2010 Sep 10
1
Greek letter included in a character vector
Hello, In the past I have used "expression" to include greek letters in axis labels, but this time I need to include the greek letter as part of a legend. Basically, I need to create the following vector to rename the levels of a factor: c("Interferon-gamma", "IL-10", "IL-5"), where "gamma" obviously needs to be printed as the greek letter
2020 Aug 24
3
(sin asunto)
Creo que el problema se podría simplificar y aún obtener un resultado aceptable si simplemente haces un ajuste lineal en un entorno del punto. Como ya tienes los valores de los puntos de cada curva como dices Carlos, creo que con esa información podrías identificar un entorno adecuado en el cual ajustar linealmente. Cuéntanos como te va, Saludos !! Eric. On 24-08-20 12:52, Carlos Ortega
2017 Jun 03
4
New var
Hi all, I have a data set with time interval and depending on the interval I want to create 5 more variables . Sample data below obs, Start, End 1,2/1/2015, 1/1/2017 2,4/11/2010, 1/1/2011 3,1/4/2006, 5/3/2007 4,10/1/2007, 1/1/2008 5,6/1/2011, 1/1/2012 6,10/15/2004,12/1/2004 First, I want get interval between the start date and end dates (End-start). obs, Start , end, datediff
2019 Feb 04
2
Ayuda con calculo de variables / transponer R
Buenas tardes, tengo dudas con el siguiente ejercicio que me han propuesto en un curso, no se si alguien podria indicarme como abordarlo, soy nueva en R y agradezco mucho su ayuda Identi car cuales son las variables que están contenidas en el data.frame. A continuación, transformar ese data.frame para que cada columna represente cada una de las variables. Usar los nombres Date, District y N.
2020 Sep 13
2
Cambiar datos de un DF
Hola: Si codificas "col1" como un factor, lo puedes cambiar todo de una vez renombrando los niveles correspondientes: > df$col1<-as.factor(df$col1) > df$col1  [1] uno   dos   3     4     cinco 6     siete 8     9     diez Levels: 3 4 6 8 9 cinco diez dos siete uno > levels(df$col1)[1:5] <-
2012 Dec 04
3
How to find matching columns in a matrix of lists?
Dear R users, I have a matrix composed of lists: m <- matrix( list(), nrow=1, ncol=3 ) m[[ 1, 1 ]] <- list("A", "B") m[[ 1, 2 ]] <- list("A", "C") m[[ 1, 3 ]] <- list("A", "B") and want to get the sub-matrix where cells contain "B". But m[ , "B" %in% m[ 1, ], drop=F ] as well as m[ , "B"
2005 Aug 08
3
use different symbols for frequency in a plot
suppose I have the following data x<-c(rep(.1,5),rep(.2,6),rep(.4,10),rep(.5,20)) y<-c(rep(.5,3),rep(.6,8),rep(1.2,8),rep(2.5,18),rep(3,4)) If I plot(x,y) in R, I will only get seven distinct points. What I want to do is to use different symbols to show the frequency at each point. e.g. if the frequncey is between 1 and 5, then I plot the point as a circle; if the frequency is between 6
2012 Aug 05
4
find date between two other dates
Hi, I am trying to assign "Season" values to dates depending on when they occur. For example, the following dates would be assigned the following "Season" numbers based on the "season" intervals detailed below in the code: ddate Season 29/12/1998 20:00:33 1 02/01/1999 05:20:44 2 02/01/1999 06:18:36 2 02/02/1999