similar to: ggplot2: legend for geom_rug() ..?

Hi, I was trying to draw a geom_bar plot. However, by default, the bars are arranged according to the label, which I don't want. I want the bars to appear exactly as they appear in the data frame. For example in the code: Lab=c(letters[4:6],letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) px <- ggplot(df,aes(Lab,valuex,label=Lab)) +

You just have to change the levels of the factor ... library(ggplot2) Lab = c(letters[4:6], letters[1:3]) valuex = c(3.1,2.3,0.4,-0.4,-1.2,-4.4) df <- data.frame(Lab,valuex) # set the factor levels to the same order as observed in the data frame df$Lab <- factor(df$Lab, levels=unique(df$Lab)) px <- ggplot(df,aes(Lab,valuex,label=Lab)) + geom_text(aes(y=0)) + geom_bar(stat =

Dear R People: I want to get the class of all of the objects in my directory. I was trying: do.call(class,list=ls()) but got an "unused argument error". I'm sure it's simple, but I'm just not seeing it. Any help would be much appreciated. Sincerely, Erin -- Erin Hodgess Associate Professor Department of Computer and Mathematical Sciences University of Houston -

Hi, First let me say I am a big fan of R and appreciate all your time and effort. The update() function does not seem to work in a for loop. Consider the following: mdat <- matrix(c(1,2,3, 11,23,13, 12,4,8), nrow = 3, ncol=3, byrow=TRUE) reg <- lm(mdat[7:9]~1) for(i in 1:2) { reg <- update(reg,.~.+mdat[((i-1)*3 + 1):(i*3)]) #update reg twice } reg # reg should have two independent

Dear R-help team, I am getting addicted to using R but keep on getting many challenges on the way especially on data management (data cleaning). I have been wanting to drop all the rows if there values are `NA' or have specific values like 1 or 2 or 3. mdat <- matrix(1:21, nrow = 7, ncol=3, byrow=TRUE, dimnames = list(c("row1",

Hi all R-users, If I have a matrix with numeric elements as follows, the values are rounded when I try to refer to a specifici element using [], the value is rounded. The same thing happens if the matrix is read from a file, the values are stored to the correct precision but then when I try to refer to a specific element (such as using [], it is rounded. How do I avoid this rounding?

Hi all, So let's say I have a matrix, mdat and I only know the index number. How do I retrieve the column and row names? For example, > mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("C.1", "C.2", "C.3"))) > mdat[4] [1] 12 >

Dear R help, Apologies for the less than informative subject line. I will do my best to describe my problem. Consider the following matrix: mdat <- matrix(c(1,0,1,1,1,0), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("T1", "T2"), c("sp.1", "sp.2", "sp.3"))) mdat In my actual data I have time

HI, Dear R community, I try to create 100 dummy variables like the following: ack$id_1 <- (ack$ID==1)*1 ack$id_2 <- (ack$ID==2)*1 .. . ack$id_100 <- (ack$ID==100)*1 I used the following codes: for(i in 1:100){ ack$id_[i] <- (ack$ID==i)*1 } But only one column is created, can anyone help me? Thanks a lot! -- Sincerely, Changbin --

Hi all, I am trying to estimate a simple logit model. By using MLE, I am maximizing the log likelihood, with optim(). The thing is, each observation has different set of choice options, so I need a loop inside the objective function, which I think slows down the optimization process. The data is constructed so that each row represent the characteristics for one alternative, and CS is a

dear all, i am anewcomer. i have a set of paired data, the values are great different from each other. i want to show them in histogram. first, how to draw each bar for corresponding paired data side by side; second, how to set the scale of y axis? one is up to 100-fold to the other. ifdoubleslash is used to omit some coordinates, the histogram will looks better. is there anyone that can help

Hello there, I have a question regarding bar plots. I am trying to plot the data from the following matrix as a barplot - # input data mdat <- matrix(c(0.1,0.9,0.9,0.1,0.5,0.5,0.45,1-0.45,0.6,0.4,0.8,0.2), nrow = 6, ncol=2, byrow=TRUE, + dimnames = list(c("Mon", "Mon", "Tues", "Tues", "Thurs", "Friday"), +

seems pretty simple, my model... has_attached_file :pic_1, :styles => { :thumb => "120x90" }, :url => "/:attachment/:id_:style.:extension", :path => ":rails_root/public/system/:attachment/:id_:style.:extension" my view... <% form_tag(:action => ''create'', :html => { :multipart => true }) do -%> <label

Hi everyone. Long time listener, first-time caller here. I have a data set that's been melted with the excellent reshape package, but I can't seem to cast it the way I need to. Here's the melted data's structure: > str(mdat) 'data.frame': 6978 obs. of 4 variables: $ VehType : Factor w/ 2 levels "Car","Truck": 1 1 2 1 1 2 1 1 1 1 ... $ Year :

Hi all, I''ve installed paperclips but paperclip is not saving the files my model has has_attached_file :attachment,:styles => { :medium => "300x300>", :thumb => "100x100>" } and i have db migration as class AddAttachmentToPolicies < ActiveRecord::Migration def self.up add_column :policies,

Hi, Can you please help me with this please? What I am trying to do is call a vector from R function and used in the new function So I create 4 functions with these arguments M11 <- function(TrainData,TestData,mdat,nsam) { ls <- list() I have few statments one of them is vectx <- c(,1,2,3,4,5,6,6) vectz <- c(12,34,5,6,78,9,90) and then................ ls(vectx=vtecx,vectz=vectz)

Alright, so I am trying to write my own function to calculate column sums in a matrix. I want the result as a single list with the values. So far I have: csum<-function(m) { a = data.frame(m) s = lapply(a,sum) return(s) } What is the easiest way to have it return in a format such as [1] 6 15 24 ? Thanks. -- View this message in context:

Hi I got a barplot that has values between 0-150 and the y-axis shows the steps 0 50 100 and 150 but I would like to change it to 0 10 20 30... ...130 140 150 Dont really know the word in english so sry about it beeing abit confusing :) Thx for your help Joel -- View this message in context: http://r.789695.n4.nabble.com/change-y-axis-distance-tp2548363p2548363.html Sent from the R help

Hi all, I try to represent a multiple curve graphic where the x-axis is the temperature and the different y-axes are the different X (X22,X43,X44...) some X corresponds to the same molecule (22 and 44 are for CO2 for instance) so I use the same colour for them. I wanna mix the linetype with the colour to be able to visually see the difference between X43 and X45 The best I have done up to now

Hello R users (and Hadley) I have another question about ggplot2 :-) (version 0.8) `dat` <- structure(list(D = c("a", "b", "c", "d"), G = c(1.51520888871520, 1.88812208268440, -6.60521862, 0.55968739), E = c(1.38888592256404, 1.39366168665589, 1.22509259382058, 1.36617701059296), I = c(6.92634958902857, 6.94416045215158, 13.2179488828556,