Displaying 20 results from an estimated 2000 matches similar to: "a question about subsetting"
2012 May 19
3
anovas ss typeI vs typeIII
Hi all,
I have been struggling with ANOVAs on R. I am new to R, so I created a simple data frame, and I do some analyses on R just to learn R and then check them on SPSS to make sure that I am doing fine. Here is the problem that I've run into:
when we use the aov function, it uses SS Type I as default (on SPSS it is Type III). Then I used the Anova function under cars package using the
2008 Nov 20
2
Removing rows with rowsums==0 (I can't figure this out)
##I want to remove the rows where the row sums are zero and this is as
far as I have gotten
ffg <- (structure(list(CD = c(0, 0, 0, 0, 3.125, 0, 0, 0, 0, 1.6, 3.125,
0, 0, 6.25, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3.125, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1.6, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 0, 1.6, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0, 0, 3.125, 0, 0, 0, 0, 0, 0, 0, 0,
2012 May 15
4
reading data into R
Hi I am really new using R, so this is really a beginner stuff! I
created a very small data set on excel and then converted it to .csv
file. I am able to open the data on R using the command "read.table
("mydata1.csv", sep=",", header=T)" and it just works fine. But when I
want to work on the data (e.g. calculate the mean of variable "X") R
says
2012 May 29
2
a question about "by" and "ddply"
Hi all,
I have a data set (df, n=10 for the sake of simplicity here) where I have two continuous variables (age and weight) and I also have a grouping variable (group, with two levels). I want to run correlations for each group separately (kind of similar to "split file" in SPSS). I've been experimenting with different functions, and I was able to do this correctly using ddply
2011 Mar 11
2
insertion of a row between individuals
Can someone help with a fairly simple task?
I have a data set where I would like to insert a 0 time event between
individuals:
what I have:
VAR DATE TIME CONC COVAR
1 NOV2 0.25 10 group1
1 NOV2 0.5 20 group1
1 NOV2 1 5 group1
1 NOV2 2 1 group1
1 NOV2 3 0.1 group1
2 NOV2 0.25 10
2009 Aug 28
1
how to explain the interaction terms regarding "treatment contrast" of lm model
Dear list,
I am confused on how to explain the interaction term in the context of
"treatment contrast".
for example, I have an data frame as below:
sub group val
1 a group1 3.685625
2 a group1 3.407445
3 a group1 4.040920
4 a group1 2.890875
5 b group1 3.853280
6 b group1 4.113585
7 b group1 3.043250
8 b group1 3.800920
9 c group1 5.394305
10 c
2011 Nov 03
1
Reclassify string values
Hi All,
Is there a simple way to convert a string such as c("A", "B" ,"C", "D")
to a string of c("Group1", "Group1", "Group2", "Group2"). Naturally I
could use the factor function as below but I don't like seeing that
warning message (and I don't want to turn off warning messages). Perhaps
a function
2012 Dec 17
1
seeking a help on if function
Hello r helpers! Below is the whole coding for my programme. Before proceed more further, let me explain for you. First of all, I need to compute trimmed mean. Till that step is ok. Then I need to compute ssdw which is sum of square deviation. If I do equal trimming at both tail of distribution that I chose, I will use the first ssd formulae which is "a". But if I am doing unequal
2011 Feb 08
3
Permissions in shared folders
Hi,
On my mail server I want to implement shared folders for each workgroup
where there are many workgroups.
One way would be to create a separate namespace for each workgroup.
However, this does not scale well so I decided to use a single Shared
mailbox and use ACLs:
namespace public {
separator = .
prefix = Shared.
location = maildir:/var/mail/shared:CONTROL=~/Maildir/shared
}
Each
2011 Jul 14
2
cbind in aggregate formula - based on an existing object (vector)
Hello!
I am aggregating using a formula in aggregate - of the type:
aggregate(cbind(var1,var2,var3)~factor1+factor2,sum,data=mydata)
However, I actually have an object (vector of my variables to be aggregated):
myvars<-c("var1","var2","var3")
I'd like my aggregate formula (its "cbind" part) to be able to use my
"myvars" object. Is it
2009 Sep 20
2
missing level of a nested factor results in an NA in lm output
Hello All,
I have posted to this list before regarding the same issue so I
apologize for the multiple e-mails. I am still struggling with this
issue so I thought I'd give it another try. This time I have included
reproducible code and a subset of the data I am analyzing.
