Displaying 20 results from an estimated 100 matches similar to: "Problem with 'nls' fitting logistic model (5PL)"
2010 Apr 29
1
How to estimate the residual SD for each sample separately in mixed-effects model?
Dear R-helpers,
I am developing a Mixed-Effects model for a study of immunoassays using
'lme4' library. The study design is as follows: 10 samples were run
using 7 different immunoassays, 3 times each, in duplicates. Data
attached. I have developed the following model:
c.lme <- lmer(Result~SPL + (SPL|Assay/Run) -1, data=data)
This model has excellent predictions - the Rsquared of
2011 Mar 23
2
Estimating correlation in multiple measures data
Dear R-helpers,
This may sound simple to you, but I'm a beginner in this, so please be
forgiving.
I have a following problem: two analytes were measured in patient's
blood on 4 occasions: ProteinA and ProteinB. How to correctly evaluate
correlation between ProteinA and ProteinB?
I tried:
x <- data.frame(Patient.ID=rep(1:10, each=4), Visit=rep(c(1:4),10),
ProteinA=rnorm(m=10,
2010 Mar 30
5
Problem comparing hazard ratios
Dear R-Helpers,
I am a novice in survival analysis. I have the following code:
for (i in 3:12) print(coxph(Surv(time, status)~a[,i], data=a))
I used it to fit the Cox Proportional Hazard models separately for every
available parameter (columns 3:12) in my data set - with intention to
compare the Hazard Ratios.
However, some of my variables are in range 0.1 to 1.6, others in range
5000 to
2008 Oct 17
2
Beginner's question: number formatting
Hello R-helpers,
I have a problem with formatting a single number to show leading zeros.
For example, I want "2" displayed as "002".
My numbers have 1 to 3 digits and I would like them all to display 3
digits for printing. I know I could use "paste" in a loop with several
"if"s, but I was wondering if there is a single function that can do this.
I have
2010 May 26
3
Problem with plotting survival predictions from cph model
Dear R-helpers,
I am working with 'cph' models from 'rms' library. When I build simple
survival models, based on 'Surv(time, event)', everything is fine and I
can make nice plots using plot(Predict(f, time=3)).
However, recently I tried to be more specific and used 'Surv(start,
stop, event)' type model. Using this model 'plot(Predict(f))' works OK,
but
2009 Aug 05
1
Starting NONMEM (nmfe6) from R
Hello,
I have made an R script that prepares a NONMEM dataset and I would like
to start the NONMEM run right after the dataset is ready.
I am using windows XP, R 2.9.1 and NONMEM 6.
I have prepared a run.bat file that looks like this:
----------------------------------------
call K:\nmvi\NMdirectories.bat
call K:\nmvi\nmfe6 "path\control.txt" "path\output.txt"
2008 Jun 10
1
Problem with by(... , median)
Hello everyone,
I am new to R, I have been using SAS for a while. Not surprisingly, I
find R much better in graphics, which is publication ready right away.
Recently, I have been trying to calculate some basic statistics using R.
I have a dataset of multiple rows per subject. For example:
Subject Date Factor1 Factor2 Factor3
P1 0.5 1 1 3
P1 1 3 2 5
P1 2 3 5 NA
...
P2 0.5 1 6 4
P2 1 2 NA 7
P2
2008 Jul 23
1
[Fwd: Re: Coefficients of Logistic Regression from bootstrap - how to get them?]
I think the argument supporting the use of bootstrap to determine
coefficients, as opposed to just running linear regression on the whole
dataset, is the comparison of Rsq and prediction errors between these
two approaches - page 1502. There's a substantial difference in favor of
the bootstrap approach.
--
Michal J. Figurski
Gustaf Rydevik wrote:
> The url for the mentioned paper is
2008 Jul 21
5
Coefficients of Logistic Regression from bootstrap - how to get them?
Hello all,
I am trying to optimize my logistic regression model by using bootstrap.
I was previously using SAS for this kind of tasks, but I am now
switching to R.
My data frame consists of 5 columns and has 109 rows. Each row is a
single record composed of the following values: Subject_name, numeric1,
numeric2, numeric3 and outcome (yes or no). All three numerics are used
to predict
2010 Oct 21
1
Big data (over 2GB) and lmer
Dear R-helpers
I have a data set of roughly 10 million records, 7 columns. It has only
about 500MB as a csv, so it fits in the memory. It's painfully slow to
do anything with it, but it's possible. I also have another dataset of
covariates that I would like to explore - with about 4GB of data...
