similar to: how to convert seconds to 12 hour time format

Dear all, I created a n*2 matrix and I want to replace the ith row with a vector. Can anyone suggest me what is the simple way to do it? Sorry for bothering you with such simple question. I appreciate any hints or advice. Thanks in advance. Cassie [[alternative HTML version deleted]]

Dear all, I am trying to simulate from truncated Pareto distribution. I know there is a package called PtProcess for Pareto distribution...but it is not for truncated one. Can anyone please help me with this? Thanks in advance. Cassie [[alternative HTML version deleted]]

Dear all, I am trying to simulate from discrete uniform distribution. But I could not find any in-built code in R. Could anyone help me please? Thanks in advance for the time and help. Cassie [[alternative HTML version deleted]]

Dear All, I am trying to define a loop for a m*n matrix, where i=1:n and j=1:m. Unlike the usual for loop, i should go in the following way: For j=1, i=1,2,3,....n For j=2, i=n,n-1,n-2,......,1 For j=3, i=1,2,3,.....n etc. which means i should go in either increasing or decreasing order alternatively. Can anyone please help me in doing this? Thanks, Cassie [[alternative HTML version

Dear all, I am writing a program using for loop. The loop contains i which runs from 1:n. There is a feature I need to include here. That is, when i=n, i+1 would be 1, not n+1. Basically the loop should run in a circular fashion. That also means, if i=1, i-1=n. Can anyone help me with this? How can I define it? Thanks. [[alternative HTML version deleted]]

Dear all, I have a data set which has latitude, longitude (not in increasing order) and observed precipitation corresponding to those locations. I am using image.plot command for that. But I want to overlay a map of US on that plot. I know we can use map('usa') to draw it, but I dont know how can I overlay it on the plot of the precipitation data. Can anyone please help me with it?

Dear all, I am trying to define an array as follows: a=array(NA,c(m,2,N,G)), Even though the numbers N and G are fixed, m is a vector. So, I can't define 'a' as above. For eg, N=3 G=6, but m=c(2,7,5) and length(m)=N. Can anyone suggest me how can I define 'a' when m is a vector? Thanks in advance for your help. Cassie [[alternative HTML version deleted]]

Does anyone know how to do a fry plot in R? I have 600-800 points per image, and I really don't want to attempt that manually. Thank you! Cassie [[alternative HTML version deleted]]

I am having a hard time putting the below into a loop, where it pulls out ppt from all he stations I have versus having to go through and hard code the data to the specific stations. I tried stnID <- stnid[which(duplicated(stnid)==FALSE)] for(i in 1:length(stnID)) { ppt[i] <- ppt[which(stnid==[i])] } but it doesn't like to use the which function inside a for loop? Any idea's here is

Dear all, I need to simulate values from a Poisson distribution which is truncated at certain value 'a'. Can anyone tell me if there is in-built package in R which can simulate from a truncated Poisson? If not, what should be the steps to write a function which would do that? Thanks in advance. Cassie [[alternative HTML version deleted]]

Hi all, I have a matrix which looks like the following, x=matrix(c(1,2,3,4,3,5,4,6,4,9),5,2,byrow=T) Now, I want to replace the 2nd columns of those 4 rows which have duplicate entries in the 1st column. For example, x[2,1]=x[3,1]=3 and I want to replace x[3,2] by x[2,2]. Similarly, I want to replace x[5,2] with x[4,2], which means that for duplicate entries in the 1st column, I want to replace

Hello R-users, I am having a problem with the 'break' command in R. I am wondering if anyone can help me out with this. My program is similar to the following. a=rep(NA,5) a[1]=0 for(i in 2:5) { a[i]=a[i-1]+runif(1,0,3) if(a[i]>5) { i=2 break } } What exactly I am trying to do is find the sequence 'a' where the individual values of 'a'

Hello R-users, I am trying to do an image plot where I have been given latitudes, longitudes and the values at the corresponding locations. A sample of the data is given as follows: values=c(0,1,0,0,0,0,2,2,0,0) lat=c(29.6660,29.6756,29.3492,29.2654,29.2827,29.4070,35.3510,35.6590,35.7587,38.2794)

Dear all, I am trying to plot 3 histograms on the same graph using the following command. hist(x,xlim=c(0,100)) hist(y,add=TRUE) hist(z,add=TRUE) The xlim of y is c(20,21) and that of z is c(99,99.5) , whereas the variable x has xlim at c(0.5,2). Apparently, the graph end of displaying a line only, corresponding to each histogram due to the wide range of the xlim and tightness of the

Hi everyone, I have bunch of date and time observations in the format %Y-%m-%d %I %M %S %p. I used strptime() to read this format. But the problem is some of the times are in the format of %I %M %p, so for those times, strptime is giving me NA values. For example, strptime(paste("2009-04-08","1:49:47 PM"),format="%Y-%m-%d %I:%M:%S %p") [1] "2009-04-08

Hi, when I run the below code,there is an error occured. could you please tell me how to treat it? > pdf('covariate.pdf') > par(mfrow=c(1,1)) > pairs(data2[,c("ID","TYPE","AGE","GNDR","HT")], + panel=function(x,y) { points(x,y); lines(lowess(x,y))}) Error in `[.data.frame`(data2, , c("ID", "TYPE",

Hello, Suppose we need a function that takes a POSIXct object and need to calculate the time difference between it and GMT time: gmtDiff <- function(time) { time.gmt <- as.POSIXct(format(time, tz="GMT")) time.plt <- as.POSIXlt(time) dlstime <- ifelse(time.plt$isdst > 0, 1, 0) timezone <- as.numeric(difftime(time, time.gmt, units="hours"))

Hi all, In what encoding does format.POSIXct return its output? It doesn't seem to be utf-8: Sys.setlocale("LC_ALL", "Japanese_Japan.932") times <- c("1970-01-01 01:00:00 UTC", "1970-02-02 22:00:00 UTC") ampm <- format(as.POSIXct(times), format = "%p") x <- gsub(">", "*", paste(ampm, collapse =

Dear All, I encounted in a problem with as.POSIXct() function. > as.POSIXct("2009/03/26 01:00:00 AM" , format="%Y/%m/%d %I:%M:%S %p") [1] NA > as.POSIXct("2009/03/26 02:00:00 PM" , format="%Y/%m/%d %I:%M:%S %p") [1] NA I have tried this in the R version 2.11.1, R version 2.10.1 and R version 2.9.2 . They all does not work. The operation system is

Hi, Does anyone know how one could format numbers using 1000 separator in R? For example, format 1000 as 1,000 and 100000 as 100,000, etc. Thanks, -- Tom [[alternative HTML version deleted]]