similar to: merging single column from different dataframe

Hello, My problem is that I would like to merge multiple files with a common column but merge accepts only two data.frames to merge. In the real situation, I have 26 different data.frames with a common column. I can of course use merge many times (see below) but what would be more sophisticated solution? For loop? Any ideas? DF1 <- data.frame(var1 = letters[1:5], a = rnorm(5)) DF2 <-

Hi, let's see, if someone can help my with this one: I have the string as follows: > str<-("one","two","three") Now I want to concatenate the items to one string, seperateted by space or something else, >str >"one, two, three" If possible without a loop. My actual goal ist to create string like >str.names >"female = names1, male

Dear All Sorry for this simple question, I could not solve it by spending days. My data looks like this: # data set.seed(1234) clvar <- c( rep(1, 10), rep(2, 10), rep(3, 10), rep(4, 10)) # I have 100 level for this factor var; yvar <- rnorm(40, 10,6); var1 <- rnorm(40, 10,4); var2 <- rnorm(40, 10,4); var3 <- rnorm(40, 5, 2); var4 <- rnorm(40, 10, 3); var5 <- rnorm(40, 15,

Hallo Everyone I have the kind of problem that one should never have because one must always plan well and communicate with your team. But now I haven't so here is my problem. I have data coming in on a daily basis from surveys in 10 towns. The questionnaire has 62 variables but some of the regions have used older versions of the questionnaire that have a few variables less. I want to combine

Hi, May be this helps: m1<- as.matrix(read.table(text=" y1 g24 y1 0 1 g24 1 0 ",sep="",header=TRUE)) m2<-as.matrix(read.table(text="y1 c1 c2 l17 ?y1 0 1 1 1 ?c1 1 0 1 1 ?c2 1 1 0 1 ?l17 1 1 1 0",sep="",header=TRUE)) m3<- as.matrix(read.table(text="y1 h4??? s2???? s30 ?y1 0 1 1 1 ?h4 1 0 1 1 ?s2 1 1 0 1 ?s30 1 1 1

# Hello, # I have a list with 6 categories and with different numbers of rows. # I would like to change each of them into a unique data frame in order to match # values with other data frames and perform some calculations. # Or I could make each category or list element have the same number of rows and create one large data.frame. # below is a creation of a sample list # I apologize for the

HI Elisa, You could use ?cut() vec1<-c(33,18,13,47,30,10,6,21,39,25,40,29,14,16,44,1,41,4,15,20,46,32,38,5,31,12,48,27,36,24,34,2,35,11,42,9,8,7,26,22,43,17,19,28,23,3,49,37,50,45) label1<-unlist(lapply(mapply(c,lapply(seq(0,45,5),function(x) x),lapply(seq(5,50,5),function(x) x),SIMPLIFY=FALSE),function(i) paste(i[1],"<x<=",i[2],sep="")))

Hello, I have a nested named list structure, like the following: x <- list( list( list(df1,df2) list(df3, list(df4,df5)) list(df6,df7))) with df1...d7 as data frames. Every data frame is named. Is there a way to get a specific named element in x? so, for example, x[[c("df5")]] gives me the data frame 5? Thank you in advance! Best, Friedericksen

Hello ... Are there any known problems or even gotchas to look out for when using a gzfile connection in read.csv/read.table in Windows? In the package PROcess, available at www.bioconductor.org/repository/devel/package/html/PROcess.html there are two files in the PROcess/inst/Test directory which are of the extension *.csv.gz. With both files, if I open up a gzfile connection, say: vv <-

Hello, I have two dataframes DF1 and DF2 that should be identical but are not (DF1 has some rows that aren't in DF2, and vice versa). I would like to produce a new dataframe DF3 containing rows in DF1 that aren't in DF2 (and similarly DF4 would contain rows in DF2 that aren't in DF1). I have a solution for this problem (see self contained example below) but it's awkward and

Hi all, I have dataframe that was created from the fusion of two dataframes. Both spanned over the same time intervall but contained different information. When I put them together, the info overlapped since there is no holes in the time interval of one of the dataframe. Here is an example where the rows "sp=A and B" are part of a first df and the rows "sp=C" come from a

I'm seeing some inconsistent behavior when re-assigning values in a data frame. The first assignment turns all of the 0s in my data frame to 2s, the second fails to do so. > df1 <- data.frame(a = c(NA, 0, 3, 4)) > df2 <- data.frame(a = c(NA, 0, 0, 4)) > df1[df1 == 0] <- 2 ## Works > df2[df2 == 0] <- 2 Error: NAs are not allowed in subscripted assignments Checking an

Hi all, I am not a skillful R programmer and has I am handling with large dataframes (about 30000 x 300) I am in need of an efficient function. I have 4 dataframes with the same dimension. I need to generate other dataframe with the some dimension than the others where in each position it has the median value of the 4 values in the same position coming from the 4 dataframes. Grateful by your

Hi R users, I have a question about plotting. The following two datasets are an example. What I have in mind is like the attached figure, but just have two rows, top row is for DF1, bottom row is for DF2. The top and bottom rows, have x-axis as var1, var2, var3, etc, while the y-axis represents A. For each row, only the leftmost panel has y-axis ticks and label. For the two rows, only the bottom

Hi, what is the recommended way to vertically concatenate 2 data frames with the same column names but different number of rows? My problem is something along these lines: df1 <- data.frame(var1=var1,var2=var2,var3=var3) # nrow(df1)=1000 df2 <- data.frame(var1=var4,var2=var5,var3=var6) # nrow(df2)=2000 I tried df <- c(df1,df2), no success. stack does not seem to be appropriate

I've been doing some consulting with students who seem to come to R from SAS. They are usually pre-occupied with do loops and it is tough to persuade them to trust R lists rather than keeping 100s of named matrices floating around. Often it happens that there is a list with lots of matrices or data frames in it and we need to "stack those together". I thought it would be a simple

I have a series of data frames that are identical structurally, i.e. - made with the same code, but I need to add them together so that they become one, longer, data frame, i.e. - each of the slot vectors are increased in length by the length of the added data frame vectors. So if I have df1 with a slot A so that length(df1$A) = 100 and I have df2 with a slot A so that length(df2$A)=200 then I

I have the following data: prefix <- c("cheap", "budget") roots <- c("car insurance", "auto insurance") suffix <- c("quote", "quotes") prefix2 <- c("cheap", "budget") roots2 <- c("car insurance", "auto insurance") roots3 <- c("car insurance", "auto

Utilizo la función merge desde hace poco, pero no se me ocurre cómo utilizarla para esto. Yo pienso que se puede hacer con una combinación de ifelse-s pero no sé cómo. Seguro que hay más de una forma ce hacerlo. Quoting José María Mateos <chema en rinzewind.org>: > On Sat, Nov 10, 2018 at 07:54:19PM +0100, Manuel Mendoza wrote: >> Muy buenas. A ver si alguien puede echarme

Dear R users, I have a very basic query, but was unable to find a proper anwser. I have the following data.frame x y 2 0.12 3 0.25 4 0.11 6 0.16 7 0.20 and, due to further calculations, I need the data to be stored as x y 1 0 2 0.12 3 0.25 4 0.11 5 0 6 0.16 7 0.20 8 0 How do