Displaying 20 results from an estimated 3000 matches similar to: "templated use of aggregate"
2012 Aug 27
2
Assigning colors on low p-values in table
Hi all R-users,
I?m trying to assign colors on those p-value in my table output that fall
above a certain critical value, let?s say a p-value >0.05.
My table looks like this:
Assets ADF-Level P-Value
ADF-First D P-Value ADF-Second D P-Value
[1,] Liabilities -2.3109 0.1988 -3.162
0.025 -6.0281
2010 Jul 28
2
Nat issue one way audio on IP dial
hi there,
i have posted earlier on the list but got no satisfying answer. the problem
is not big.
I have asterisk server directly connected with internet (79.80.x.x) and
clients are behind router. clients/users are registered with asterisk and
are using sipura and xlite softphone.
Now problem is that when a user calls other by dialing his IP:Port (sip
uri), call is connected fine and he can
2010 Oct 29
3
Dickey Fuller Test
Dear Users, please help with the following DF test:
=====
library(tseries)
library(timeSeries)
Y=c(3519,3803,4332,4251,4661,4811,4448,4451,4343,4067,4001,3934,3652,3768
,4082,4101,4628,4898,4476,4728,4458,4004,4095,4056,3641,3966,4417,4367
,4821,5190,4638,4904,4528,4383,4339,4327,3856,4072,4563,4561,4984,5316
,4843,5383,4889,4681,4466,4463,4217,4322,4779,4988,5383,5591,5322,5404
2011 Oct 11
5
Help to write to a file
Dear all:
I am having some problems to use the function "sink()". Basically I am doing
a loop over two files which contain unit-root variables. Then on a loop, I
extract every i element of both files to create an object called z. If z
meets some requirements, then I perform a unit root test (ADF test),
otherwise not. As this process is repeated several times, for each i I want
to get
2013 Jun 23
1
Scaling Statistical
Short question: Is it possible to use statistical tests, like the Augmented
Dickey-Fuller test, in functions with for-loops? If not, are there any
alternative ways to scale measures?
Detailed explanation: I am working with time-series, and I want to flag
curves that are not stationary and which display pulses, trends, or level
shifts.
>df
DATE ID VALUE2012-03-06 1
2006 Aug 28
1
Help on function adf.test
Hello everybody,
I've got a matrix called EUROPEDATA and I want to calculate the adf test statistic (part of the tseries package) on a rolling basis for window my.win on each column; i.e. each column of EUROPEDATA represents a particular variable; for the first column I calculate the adf test statistic for window my.win = 60 for example, roll forward one observation, calculate the adf
2007 Aug 16
2
ADF test
Hi all,
Hope you people do not feel irritated for repeatedly sending mail on Time series.
Here I got another problem on the same, and hope I would get some answer from you.
I have following dataset:
data[,1]
[1] 4.96 4.95 4.96 4.96 4.97 4.97 4.97 4.97 4.97 4.98 4.98 4.98 4.98 4.98 4.99 4.99 5.00 5.01
[19] 5.01 5.00 5.01 5.01 5.01 5.01 5.02 5.01 5.02 5.02 5.03 5.03 5.03
2009 Mar 20
1
Dickey Fuller test of a time series (problem)
Hi all,
I tried to do a Dickey Fuller test with R using adf.test with a time series of german stock prices. I have 10 stocks from 1985 to 2009 with monthly stock prices. So if you do the math I have 289 values for each stock.
I tried to do the test for each stock alone and had the 289 values of my first stock listed in R.
When I tried to do the test with command adf.test(x, k=1) the following
2007 Feb 13
1
lag orders with ADF.test
Hello!
I do not understand what is meant by:
"aic" and "bic" follow a top-down strategy based on the Akaike's and Schwarz's information criteria
in the datails to the ADF.test function. What does a "top-down strategy" mean? Probably the respective criterion is minimized and the mode vector contains the lag orders at which the criterion attains it
2011 Jun 06
2
Problem in R documentation
I am not able to run Dickey-Fuller test.
adf.test() function is not working. It is showing 'Error: could not find
function "adf.test"
Can any tell how to call "time series" library?
