similar to: Could dynlm function work for xts objects?

Dear list-reader, by running the following script: library(zoo) sessionInfo() search() packageDescription("zoo") data(EuStockMarkets) dax <- as.zoo(EuStockMarkets[1:10, "DAX"]) daxr <- diff(log(dax)) identical(as.vector(qnorm(daxr)), qnorm(coredata(daxr))) qqnorm(coredata(daxr)) qqnorm(daxr) qqnorm() produces an error: > qqnorm(daxr) Fehler in if (xi == xj) 0L

Hi R programmers, I have stumbled across what seems a very simple problem. My goal is to create a xts time series object which contains vectors as values. In other words, I try to create something like this: 2009-01-01 => c('aa', 'bb', 'dd') ... 2010-02-01 => c('mm') I have figured out parts of separately. Here's what works (new xts time-series with

I would like to add vertical shaded blocks in plot.xts graphs (like recession periods in FRED graphs) The reason I use plot.xts instead of plot.zoo is that I like the fact that the grid is automatically aligned with major ticks in plot.xts. xblocks() and rect() do not seem to work with plot.xts (only with plot.zoo). Are there any alternative methods that work with plot.xts? Thanks. -- View

I am estimating Value at Risk using PerfomanceAnalytics package. The?variables are stored in a data frame. I formated the data variables using zoo() and as.xtx() but it is not working. The working example is below. ##########################################################? reguire(zoo) require(PerformanceAnalytics) reguire(xts) ? year<- c(1991-12-30, 1992-12-30, 1993-12-30, 1994-12-30) R1

Isn't this like trying to tie up the horse after it has left the barn? Why not figure all this out _before_ converting to xts? On April 12, 2023 12:29:49 PM PDT, akshay kulkarni <akshay_e4 at hotmail.com> wrote: >Dear Rui, > Not working. I have entirely removed the column containing % but am still bootless: > >> head(coredata(INFYTX)) > INFY

Dear Rui, Not working. I have entirely removed the column containing % but am still bootless: > head(coredata(INFYTX)) INFY Historical Data INFY Historical Data INFY Historical Data INFY Historical Data [1,] "47.26" "44.28" "47.56" "44.28" [2,] "46.30" "44.92"

Dear members, I have an xts object: > head(INFYTX) INFY Historical Data INFY Historical Data.1 INFY Historical Data.2 2003-04-16 "47.26" "44.28" "47.56" 2003-04-17 "46.30" "44.92" "46.53" 2003-04-21 "45.82"

?s 19:57 de 12/04/2023, akshay kulkarni escreveu: > Dear members, > I have an xts object: > >> head(INFYTX) > INFY Historical Data INFY Historical Data.1 INFY Historical Data.2 > 2003-04-16 "47.26" "44.28" "47.56" > 2003-04-17 "46.30" "44.92"

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Sir, I have hit a the limits of my understanding of text / par / opar etc... I have a few related xts data frames which have multiple columns, and have written a for-loop to make a set of charts - however i do not get any margin text when i run the loop. when i test the code outside of the loop the margin text appears - however when i run the loop the margin text does not appear ... what gives?

Hello, I looked in the R-help but could not find an archive addressing the following. I would like to convert a character to numeric after reading a file with RDS extension. After using as.numeric, I checked if it is numeric. It was not converted. Please help. Here is my code >Report <- readRDS(file="RDS/Report.RDS") > Report[1:2,] dive_id date

(Sorry, sent the message before I finished it) Hello, everyone I have a long script that uses zoo objects. In this script I used simple moving averages and these I can very efficiently calculate with filter() functions. Now, I have to use special "exponential" moving averages, and the only way I could write the code was with a for-loop, which makes everything extremely slow. I don't

Hello, everyone I have a long script that uses zoo objects. In this script I used simple moving averages and these I can very efficiently calculate with filter() functions. Now, I have to use special "exponential" moving averages, and the only way I could write the code was with a for-loop, which makes everything extremely slow. I don't know how to optimize the code, but I need to

Dear R-helpers, It seems to me that a character zoo cannot be coerced to a numeric zoo. Below is a minimal example. Can someone tell me what I have done wrong? > z<-zoo(1:4,order.by=1:4) > coredata(z)<-as.character(coredata(z)) > str(z) ‘zoo’ series from 1 to 4 Data: chr [1:4] "1" "2" "3" "4" Index: int [1:4] 1 2 3 4 >

Dear all, I have an error message, when I try to convert a zoo object (called test) to ts (on R 2.4.0, Package zoo version 1.2-1, Windows XP) > test 1994-05-10 1994-06-09 1994-07-09 0.0024943889 0.0024881824 0.0006955831 > str(test) atomic [1:3] 0.002494 0.002488 0.000696 - attr(*, "index")=Class 'Date' num [1:3] 8895 8925 8955 > is.regular(test) [1] TRUE

My problem is the following : I create 2 zoo objects and then I try to subset one of them using logic. indicesthatpass is a vector of trues and falses but when I send it into bckret, it returns an empty bckret. Obviously it has something to do with bckret being a zoo object and if I do the same subsctripting off of coredata(bckret), I'm confident it will work. But, I need to keep the minute

Hi, I have an intraday timeseries of financial data (see below) which has gaps due to market opening and closing hours. I am trying to plot it, but the time gap is always visible in the plot. I tried converting data to xts, zoo, timeSeries and plotting it with different functions i.e. plot.xts, plot.zoo. The only way to make it work was with function 'chartSeries' in the quantmod package

Hi, I work with SEXP C code and with xts and quantmod packages. I try to touch how xts internal works. So we have R session and: > ls() character(0) > getSymbols('AAPL') # quantmod package [1] "AAPL" > ls() [1] "AAPL" > str(AAPL) An ?xts? object from 2007-01-03 to 2010-09-09 containing: Data: num [1:929, 1:6] 86.3 84 85.8 86 86.5 ... - attr(*,

I used quantmod to pull in price data from the ticker SPY. The data has date and closing price. I would like to show the day of the week for each closing price. Is that possible? Also, I would like to add the back into the data frame in a new column without changing the structure of the data set if possible. SPY 2009-01-02 92.96 2009-01-05 92.85 2009-01-06 93.47

Hi all, I bumped into this awkward zoo behaviour. I'd be half tempted to call it a bug, what do you think? It's annoying to work around it :( I wonder if this was the behaviour of older zoo versions, I can't remember coming across this sort of thing... > version _ platform i386-pc-solaris2.10 arch i386 os solaris2.10 system i386,