Displaying 20 results from an estimated 10000 matches similar to: "How to "flatten" a multidimensional array into a dataframe?"
2013 Nov 19
2
Optim function & Hessian matrix
Dear R Users
Hi,
I have very emergency problems in my programming about finding MLE
with optim command. I reproduced it with real data. I guess that my
function object in optim is very sensitive because it has power
function .
Then optim give me lower or initial values for estimates with these
warnings for Hessian matrix computation:
1: In log(B2 * (C2^(y + v))) : NaNs produced
2: In log(B3
2004 Jul 08
2
Getting elements of a matrix by a vector of column indice s
See if the following helps:
> m <- outer(letters[1:5], 1:4, paste, sep="")
> m
[,1] [,2] [,3] [,4]
[1,] "a1" "a2" "a3" "a4"
[2,] "b1" "b2" "b3" "b4"
[3,] "c1" "c2" "c3" "c4"
[4,] "d1" "d2" "d3" "d4"
[5,]
2010 Feb 09
2
How can I rearange my dataframe
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2005 Jun 03
2
rearrange data
Dear all:
I have this:
A1 B1 C1 D1 E1
A2 B2 C2 D2 E2
A3 B3 C3 D3 E3
And I want this
A1 E1
B1 E1
C1 E1
D1 E1
A2 E2
B2 E2
C2 E2
D2 E2
A3 E3
B3 E3
C3 E3
D3 E3
Example:
m<- matrix(1:15,nrow=3,byrow=T)
m
v<- unlist(list(t(m[,1:4])))
u<- rep(c(5,10,15),c(4,4,4))
data.frame(v,u)
This is the result I want but I would like to learn a simpler way to do it.
Any clue?
2005 Aug 15
2
queer data set
I have a dataset that is basically structureless. Its dimension varies
from row to row and sep(s) are a mixture of tab and semi colon (;) and
example is
HEADER1 HEADER2 HEADER3 HEADER3
A1 B1 C1 X11;X12;X13
A2 B2 C2 X21;X22;X23;X24;X25
A3 B3 C3
A4 B4 C4 X41;X42;X43
A5 B5 C5 X51
etc., say. Note that a blank
2006 Sep 13
3
group bunch of lines in a data.frame, an additional requirement
Thanks for pointing me out "aggregate", that works fine!
There is one complication though: I have mixed types (numerical and character),
So the matrix is of the form:
A 1.0 200 ID1
A 3.0 800 ID1
A 2.0 200 ID1
B 0.5 20 ID2
B 0.9 50 ID2
C 5.0 70 ID1
One letter always has the same ID but one ID can be shared by many
letters (like ID1)
I just want to keep track of the ID, and get
2007 Mar 09
1
Applying some equations over all unique combinations of 4 variables
#I have a data set that looks like this. A bit more
complicated actually with
# three factor levels but these calculations need to
be done on one factor at a
#I then have a set of different rates that are applied
#to it.
#dataset
cata <- c( 1,1,6,1,1,2)
catb <- c( 1,2,3,4,5,6)
doga <- c(3,5,3,6,4, 0)
data1 <- data.frame(cata, catb, doga)
rm(cata,catb,doga)
data1
# start rates
#
2012 Dec 27
3
Retrieve indexes of the "first occurrence of numbers" in an effective manner
Hi,
That sounds simple but I cannot think of a really fast way of getting
the following:
c(1,1,2,2,3,3,4,4) would give c(1,3,5,7)
i.e., a function that returns the indexes of the first occurrences of numbers.
Note that numbers may have any order e.g., c(3,4,1,2,1,1,2,3,5), can
be very large, and the vectors are also very large (which prohibits
any loop).
The best I could think of is:
tmp =
2012 Dec 27
4
Finding (swapped) repetitions of numbers pairs across two columns
Hi,
I've had this problem for a while and tackled it is a quite dirty way
so I'm wondering is a better solution exists:
If we have two vectors:
v1 = c(0,1,2,3,4)
v2 = c(5,3,2,1,0)
How to remove one instance of the "3,1" / "1,3" double?
At the moment I'm using the following solution, which is quite horrible:
v1 = c(0,1,2,3,4)
v2 = c(5,3,2,1,0)
ft <-
2018 Nov 25
3
[2.3.4] Segmentation faults
<!doctype html>
<html>
<head>
<meta charset="UTF-8">
</head>
<body>
<div>
<br>
</div>
<blockquote type="cite">
<div>
On 25 November 2018 at 06:29 Joan Moreau <
<a href="mailto:jom@grosjo.net">jom@grosjo.net</a>> wrote:
</div>
<div>
2007 Jul 12
1
how to estimate treatment-interaction contrasts
Hello, R experts,
Sorry for asking this question again again since I really want a help!
