similar to: Question about expand.grid function in R

Hello! # I have 3 vectors of values: values1<-rnorm(10) values2<-rnorm(10) values3<-rnorm(10) # In real life, all 3 vectors have a length of 25 # I create all possible combinations of 4 based on 10 elements: mycombos<-expand.grid(1:10,1:10,1:10,1:10) dim(mycombos) # Removing rows that contain pairs of identical values in any 2 of these columns: mycombos<-mycombos[!(mycombos$Var1

Hi, I have one question on expand.grid() function. When I write following syntax :expand.grid(c("u", "l"), c("u", "l"), c("u", "l")) I get following as desired : Var1 Var2 Var3 1 u u u 2 l u u 3 u l u 4 l l u 5 u u l 6 l u l 7 u l l 8 l l l However

Hello All: The function expand.grid() does nearly exactly what I want for permutation tests I wish to carry out, and it does so quickly when the number is kept small as in the example below: expand.grid(rep(list(c(-1, 1)), 3)) Var1 Var2 Var3 1 -1 -1 -1 2 1 -1 -1 3 -1 1 -1 4 1 1 -1 5 -1 -1 1 6 1 -1 1 7 -1 1 1 8 1 1 1 Understandably,

Hello! I have a list of variable length. One example is: X=vector("list",3) X[[1]]=1:2 X[[2]]=1:2 X[[3]]=1:2 How could I run expand.grid on the elements of X so that the results would be the same as expand.grid(1:2,1:2,1:2)? Thank you! Dimitri -- Dimitri Liakhovitski gfk.com <http://marketfusionanalytics.com/> [[alternative HTML version deleted]]

Dear R users I want to compute Kendall's Tau between two vectors x and y. But x and y may have zeros in the same position(s) and I wrote the following function to be sure to drop out those "double zeros" "cor.kendall" <- function(x,y) { nox <- c() noy <- c() # for (i in 1:length(x)) if (x[i]!= 0 | y[i] != 0) nox[length(nox)+1]<- x[i] for (i in

Hi, it looks like save() is saving all contents of the calling environments if the object to be saved is *not* evaluated, although it is not that simple either. After many hours of troubleshooting, I'm still confused. Here is a reproducible example (also attached) with output. I let the code and the output talk for itself: peek <- function(file, from=1, to=500) {

Situation: 8 POTS lines, 3 companies, 1 system. Channel banking the POTS lines onto a T1 thru an ADIT 600. The only way our carrier will provide DNIS is thru Analog DID #'s. Anyone know of a piece of hardware that can add DNIS digits to a particular line? -Darren

Hi All - "i'm new to linux" My Specs: Suse 9.0 & Windows 2003 Server (PDC) My needs: authenticating with Windows 2003 Server My Problem: Samba 2.x.x not working with Windows 2003 Server (worked with Windows 2000 Server!?) My Solution: Try Samba 3.0.1... Unfortunately - I could noy locate a RPM for Samba 3.0.1 so far... Have any one got any idea where I would be able to

Hello, I am trying to make a plot of the rates of an enzyme against three different protein concentrations (there are 45 rates in total and split up into 3 groups of 15, each receiving one of the 3 protein concentrations). When I enter the following code I instead get 3 separate boxplots for each of the three different protein concentrations ... plot(rate ~ ferm, data=LDH, col=LDH$rate,

I have some data measured with a coarsely-quantized clock. Let's say the real data are q<- sort(rexp(100,.5)) The quantized form is floor(q), so a simple quantile plot of one against the other can be calculated using: plot(q,type="l"); points(floor(q),col="red") which of course shows the characteristic stair-step. I would like to smooth the quantized

Hi Charles, Yes, it looks like my g++ does contain STL library which might be just my specific case... However, as a temporary solution I disabled nutclient in Makefile (please find the file attached). And nut-2.7.3 can be compiled now. Thanks, Sergey On Wed, Jul 8, 2015 at 4:13 AM, Charles Lepple <clepple at gmail.com> wrote: > On Jul 6, 2015, at 10:32 AM, Sergey Talchuk

try with 2.2.33.1 ---Aki TuomiDovecot oy -------- Original message --------From: Odhiambo Washington <odhiambo at gmail.com> Date: 13/10/2017 10:42 (GMT+02:00) To: Dovecot Mailing List <dovecot at dovecot.org> Cc: dovecot-news at dovecot.org Subject: Re: v2.2.33 released On 10 October 2017 at 18:28, Timo Sirainen <tss at iki.fi> wrote: >

Hi, I couldn't find anything about this subject from archive - are there known problems with compiling libshout2 under FreeBSD 5.1 or 4.8 (both are up to date). I downloaded libshout2 latest nightly snapshot and tried to compile it on 5.0 and then later on 4.8. Both failed (problems were mostly around sock.c, sock.h, resolver.c - redeclaring and syntax errors). Thinking that it might be a

Dear expeRts, The order in which the variables vary in expand.grid() is often unintuitive. I would like to suggest a 'method' slot for expand.grid() which requires only very little changes (100% backward compatible) and which allows one to control this order. Please find attached diffs against R-devel. Cheers, Marius ### ./src/library/base/R/expand.grid.R

Hi all, It is not clear to me why this cannot be ploted with image. Any help? > g <- data.frame(expand.grid(x= 1:5, y= 1:5), z= rnorm(25)) > image(g) Error in image.default(g) : increasing x and y values expected > is.list(g) [1] TRUE > g$x [1] 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 1 2 3 4 5 > g$y [1] 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 5 5 5 5 5 > Thanks in

Hello. I'm trying to do this (not necessarily 0:1) : expand.grid ( 0:1, 0:1, 0:1, 0:1, 0:1) etc..etc. but I want to have control over how many 0:1 are included. Any ideas please ? Thankyou. Simon Parker Imperial College --------------------------------- A Smarter Email. [[alternative HTML version deleted]]

Hello my R buddies, I'm trying to generate a bivariate data.frame with the elements of first row greater than the second row. The more complicated method that I can think of is: n <- 10 temp <- expand.grid(1:n,1:n) temp<-temp[temp[,1]>temp[,2],] However, I guess there must be some easier way of doing this. Besides, if inequality condition is applied at the very

Dear R gurus, I'm looking for a way to expand a matrix to a data frame as detailed below: given a Matrix M with attribute dimnames=list(c("a","b"),c("u","v")), return a data frame df.M with df.M$row df.M$col df.M$val "a" "u" M["a","u"] "b" "v"

  Hello R-users,   I have the following question, for which my search did not really return any usable result. If I have a matrix a1, and a vector a2 like below   a1<-matrix(c(1:4),2,2) a2<-c(8,9)   is there any function like the expand.grid (or some clever calling of the function) such that it outputs a matrix or dataframe where the entire a1 matrix is repeated for each value of a2 (the

Dear all, I am using expand.grid for calculating all the possible values between four pairs. I would like to ask you if it is possible to filter the result out, so to keep all unique pairs. In my algorithm the input c(1,2) produces the same results as the c(2,1) so for example in the following code below > expand.grid(c(1,2,3),c(1,2,3))   Var1 Var2 1    1    1 2    2    1 3    3    1 4