similar to: rgeos - gBuffer, width by z-value

Dear list! I work with multiple Kruskal-Wallis test (kruskalmc, package pgirmess), which evaluates differences in medians among groups (5 groups). A result of a test is significant differences among some groups, while median values are the same for 4 groups (using tapply). Why? p.s.: number of samples in groups vary from 50 to 4900. Thanks to all, OV .

I figured it out, at least enough to get rgeos's gSimplify function to work, which was my original goal; the stringr problem was with 0.2, however I got stringr 0.5 to install by changing the minimum version in DESCRIPTION from R2.11 to R 2.10. ... Thanks for the help! ############# # This is how I got rgeos to install in R GUI on my Intel Mac OS X 10.4: ############# # stringr

Dear list! I would like to calculate "chisq.test" on simple data set with 70 observations, but the output is ''Warning message:'' Warning message: In chisq.test(tabele) : Chi-squared approximation may be incorrect Here is an example:         tabele <- matrix(c(11, 3, 3, 18, 3, 6, 5, 21), ncol = 4, byrow = TRUE)         dimnames(tabela) <- list(        

Dear list!   I would like to write a function to transform matrix, which is input argument of a written function. It is easy with new matrix (see below), but my idea is to transform input argument (matrix) of function without any additional matrixes. Here is an example: fun1 <- function(xy) { xy <- cbind(xy[,1], xy[,2], xy[,1] + xy[,2]) return(xy) }   df1 <- matrix(c(1,2,3,1,2,3), ncol =

Dear list members! I am looking for ''nice solution'' for (maybe) simple problem. I need a code (small program) to calculate row index for max value (example below: df1$values) by groups (example below: df1$groups). df1 <- data.frame( groups = c(1,1,1,1,1,2,2,2,3,3,3,3), values = c(1,1,1,2,1,1,2,3,2,1,4,3) ) df1 expected results > 4 8 11 # row index of max values by group

Dear list! ? I have question of?'correct function formation'. Which function (fun1 or fun2; see below) is written more correctly? Using ''structure'' as output or creating empty ''data.frame'' and then transform it as output? (fun1 and fun1 is just for illustration). ? Thanks a lot, OV ? code: input <- data.frame(x1 = rnorm(20), x2 = rnorm(20), x3 =

Hi R-helper! I have problem with setMethods for "[". Here is example : setClass("myClass", representation(ID.r = "numeric", ID.c = "character", DAT = "matrix")) to.myClass <- function(ID.r, ID.c, DAT) {     out <- new("myClass", ID.r = ID.r, ID.c = ID.c, DAT = DAT)     return(out)       }       setMethod("[",

Hi everybody! I have a matrix of class "myClass", for example: myMat <- matrix(rnorm(30), nrow = 6) attr(myMat, "class") <- "myClass" class(myMat) When I extract part of ''myMat'', the corresponding class ''myClass'' unfortunately disappear: myMat.p <- myMat[,1:2] class(myMat.p) Please for any advice / suggestions, how

Hi all!   My question is how to colour pixels by z value in persp plot in raster package. Here is an example:     x <- seq(-1.95, 1.95, length = 30) y <- seq(-1.95, 1.95, length = 35) z <- outer(x, y, function(a,b) a*b^2) r1 <- raster(nrows=35, ncols=30, xmn=0, xmx=30, ymn = 0, ymx = 35) r1[] <- c(z) persp(r1)   There already exist some function to produce persp plot for anothe

Dear R helpers! I have a vector 'x1' and data.frame 'df1'. Do you have any suggestion how to get vector x2, which will be a result of matching values from vector 'x1' and values from 'df1'? Please, see the example: x1 <- c(rep(1,3), rep(NA,2), rep(2,4)) df1 <- data.frame(c1 = c(1,2), c2 = c(5,6)) I would like to get vector x2: > x2 [1]  5  5  5 NA NA  6 

Hi all!   My question in about using mapply instead for loop. Below is a example with for loop: Is it posible to give same results with mapply function?   Thanks for help!   OV   x <- 1:10 y <- 1:10 xyz <- data.frame(expand.grid(x,y)[1], expand.grid(x,y)[2], z = rnorm(100)) names(xyz) <- c("x", "y", "z") head(xyz) size <- 2 output <- NULL   ### for

Hi, I am using in my workflow gIntersection from sp package. Part of my relevant sessionInfo is: R version 4.0.3 (2020-10-10) Platform: x86_64-w64-mingw32/x64 (64-bit) Running under: Windows 10 x64 (build 17763) attached base packages: [1] stats graphics grDevices utils datasets methods base other attached packages: [1] CircStats_0.2-6 boot_1.3-25 MASS_7.3-53 stringr_1.4.0

I have obtained shapefiles for Indian states from here: http://www.maptell.com/index.php?option=com_remository&Itemid=159&func=fileinfo&filecatid=115&parent=category Problem: I want to extract centroid coordinates for each State, but there is some coding problem with the shapefiles that prevents this. #Code: #After extracting the shapefiles from the india_state.zip file, then:

Hi All, Does anybody know of any existing functions that will calculate distance inland from a coastline? It's possible to test if a lon,lat location is land or sea using map.where(), but I need to add a buffer to this of say 2km, to allow for points that are just on the coast, and below the resolution of the worldHires database. I'm working with a marine mammal satellite telemetry

Hello Everybody. i am installing rgeo in R-2.13 on debian lenny. i am getting following error. Can anybody help me why i m not able to compile rgeos. rgeos_misc.c: In function ‘rgeos_hausdorffdistance’: rgeos_misc.c:55: error: ‘GEOSHausdorffDistance_r’ undeclared (first use in this function) rgeos_misc.c:55: error: (Each undeclared identifier is reported only once rgeos_misc.c:55: error: for

Some notes on installing rgeos in R 2.14.0 on a Linux Mint 11 (x86_64-pc-linux-gnu) machine 1. rgeos 0.1-15 will not run with GEOS 3.2.0-1, which is the version currently available on Synaptic package manager 2. I installed GEOS 3.3.1 (the latest version) from http://trac.osgeo.org/geos/, but rgeos will not run with this either 3. I then install GEOS 3.2.3, and now rgeos works fine! It seems

The third report on the R-spatial evolution project has been published. https://r-spatial.org/r/2023/04/10/evolution3.html It links back to earlier blogs and presentations, and focuses on work that maintainers of R packages and workflows using rgdal, rgeos and maptools need to put in train now before the packages are archived on CRAN. The first changes will occur in June 2023, and the

The third report on the R-spatial evolution project has been published. https://r-spatial.org/r/2023/04/10/evolution3.html It links back to earlier blogs and presentations, and focuses on work that maintainers of R packages and workflows using rgdal, rgeos and maptools need to put in train now before the packages are archived on CRAN. The first changes will occur in June 2023, and the

The legacy R spatial infrastructure packages maptools, rgdal and rgeos will be archived by CRAN on Monday, October 16, 2023; rgrass7 has already been replaced by rgrass and will be archived with the retiring packages. The choice of date matches the previously announced archiving during October 2023, and the specific date matches the release schedule of Bioconductor 3.18 (some Bioconductor

The legacy R spatial infrastructure packages maptools, rgdal and rgeos will be archived by CRAN on Monday, October 16, 2023; rgrass7 has already been replaced by rgrass and will be archived with the retiring packages. The choice of date matches the previously announced archiving during October 2023, and the specific date matches the release schedule of Bioconductor 3.18 (some Bioconductor