--
Siddharth Arun,
4th Year Undergraduate student
Industrial Engineering and Management,
IIT Kharagpur
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2008 Oct 02
1
nls with plinear and function on RHS
Dear R gurus,
As part of finding initial values for a much more complicated fit I want to
fit a function of the form y ~ a + bx + cx^d to fairly "noisy" data and have
hit some problems.
To demonstrate the specific R-related problem, here is an idealised data
set, smaller and better fitting than reality:
# idealised data set
aDF <- data.frame( x= c(1.80, 9.27, 6.48, 2.61, 9.86,
2013 Mar 22
4
error while extracting the p-value from adf.test
Hello all,
I tried to extract the p-value from adf.test in tseries; however, I got the error message such as
> ht=adf.test(list.var$aa)
> ht$p-value
Error in ht$p - value : non-numeric argument to binary operator
> ht
Augmented Dickey-Fuller Test
data: list.var$aa
Dickey-Fuller = -2.3147, Lag order = 4, p-value = 0.4461
alternative hypothesis: stationary
> ht$data
[1]
2007 Dec 08
2
time series tests
Hi all,
Can anyone clear my doubts about what conclusions to take with the following what puts of some time series tests:
> adf.test(melbmax)
Augmented Dickey-Fuller Test
data: melbmax
Dickey-Fuller = -5.4075, Lag order = 15, p-value = 0.01
alternative hypothesis: stationary
Warning message:
p-value smaller than printed p-value in: adf.test(melbmax)
2004 Oct 13
4
incomplete function output
Dear R users,
I have a function (below) which encompasses several tests.
However, when I run it, only the output of the last test is
displayed. How can I ensure that the function root(var)
will run and display the output from all tests, and not
just the last one?
Thank you,
b.
root <- function(var)
{
#---Phillips-Perron
PP.test(var, lshort = TRUE)
PP.test(var, lshort = FALSE)
2007 Jan 18
2
problem in adf command
this command is used in tseries
adf.test(x, alternative = c("stationary", "explosive"),
k = trunc((length(x)-1)^(1/3)))
this command apply adf test on data given in x .here general
equatiuon
that is, equation with constant and trend is used.if i did not include
constant or trend in the equation and run the
command then how i can run this command in tseries.
2010 Aug 03
2
RTP stream not passing through router with port forwarding
Hi,
I am trying to dial a registered user via his IP:Port mechanism, but problem
is that the audio data is not reaching to dialed user. here is the scenario.
caller and callee both are registered at asterisk server. asterisk server is
on public ip so no port forwarding and natting necessary there. however
caller and callee both are behind router and there is port forwarding
enabled and nat=yes,
2009 Jun 09
1
Using ADF.Test
Hi,
I am quite new to R and would appreciate some guidance, if possible.
I have imported a csv file: spread <- read.csv("Spread.csv")
I get the following error when I try to run adf.test:
> adf.test(spread,alternative = c("stationary", "explosive"),0)
Error in embed(y, k) : 'x' is not a vector or matrix
Why is this?
--
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2008 Dec 08
1
About adf.test
Dear sir,
I am a new user of R statistical package. I want to perform
adf.test(augmented dickey fuller test), which packages I need to install in
order to perform it. I am getting following message on my monitor.
*x<-rnorm(1000)
> adf.test(x)
Error: could not find function "adf.test"
*I am waiting for your response.
Kamlesh Kumar.
--
Kamlesh Kumar
Appt. No. - QQ420,
2013 Apr 30
1
ADF test --time series
Hi all,
I was running the adf test in R.
CODE 1:
adf.test(data$LOSS)
Augmented Dickey-Fuller Test
data: data$LOSS
Dickey-Fuller = -1.9864, Lag order = 2, p-value = 0.5775
alternative hypothesis: stationary
CODE 2:
adf.test(diff(diff(data$LOSS)))
Augmented Dickey-Fuller Test
data: diff(diff(data$LOSS))
Dickey-Fuller = -6.9287, Lag order = 2, p-value = 0.01
alternative
2007 Apr 05
2
about systemfit
Hello. I am still a newbie in R. Excuse me if I am asking something obvious. My efforts to get an answer through browsing the mailing archives failed. I want to perform an augmented Dickey-Fuller test and to obtain AIC and BIC and to be able to impose some linear restrictions on the ADF regression so as to decide the correct order of autoregression. However I could find no obvious way to impose