similar to: Displayed Date Format in Plot Title.

Hello, I am trying to create a plot often seen in hydrodynamic work than includes a contour plot representing the water speed with arrows pointing in the direction of flow. Does anyone have any idea how I might add arrows based on wf$angle (in the example below) to the plot below? Thanks in advance! Sam library(lattice) speed <- runif(100, 0, 20) wf <- data.frame(speed) wf$width <-

Hello, I am having trouble figuring out how to convert a Day of Year integer back into a Date format. For example I have the following: date <- c('2008-01-01','2008-01-02','2008-01-03','2008-01-04','2008-01-05','2008-01-06','2008-01-07',

Hello all, I have not been able to find an answer to this problem. I feel like it might be so simple though that it might not get a response. Suppose I have a dataframe like the one I have copied below (minus the 'calib' column). I wish to create a column like calib where I am subtracting the 'Count' when 'stain' is 'none' from all other 'Count' data for

Hello all, This is one of those "Is there a better way to do this questions". Say I have a dataframe (df) with a grouping variable (z). This is my base data. Now I know that there is a higher order level of grouping that exist for my group variable. So what I want to do is create a new column that express that higher order level of grouping based on values in the sub-group (z in this

Hello, I am trying to define a different interval for a "year". In hydrology, a "water year" is defined as the period between October 1st and September 30 of the following year. I was wondering how I might do this in R. Say I have a data.frame like the following and I want to extract a variable with the water year specs as defined above:

I have constructed a Trellis style xyplot. lengthf <- factor(length) xyplot(SLI$velocity ~ SLI$width | SLI$lengthf, layout = c(2,7), xlab = "Width (cm)", ylab = "Velocity (m/s^2)", col = "black") This produces a lovely little plot. However, the grouping factor(lengthf) isn't in the right order. My values range from 2-28 and the 2 graph on the bottom left and

Hello, I am having a problem making use of some data outputted from an instrument in a somewhat weird format. The instrument outputs two columns - one called JulianDay.Hour and one called Minutes.Seconds. I would like to convert these columns into a single column with a time. So I was using substr() and paste to extract that info. This works fine for the JulianDay.Hour column as there are always

Hello list, ## I have been doing the following process to convert data from one form to another for a while but it occurs to me that there is probably an easier way to do this. I am often given data that have column names which are actually data and I much prefer dealing with data that are sorted by factors. So to convert the columns I have previously made use of make.groups() in the lattice

Hello, I am looking for a way to subset a data frame by choosing the top ten maximum values from that dataframe. As well this occurs within some factor levels. ## I've used plyr here but I'm not married to this approach require(plyr) ## I've created a data.frame with two groups and then a id variable (y) df <- data.frame(x=rnorm(400, mean=20), y=1:400,

I am running Dovecot on OS X Lion and the webmail displays the date in a European style format - day of the month and then month number. How can I reverse this? -- View this message in context: http://old.nabble.com/How-do-I-change-the-date-format-displayed-on-webmail--tp32233645p32233645.html Sent from the Dovecot mailing list archive at Nabble.com.

Hello all, I am having a little trouble working with "strptime" and I was hoping someone might be able to give me a hand. I have an instrument that outputs an ordinal date and time in two columns something like this: day.hour min.sec 1 12525 2050 2 12518 2029 3 12524 2023 4 12524 2028 5 12507 2035 Now the problem I am having is converting these numbers

Good Morning, I am trying to create a new column of character strings based on the first two letters in a string in another column. I believe that I need to use some combination of ifelse and grep but I am not totally sure how to combine them. I am not totally sure why the command below isn't working. Obviously it isn't finding anything that matches my criteria but I am not sure why. Any

Hello all, I need to figure out a way to lag a variable in by a number of days without using the zoo package. I need to use a remote R connection that doesn't have the zoo package installed and is unwilling to do so. So that is, I want a function where I can specify the number of days to lag a variable against a Date formatted column. That is relatively easy to do. The problem arises when I

Hello all, Let me first say that this isn't a question about outliers. I am using the outlier function from the outliers package but I am using it only because it is a convenient wrapper to determine values that have the largest difference between itself and the sample mean. Where I am running into problems is that I am several groups where I want to calculate the "outlier" within

Hello, I am attempting to write a script that adds error bars to a barchart. I basing my attempt heavily on the following thread: http://tolstoy.newcastle.edu.au/R/e2/help/06/10/2791.html I can't seem to get around the problem that was discussed in the thread. The following example should illustrate my problem. Sorry about the messy example but I am 1) trying to make it as close as possible

Hi, In my form I have date field set as ''datetime_select'' which is fine as I wanted it in the same format. But while displaying (list action) it displays date in long format i.e. ''Tue May 30 15:39:00 Central Daylight Time 2006''. How can I format it so that it will just be diaplyed as ''dd/mm/yyyy'' format? Thanks -- Posted via

Hi, Just wondering how I get both the current date and time to display here (so far I can only get the date OR the time): @tblregisteredphone.txtregisterdatetime = Date.today Also, how can I change the format of the date and time from: Tue Apr 04 00:00:00 GMT Daylight Time 2006 to 2006-04-04 12:04:00 ?? I''m sure it''s very simple, I just don''t know how

Hello, Can anyone recommend a good example of web implementation of R? Can't seem to find anything on my own. Thanks in advance! Sam [[alternative HTML version deleted]]

Hello all, ## I am trying to convert some year and month data into a single variable that has a date format so I can plot a proper x axis. ## I've made a few tries at this and search around but I haven't found anything. I am looking for something of the format "%Y-%m" ## A data.frame df <- data.frame(x=rnorm(36, 1, 10), month=rep(1:12, each = 3), year=c(2000,2001,2002)) ##

I have Time fields in my PostgreSQL tables, which I force to display as time only with this entry in config/locales/en.yml: time: formats: default: "%H:%M:%S" Problem is, that format is now applied to Timestamp fields, including the default created_at and updated_at fields. Why is it applying the Time (time only) format to a Timestamp (date + time) field, and how do I