similar to: Convert 2-dim array to 3-dim array

Hello dear R-users, I am currently trying to fill some datasatructure (array, list, hash...) with matrices that are calculated by a function and do vary in size: mylist = list() for(i in 1:n) mylist[i] = function(...) # returns a matrix print(mylist[1]) # prints only the first element of the matrix How can I store and afterwards access the matrices that are calculated by my function?

Hi all, I have a three dimensional array with the corresponding dimension names. I would like to subset the array according to the dimension names. For example, suppose I want to extract the values corresponding to A=20, B=10, C=0. I know I can do: P2[dimnames(P2)$A==20, dimnames(P2)$B==10, dimnames(P2)$C==0] But is there a better way for doing this? Thanks for your help! Hanna >

Dear List A 2-dimensional array seems to be "interpreted" as a matrix whereas higher dimensional arrays are interpreted as arrays, e.g. > a1 <- array(1:8,c(2,2,2)) > class(a1) [1] "array" > a2 <- array(1:4,c(2,2)) > class(a2) [1] "matrix" If I write a generic function (apologies if this is the wrong word) on arrays as foo <- function(x)

Ran into the follow intermediate case in an external package (w/ recent R v2.8.1 patched and R v2.9.0 devel): > x <- 1:2 > dim(x) <- 2 > dim(x) [1] 2 > x [1] 1 2 > str(x) int [, 1:2] 1 2 > nrow(x) [1] 2 > ncol(x) [1] NA > is.vector(x) [1] FALSE > is.matrix(x) [1] FALSE > is.array(x) [1] TRUE > x[1] [1] 1 > x[,1] Error in x[, 1] : incorrect number of

Hi, I have a three dimensional array, e.g., my.array = array(0, dim=c(2,3,4), dimnames=list( d1=c("A1","A2"), d2=c("B1","B2","B3"), d3=c("C1","C2","C3","C4")) ) what I would like to get is then a dataframe: d1 d2 d3 value A1 B1 C1 0 A2 B1 C1 0 . . . A2 B3 C4 0 I'm sure there is one function to do

Hi Simon, thank you for the concise reply. Do you mean the reported behavior of drop() is not a bug? It looks like a borderline bug to me (see below), but I'm not the judge of that. If this is the intended behavior and serves an actual purpose, then that could be explicitly documented in a \note{} on the help page. Such a note would slightly reduce the surprise of users running into this

Have you tried P2["20", "10", "0"] ? Jean On Thu, Jun 1, 2017 at 3:10 PM, li li <hannah.hlx at gmail.com> wrote: > Hi all, > I have a three dimensional array with the corresponding dimension names. > I would like to subset the array according to the dimension names. For > example, > suppose I want to extract the values corresponding to A=20,

I want to make a multi-dimensional array. To be specific I want to make the following array results<-array(0,dim=c(2,2,64,7)) This is the code I have created but it gives no result due to the error "subscript out of bound". x<-rep(7,7) # Missingness in intervention y<-rep(7,7) # Missingness in control

Hi: How can I extract the dimension-names of a pre-defined element in a multidimensional array in R ? A toy example is provided below: I have a 4-dimensional array with each dimension having certain length. In the below example, "mydatastructure" explains the structure of my data. mydatastructure = array(0, dim=c(length(b),length(z),length(x),length(d)), dimnames=list(b,z,x,d)) where,

Hi All, I am having great trouble doing something pretty simple. Here is what I did: > x <- read.table("clipboard") > dim (x) [1] 126 10 > typeof(x) [1] "list" > w <- array(x) > typeof(w) "list" Q1: How come after constructing an array out of the list, the type of the array is still "list"? > w <- as.array(x) Error in

Dear list, I'm trying to add a new dim to a multidimensional array. My array looks like this a1 <- array(1:8, c(2, 2, 2)) dimnames(a1) <- list(A = c("A1", "A2"), B = c("B1", "B2"), D = c("D1", "D2")) I would like to add a new dim 'group' with the value "low".

Dear all I would like to have some data in the form of a 2-dimensional array (matrix) of lists, so that I can easily find the desired list object by indexing the structure by rows and columns. In matlab there exists a data type called "cell array": a matrix of "cells", which are composite objects very similar to R lists. I know that in R you can create 1-dimensional

Hi! I'm just getting started with R (and with the analysis of large datasets in general). I have several beginner-level questions whose answers I have not been able to find, and was hoping one of you would be kind enough to throw me a cluebrick or two. I have a 6-dimensional numeric array (which I'll call myarray) that is "fully named". By this I mean that non-NULL dimnames

Hi, I am working on some microarray data, and have some problems with writing iterations. In essence, the problem is that objects with three dimensions don't have rownames and colnames. These colnames and rownames would otherwise still be there in 2 dimensional objects. I need to generate multiple iterations of a 2 means-clustering algorithm, and these objects thus probably need 3

Hello all, I have data from a csv that i need to coerce into a multi dimensional array. As you can see from my sample code i have yet to master building efficient code. I can sort of do what i want but its very cumbersome code and i know there is a better way to do it, i am just not expereinced enought yet. So for the following: #Create Data h1i1a1<-sample(1:20, 5, replace=TRUE)

Hi the list Is it possible to create an empty matrix ? I do not mean an matrix with a single value that is NA (which is not empty) but a real empty one, with length=0. I do not understand why we have length(numeric()), length(factor()) and length(character()) to zero, and length(array()) to one... Any rason for that ? Thanks Christophe

Hi all, I'm not sure if this is a feature or a bug (and I did read the FAQ and the posting guide, but am still not sure). Some of my students have been complaining and I thought I just might ask: Let K be a vector of length k. If one types dim(K), you get NULL rather than [1] k. Is this logical? Here's the way I explain it (and maybe someone can provide a more accurate

Dear R users, can someone help with these short puzzles? 1) Is there a function like outer() that evaluates a three-argument function on a threedimensional grid - or else how to define such a function, say, outer.3()? E.g., calculate (x/y)^z on (x,y,z) element of {1,2,3}x{3,4}x{4,5} and return the results in a 3-dimensional array. I would naively use outer() on two of the arguments within a

Can I assign names to rows/columns in a i x k x j matrix / dataframe? This message and any attachment are confidential and may be privileged or otherwise protected from disclosure. If you are not the intended recipient, please telephone or email the sender and delete this message and any attachment from your system. If you are not the intended recipient you must not copy this message or

Hello, I'm hoping someone with a wide experience with R may be able to see what the program is trying to tell me. I've got an array: y1=rnorm(41,0.2) y2=rnorm(41,0.2) y3=rbind(y1,y2) data11<-array(0,c(41,2,2)) data11[,1,]=y3 data11[,2,]=y3 rownames(data11)<-rownames(data11, do.NULL = FALSE, prefix = "Obs.") colnames=c("V","R")