I am running an ANOVA with three factors: GROUP (5 levels), FEATURE
(2 levels), and PATIENT (2 levels), where
2005 Apr 20
1
negative p-values from fisher's test (PR#7801)
Full_Name: Martha Nason
Version: 2.0.1
OS: Windows XP
Submission from: (NULL) (137.187.154.154)
I am running simulations using fisher's test on 2 x c tables and a very small
p.value from fisher's test (<2.2e-16) is returned as a negative number. Code
follows.
> set.seed(0)
> nreps.outer <-7
> pvalue.fisher <- rep(NA,nreps.outer)
>
> population1 <- c(
2008 Aug 01
3
Grouping Index of Matrix Based on Certain Condition
Hi,
I have the following (M x N) matrix, where M = 10 and N =2
What I intend to do is to group index of (M) based on this condition
of "x_mn" , namely
For each M,
If x_m1 > x_m2, assign index of M to Group1
otherwise assign index of M into Group 2
> x
[,1] [,2]
[1,] 4.482909e-01 0.55170907
[2,] 9.479594e-01 0.05204063
[3,] 8.923553e-01 0.10764474
2010 Jan 25
3
binary
Hi all
Assume I have a data set xx;
Group: 1=group1 ?, 2=group2
IQ: ?1= High, 0 =low
fit <- glm(IQ ~group, data = xx, family = binomial())
summary(fit)
Results
?????? ????????????Estimate Std. Error z value Pr(>|z|)
(Intercept) -2.55456??? 0.210 -12.273? < 5e-16 ***
group????????? 0.36180 ?????0.076?? 3.952 ????5.24e-05 ***
the odd ratio = exp(0.36180 )= 1.435912
My question
2011 Apr 04
2
merging 2 frames while keeping all the entries from the "reference" frame
Hello!
I have my data frame "mydata" (below) and data frame "reference" -
that contains all the dates I would like to be present in the final
data frame.
I am trying to merge them so that the the result data frame contains
all 8 dates in both subgroups (i.e., Group1 should have 8 rows and
Group2 too). But when I merge it it's not coming out this way. Any
hint would be
2010 May 05
2
t.test per line
Dear All,
I apologize for this trivial question, I can not find the solution
I try to use t.test function per line in the data.frame, But i
dont'understand the error message
my program is as follows
group1<-gl(2,20)
fun<-function(x){
m<-data.frame(group1,x)
#anova(aov(x ~ group1, m))
t.est(x ~ group1,m)
}
ttest<- apply(data, 1, fun)
Error in t.test.default(x = c(1, 1,
2008 Oct 02
2
aggregate empty row for pretty appearance also subtotal if possible
Hi,
To pretty print aggregates by various dimensions I needed to add a
empty row in output of aggregate.
For example.
d<-(aggregate(data[,cbind("x")], by=list(data$group1,data$group2),
sum))
Group.1 Group.2 x
1 A N 3
2 A Y 2
3 B N 420164905
Is there a way to add an empty
2011 Jun 01
2
Samba + ACL + Linux Client
Hello,
I'm Oliver and I need help for a experiment.
I have a sharing with Samba version 3.2.5, my distribution Linux is
Debian(Lenny) and the acl version is 2.2.47.
Below my configurations files:
#/etc/fstab
/dev/sda3 /shared reiserfs defaults,acl 0 1
#smb.conf
[data]
comment = files
path = /shared
inherit acls = yes
inherit permissions = yes
map acl inherit = Yes
#
2005 Feb 23
1
How to conctruct an inner grouping for nlme random statement?
Hello. Im hoping someone can help with a grouping
question related to the "random=" statement within the
nlme function. How do you specify that some grouping
levels are inner to others? I tried several things,
given below.
Lets say I have a data frame with five variables,
resp, cov1, ran1, ran2, group1, and group 2. The
formula is resp~cov1 + ran1 + ran2, where the ran are
random
2016 Mar 31
4
rsync with overlay tree
I maintain a directory structure containing dirs and files that I regularly push to ~50 hosts, which are divided into 3 groups that have slightly different needs (minor mods in a couple of files).
So ideally I would have 4 directories:
/path/to/sync/common/ <- common files
/path/to/sync/group1/ <- group1 specific only
/path/to/sync/group2/ <- group2 specific only