similar to: Any package recommended for time series graphics in R?

Hello, I work with time series data. From time to time I run programs to produce results that are in time series form (e.g., quarterly or monthly data). After a few days I might need to access part of the results and to run another program. Is there any function or package (like dataframe or zoo?) that might help so that I don't need to copy the results manually to a csv or xls file?

Hello, I am writing codes for time series computation but encountering some problems Given the quarterly data from 1983Q1 to 1984Q2 PI1<-ts(c(2.747365190,2.791594762, -0.009953715, -0.015059485, -1.190061246, -0.553031799, 0.686874720, 0.953911035), start=c(1983,1), frequency=4) > PI1 Qtr1 Qtr2 Qtr3 Qtr4 1983 2.747365190 2.791594762

Hello, I have a question on how to tabulate the time series data. I use RStudio, but if can be done in any other R editor, it should work in RStudio as well. > a1<-11:22 > a1ts<-ts(a1, frequency=4, start=c(1978,1)) > a1ts Qtr1 Qtr2 Qtr3 Qtr4 1978 11 12 13 14 1979 15 16 17 18 1980 19 20 21 22 If I click the variable "a1ts" on the

I have a program, when I write if(num!=NA) it yields an error message. However, if I write if(is.na(num)==FALSE) it works. Why doesn't the first statement work? Thanks, Miao [[alternative HTML version deleted]]

Hello, Let us convert a vector to a time series object starting in 1978Q1: FRW<-ts(FRW0, frequency=4, start=c(1978,1)) FRW[3:6] represents the data from 1978Q3 to 1979Q2. Could we access the data by the time (1978Q3 to 1979Q2) instead of FRW[3:6]? Thanks, miao [[alternative HTML version deleted]]

Hi, I have a structure, which is the result of a function How can I access the elements in the gradient? > dput(test1) structure(-1.17782911684913, gradient = structure(c(-0.0571065371783791, -0.144708170683529), .Dim = 1:2, .Dimnames = list(NULL, c("x1", "x2")))) > test1[[1]] [1] -1.177829 > test1 [1] -1.177829 attr(,"gradient") x1

Hello, I try to handle the data using read.csv , zoo and aggregate functions. The data contains NA values. After aggregating monthly data into quarterly data, all data become NA. Is it because I don't properly aggregate the data in the presence of NAs? What can I do? Another problem is that the date in month is presented in Chinese (My OS is in Chinese.) How can I set the default

Hi, How could we print the frequency table (produced by "table") to an Excel file? Is there an easy way to do so? Thanks, Miao > df <- data.frame(x = 1:3, y = 3:1, z = letters[1:3]) > table(df[,c("y","z")]) z y a b c 1 0 0 1 2 0 1 0 3 1 0 0 > test<-table(df[,c("y","z")]) > as.data.frame(test) y z Freq 1 1 a

Hello, I am using RStudio and have trouble finding out the problematic line in the presence of a bug. Could I view the line NUMBER which contains a bug? Is there any R editor able to do it? Thanks, Miao [[alternative HTML version deleted]]

Dear Daniel and Jorge, Thank you very much and it does help. If I have a string "ABCD", how can I access the second element of the string "B"? Thanks, Miao 2012/7/27 Daniel Nordlund <djnordlund@frontier.com> > > -----Original Message----- > > From: r-help-bounces@r-project.org [mailto:r-help-bounces@r-project.org] > > On Behalf Of jpm miao

Hi jpm miao, You can get CSV files that can be imported into Excel like this: library(prettyR) sink("excel_table1.csv") delim.table(table(df[,c("y","z")])) sink() sink("excel_table2.csv") delim.table(as.data.frame(table(df[,c("y","z")])),label="") sink() sink("excel_table3.csv")

Example: Will ts objects be obsolete or modified? > a [,1] 1983 Q1 2.747365190 1983 Q2 2.791594762 1983 Q3 -0.009953715 1983 Q4 -0.015059485 1984 Q1 -1.190061246 1984 Q2 -0.553031799 1984 Q3 0.686874720 1984 Q4 0.953911035> lag(a,4) [,1] 1983 Q1 NA 1983 Q2 NA 1983 Q3 NA 1983 Q4 NA 1984 Q1 2.747365190 1984 Q2

Hi, How can I plot two curves with distinct x and y vectors? I would like to join one of them by regular lines and plot the other just by points (no lines). Can it be done in regular R graphic tools, say "plot" function? Can it be done in Lattice package, say "xyplot" function? Thanks, Miao My data look like this: two curves with different vector size x

HI, I have a dataframe with two variable A, B. I transform the two variable and name them as C, D and save it in a dataframe dfcd. However, I wonder why can't I call them by dfcd$C and dfcd$D? Thanks, Miao > A=c(1,2,3) > B=c(4,6,7) > dfab<-data.frame(A,B) > C=dfab["A"]*2 > D=dfab["B"]*3 > dfcd<-data.frame(C,D) > dfcd A B 1 2 12 2 4 18

Hi, I let xzoo be an empty object: > xzoo<-{} and I have an existing zoo object x1zoo_f. I would like to combine the two to make a new zoo object, and continue doing so in a loop, which is not shown here. However, when I type > xzoo<-cbind(xzoo, x1zoo_f) An error message emerges Error in zoo(structure(x, dim = dim(x)), index(x), ...) : “x” : attempt to define

Taking the Grunfeld data, which is built-in in R, for example, (1)How can I construct a dataset (or dataframe) that consists of the data of all firms in 1951? (2)How can I calculate the average capital in each form over the period 1951-1954? What I can imagine is to categorize the data by firm, and then select the data between 1951 and 1954 for each firm, but how can I do it? Thanks, Miao

Hi, I have three time series and I would like to plot them on the same graph such that two of them share left y-axis and the third uses right y-axis. rm(list=ls()) library(zoo) x1 <- read.csv(file="120322DBCdata.csv", header=TRUE) x1date<-as.yearqtr(1979)+seq(0,nrow(x1)-1)/4 x1zoo<-zoo(x1, x1date, frequency=4) x1zoodata<-cbind(x1zoo$D4GDP, x1zoo$D4NE,

Hi, I would like to read several datasets and would like to create a set (list? sequence?) of many empty dataframes. How could this be done? How could I declare a set (list? sequence?) of many empty matrices? Thanks, Miao [[alternative HTML version deleted]]

Hello, I have problem running the histogram function "hist". The area under the histogram is much lower than 1. Could anyone tell me what the problem is? Thanks, (The total number of observation is 992 (close to 1000), so the probability that 0<Y1<35 is approximately 0.277) miao rm(list=ls()) par(mfrow=c(1, 1)) Y <- cbind(matrix(35*0.5,1,277), matrix(35*1.5, 1, 146),

Hi, I'd like to print a string vertically. For example, I would like to print "abcd" as "a\nb\nc\nd" Is there a function in R such that Input: "abcd" Output: "a\nb\nc\nd"? Thanks, Miao [[alternative HTML version deleted]]