I would like to merge the two datasets and use lmer to build a mixed
effects model. Is
2008 Jul 24
1
[Fwd: Re: Coefficients of Logistic Regression from bootstrap - how to get them?]
Thank you Frank and all for your advices.
Here I attach the raw data from the Pawinski's paper. I have obtained
permission from the corresponding Author to post it here for everyone.
The only condition of use is that the Authors retain ownership of the
data, and any publication resulting from these data must be managed by them.
The dataset is composed as follows: patient number / MMF dose in
2008 Oct 06
1
Need to calculate within- and between- run CV
Dear R-helpers,
I have a dataset named "qu", organized as follows:
Sample Run Replicate Value
1 1 1 25
1 1 2 40
1 1 3 33
1 1 4 29
1 2 1 37
1 2 2 44
1 2 3 45
1 3 1 25
1 3 2 40
1 4 1 33
1 4 2 29
1 4 3 25
2 ...
Basically, a sample was run on an assay multiple times within a single
day. Each of these results is "Replicate". Then run was repeated several
times in
2010 Aug 10
3
Plotting confidence bands around regression line
Dear R-helpers and graphics gurus,
I have two problems with plotting confidence bands:
1. First is relatively simple. I am using the Passing-Bablok procedure
to obtain "unbiased" regression coefficients. This procedure yields the
"a" & "b" coefficient values along with their confidence intervals. I
then plot the raw data with the regression line, but I would
2010 Jan 15
1
'nlme' library - lme function results
Dear R-helpers
I am running a simple mixed effects model using lme(). The call looks
like this:
fit <- lme(Analyte~Sample, data=Data, random=~1 | Run)
I am particularly interested in the estimated random effects. When I
print the 'fit' object, it looks something like example below:
(...)
Random effects:
Formula: ~1 | Run
(Intercept) Residual
StdDev: 3.483794 3.637523
2003 Jul 10
6
info
HI
I'm a student in chemical engineering, and i have to implement an algoritm about FIVE PARAMETERS INTERPOLATION for a calibration curve (dose, optical density)
y = a + (c - a) /(1+ e[-b(x-m])
where
x = ln(analyte dose + 1)
y = the optical absorbance data
a = the curves top asymptote
b = the slope of the curve
c = the curves bottom asymptote
m = the curve X intercept
Have you never seen
2009 Apr 24
0
Problem with greek "beta" symbol in plot using CairoPDF (Windows)
Dear R-Helpers,
I have a problem with displaying the greek "beta" symbol in PDF files
using Cairo library - it displays as an empty box. The same also happens
for a dash symbol in subscript. Both symbols are displayed correctly if
the plot is produced on screen (outside of CairoPDF).
The syntax that I use for it in plot command is:
2010 May 12
1
data frame subscription
Dear group,
Here is my df :
pose16 <-
structure(list(DESCRIPTION = structure(c(1L, 2L, 3L, 4L, 5L,
6L, 7L, 8L, 9L, 12L), .Label = c("COPPER May/10", "COTTON NO.2 Jul/10",
"CRUDE OIL miNY May/10", "GOLD Jun/10", "ROBUSTA COFFEE (10) Jul/10",
"SOYBEANS Jul/10", "SUGAR NO.11 Jul/10", "SUGAR NO.11 May/10",
2010 Aug 02
2
Including a text file (JAGS model) in an R package
Hello,
I can`t figure out how to include a text file for use in an example in the .Rd help files of an R package I am writing.
I want the examples section of one help file to look like this:
\examples{
# Load the JAGS model
mod <- jags.model("model.txt")
}
The function jags.model tries to read in the file model.txt. So far every time I run R CMD check, I get an error message:
2015 Nov 19
0
statistician opening at Merck Research Labs in NJ, USA
If you are interested in the following position, please contact Vladimir Svetnik at Vladimir_svetnik at merck.com.
Date: Nov 18, 2015
Location: Rahway, NJ, US
Associate Principal Scientist, Biostatistics-BIO004396
Description
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2011 Feb 01
4
Fitting ELISA measurements "unknowns" to 4 parameter logistic model
Hello,
I am trying to fit my Elisa results (absorbance readings) to a standard
curve. To create the standard curve model, I performed a 4-parameter
logistic fit using the 'drc' package (ExpectedConc~Absorbance). This gave me
the following:
> FourP
A 'drc' model.
Call:
drm(formula = Response ~ Expected, data = SC, fct = LL.4())
Coefficients:
b:(Intercept) c:(Intercept)