similar to: Retrieving matrix column and row names by index value

Hi Everyone, Does anyone know of any projects for running an interactive R session within a web browser? I'm looking for something similar to the one on the Ruby website (http://tryruby.org), except for R. Thanks for your responses in advance! Lanna ----- Lanna Jin lannajin at gmail.com 510-898-8525 -- View this message in context:

Hi All, If given a dataframe (long form) with Year, Species, and Location, How would I write a function that would create a unique matrix of Species & Location for each Year? What I've tried doing is the following: data #dataframe dataT<-table(data$Species,data$Location,data$Year) #creates tables of Species vs Location for each Year But I'm encountering issues individually

Hi R-experts, I try to find a way to transfer a matrix to a data.frame that is used as input of aov. can you give me advice for that? >mdat <- matrix(c(1,2,3, 11,12,13), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("row1", "row2"), c("Col1", "Col2", "Col3"))) >mdat      Col1 Col2 Col3 row1    1    2    3 row2   11   12   13 ===>

Hi guys, I have a matrix with values varying from approximately -0.7 to 0.33 that I want to create a heatmap/levelplot with. When I execute the levelplot function for my matrix, I end up getting colors that are adjusted to the max and min rather than around 0. In other words, ideally I would like to have a color ramp that goes from red (negative number), to white (0), to blue (positive);

Hi all, First off, thank you for the overwhelming response last time. I'm still trying to figure out the syntax of R to plot some distributions of some frequencies. I've managed to plot histograms from the data, but I would like to clean it up using xyplot from library(lattice). Unfortunately I cannot find a solution to my problem. Given a dataframe "all2", with numerical

Hey All, So, I am confused how exactly to use nesting loop functions in R to spit out data frames. I've managed to create a working function for my data set that generates a data frame for a given set of Year i and Location j; but how would I do it for all Years and Locations? Here is my working function: test<-function(i,j){ a<-x[which(x$Year==i & x$Location==j),]

Hey all, I feel like the solution to this problem should be relatively simple, but for some reason I can't find answers or come up with my own solution. Given the dataframe: (SpA and SpB not important, want to look at distribution of cooccurance for each year) Year SpA SpB Coocc 2000 0 2000 2 2000 1 2001 8 2001 2 2001 0 2001 0 2002 1 2002 2 How can I apply different functions to

I need to replace <NA> occurrences in multiple columns in a data.frame with "000/000" how do I achieve this? Thanks Nevil Amos

as a r noob i am having another problem: i have a big dataframe where each row corresponds to one entry and each column is a field... for instance, i have the column ID and time and many more... Id like to get a dataframe where all IDs are just included once (some users with that ID might have several entries but Id like to kepp only one).. when i use unique I only get a list of the levels (or

Dear R-help team, I am getting addicted to using R but keep on getting many challenges on the way especially on data management (data cleaning). I have been wanting to drop all the rows if there values are `NA' or have specific values like 1 or 2 or 3. mdat <- matrix(1:21, nrow = 7, ncol=3, byrow=TRUE, dimnames = list(c("row1",

Hi, First let me say I am a big fan of R and appreciate all your time and effort. The update() function does not seem to work in a for loop. Consider the following: mdat <- matrix(c(1,2,3, 11,23,13, 12,4,8), nrow = 3, ncol=3, byrow=TRUE) reg <- lm(mdat[7:9]~1) for(i in 1:2) { reg <- update(reg,.~.+mdat[((i-1)*3 + 1):(i*3)]) #update reg twice } reg # reg should have two independent

Hi everyone. Long time listener, first-time caller here. I have a data set that's been melted with the excellent reshape package, but I can't seem to cast it the way I need to. Here's the melted data's structure: > str(mdat) 'data.frame': 6978 obs. of 4 variables: $ VehType : Factor w/ 2 levels "Car","Truck": 1 1 2 1 1 2 1 1 1 1 ... $ Year :

Hello there, I have a question regarding bar plots. I am trying to plot the data from the following matrix as a barplot - # input data mdat <- matrix(c(0.1,0.9,0.9,0.1,0.5,0.5,0.45,1-0.45,0.6,0.4,0.8,0.2), nrow = 6, ncol=2, byrow=TRUE, + dimnames = list(c("Mon", "Mon", "Tues", "Tues", "Thurs", "Friday"), +

Dear R help, Apologies for the less than informative subject line. I will do my best to describe my problem. Consider the following matrix: mdat <- matrix(c(1,0,1,1,1,0), nrow = 2, ncol=3, byrow=TRUE, dimnames = list(c("T1", "T2"), c("sp.1", "sp.2", "sp.3"))) mdat In my actual data I have time

HOla a todos soy novato en R. Lo que pasa es que tengo un conjunto de datos en una matriz y me gustaría saber , si es que el R tiene un comando en especial (para no tener que hacer el programa) para que dichos datos queden en una sola fila o columna. gracias. -- [[alternative HTML version deleted]]

Hi all R-users, If I have a matrix with numeric elements as follows, the values are rounded when I try to refer to a specifici element using [], the value is rounded. The same thing happens if the matrix is read from a file, the values are stored to the correct precision but then when I try to refer to a specific element (such as using [], it is rounded. How do I avoid this rounding?

Hello R users (and Hadley) I have another question about ggplot2 :-) (version 0.8) `dat` <- structure(list(D = c("a", "b", "c", "d"), G = c(1.51520888871520, 1.88812208268440, -6.60521862, 0.55968739), E = c(1.38888592256404, 1.39366168665589, 1.22509259382058, 1.36617701059296), I = c(6.92634958902857, 6.94416045215158, 13.2179488828556,

Hi, I was trying to make another legend for the rug plot. Sample code: library(ggplo2) ids <- paste('id_',1:3,sep='') before <- sample(9) after <- sample(1:10,9) dat <- as.matrix(cbind(before,after)) rownames(dat) <- rep(ids,3) position <- c(rep(10,3),rep(13,3),rep(19,3)) mdat <- cbind(melt(dat),position) ggplot(mdat, aes(position, value)) +

Dear group, I am losing my mind with a simple question. Sorry if obvious, but I maybe start to be confused after days and days of reading documentations. Df : df <- structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class = "factor", .Label = "w")), .Names = c("a", "b", "c"), row.names = c(NA, -3L), class =

Hello, It looks to me as if the ! logical operator cannot be called when subsetting a data.frame. In the example below, the value column has two factor levels (but my typical datasets have more), and what I am trying to do is to exclude all lines for which the "value" is different from "A". I have got a syntax error message everytime I try to use the subset() function.