I have a two-factor experiment data and like to calculate estimates of
interation contrasts say factor A has levels of a1, a2, and B has
levels of b1, b2, b3, b4, and b5 with 3 replicates. I am not sure the
constrast estimate I got is right using the script below:
2018 Nov 24
2
v2.3.4 released
On Fri, 23 Nov 2018 10:45:56 -0500, Brad Smith stated:
>On 11/23/2018 9:31 AM, The Doctor wrote:
>
>> On Fri, Nov 23, 2018 at 04:06:53PM +0300, Odhiambo Washington wrote:
>>> On Fri, 23 Nov 2018 at 15:29, Timo Sirainen <tss at iki.fi> wrote:
>>>
>>>> https://dovecot.org/releases/2.3/dovecot-2.3.4.tar.gz
>>>>
2012 Mar 12
3
Idea/package to "linearize a curve" along the diagonal?
Hi,
I am trying to normalize some data. First I fitted a principal curve
(using the LCPM package), but now I would like to apply a
transformation so that the curve becomes a "straight diagonal line" on
the plot. The data used to fit the curve would then be normalized by
applying the same transformation to it.
A simple solution could be to apply translations only (e.g., as done
after a
2008 Dec 09
1
creating standard curves for ELISA analysis
Hello R guru's
I am a newbie to R, In my research work I usually generate a lot of ELISA
data in form of absorbance values. I ususally use Excel to calculate the
concentrations of unknown, but it is too tedious and manual especially when
I have 100's of files to process. I would appreciate some help in creating
a R script to do this with minimal manual input. s A1-G1 and A2-G2 are
2011 Dec 22
2
Indexing multi-dimensional table
I want to take slices of a multi-dimensional table (or array) without
knowing the number of dimensions in advance.
As a test I tried using (in this example a 3d table):
do.call(`[`, list(tbl, x,NULL,NULL)]
where I built the list on the fly. It works great as long as I only want the
first dimension however when I try a different dimension, say with
list(tbl,NULL,x,NULL), I get
2018 Nov 27
2
[2.3.4] Segmentation faults
It's still missing core dump (or bt full from it)
Aki
On 27.11.2018 8.39, Joan Moreau wrote:
>
> Thank you Aki
>
> here the requested data (below)
>
> Please not as well that we have numerous subfolders (>50) and pretty
> big mailbox sizes (>20G)
>
> Bug appears mostly in auth process and index-worker
>
>
> dovecot -n :
>
> # 2.4.devel
2011 Dec 06
1
Sequential Sum in R
I am trying to code the following excel formula in R.
a b c Result Formula
1 10 0.1 #N/A
IF(B2<20,NA(),C2+IF(ISERROR(D1),0,D1))
2 20 0.2 0.2
IF(B3<20,NA(),C3+IF(ISERROR(D2),0,D2))
3 30 0.3 0.5
IF(B4<20,NA(),C4+IF(ISERROR(D3),0,D3))
4 40
2005 Aug 13
1
How to change the names in tone pitch column
Hi,
I have a column (V4) in a midi event list which includes tone pitch names,
i.e. "A4, E4, C#4, A3...":
> compo[1:10,]
V1 V2 V3 V4 V5 V6 V7
1 1 1 0 A4 96 2 0
2 1 1 0 E4 96 2 0
3 1 1 0 C#4 96 2 0
4 1 1 0 A3 96 2 0
5 1 3 0 B4 96 1 0
6 1 3 0 E4 96 1 0
7 1 3 0 B3 96 1 0
8 1 3 0 G#3 96 1 0
9 1 4 0 C#5 96 1 0
10
2013 Nov 21
1
how can I import a number of datsets in a folder in my working directory to a list in R
Hi,
Suppose, if I create 15 files in my working directory.
set.seed(48)
lapply(1:15,function(i) {m1 <- matrix(sample(1:20,1686*2,replace=TRUE),nrow=1686,ncol=2); write.table(m1,paste0("file_",i,".txt"),row.names=FALSE,quote=FALSE)})
?D <-dir()
D1 <- D[order(as.numeric(gsub("\\D+","",D)))]
D1
?res <- t(sapply(D1,function(x) {x1<-
2003 Dec 15
2
3.0.1rc2 LDAP - problems joining domain
Hi,
I'm back on the list ;-)
I seem to be having some trouble getting W2K machines to join the domain in
3.0.1rc2. I haven't looked at this in detail since 2.2.8a but it looks like
the account gets created in LDAP and then it has trouble setting the password
appropriately. I believe this is the relevant part of the log:
api_rpcTNP: samr op 0x3a - api_rpcTNP: rpc command: