similar to: Reshaping data from long to wide without a "timevar"

Hi, I'm a new R user and I'm having trouble with the read.csv command. It somehow treats the first column as a row name field even though it's not a row name. there are no missing columns/entries and i'm not sure how to resolve this. the format of my data is A, B, C, D,......(3984 columns) 12, 13, 41,......(all numeric) it either treats column A as rownames or if I explicitly

Hi! All, To find co-expressed genes from a expression matrix of dimension (9275 X 569), I used rcorr function from library(Hmisc) to calculate pearson correlation coefficient (PCC) and their corresponding p-values. From the correlation matrix (9275 X 9275) and pvalue matrix (9275 X 9275) obtained using rcorr function, I wanted to select those pairs whose PCC's are above 0.8 cut-off and then

Hi I have a data.frame with 2 columns. The first column is an ID column. The other columns are description of the ids. There is more than one description for each Id. Want I want to get as a value is a data.frame where each row corresponds to one ID and has as many columns as different descriptions. I have used a very convoluted step, but I'm very convinced there is an easier way to do

Hi all! I have data in ?Long? format which I would like to reshape to ?Wide?. I know that one possibility is the ?reshape? command, which needs a ?timevar?. Data look as follows: There are approx. 3000 persons (?IDENTITY?) and, for each person, there are between 2 and 20 events (?EVENT?). For now, there's one row for each event (9506 rows)

I have two waves of a survey given to students at various middle schools and high schools, with student id numbers for each student. I am having difficulty reshaping the file from long to wide. My code is below: library(foreign) svy <- read.spss("studsur4.SAV") svy.wide <- reshape(svy, timevar="WAVE", idvar="id", direction="wide")

>cbn<-as.matrix(expand.grid( rep( list(0:1), 50))) Error in rep.int(rep.int(seq_len(nx), rep.int(rep.fac, nx)), orep) : invalid 'times' value In addition: Warning message: In rep.int(rep.int(seq_len(nx), rep.int(rep.fac, nx)), orep) : NAs introduced by coercion But I'm only interested in cbn matrix rows where: cbn<- cbn[rowSums(cbn)==5,] Is there a way to evaluate it

For the following code below, the x-axis ticks are 1,2,3,4,5,6,7 when I was expection them to be 1,2,8,9,10,11,12. Please help me figure out where is the mistake. library(lattice) testdata <- as.data.frame(t(structure(c( 1,2005,9.24,6.18,634, 2,2005,8.65,6.05,96, 8,2004,6.81,6.51,16, 9,2004,9.0,7.29,8, 10,2004,8.84,6.18,524, 11,2004,8.54,6.35,579, 12,2004,9.97,6.3,614, 12,2005,8.75,5.84,32,

Hi... With samba4 I sometimes feel like a bloody beginner even I use samba since ages. Miracle of the day: Users connecting using samba4 cannot write to group writeable folders even they should be able to. I upgraded one 3.6 fileserver to 4.2.3. PDC is always a samba 4.2.3 instance. I am using samba4 in classic PDC mode for a couple of reasons. On my fileserver I have a folder called

Hi All.. Have a question.. For the following r code testdata <- as.data.frame(t(structure(c( "1/1/04","LV1",3.8,2,87, "2/1/04","LV1",3.2,3,28, "3/1/04","LV1",3.4,3,88, "4/1/04","LV1",3,2,26, "5/1/04","LV1",3.8,2,87, "6/1/04","LV1",3.2,3,28,

I have a text string that contains text within two brackets. e.g. "testdata[3]" "testdata[-4]", "testdata[-4g]", I wish to "extract" the string enclosed in brackets? What is a good way to do this? e.g. fun(testdata[3]) = '3' fun(testdata[-4g]) = '-4g' --------------------------------- Moody friends. Drama queens. Your life?

In playing around with data.frames (and wanting a simple, cheap way to use the variable and case names in plots; but I've solved that with some hacks, yech), I noticed the following behavior with subsetting. testdata <- data.frame(matrix(1:20,nrow=4,ncol=5)) names(testdata) ## expect labels, get them names(testdata[2,]) ## expect labels, get them names(testdata[,2]) ## expect labels, but

Dear all, I have a dataset where the interaction is more than obvious, but I was asked to give a p-value, so I ran a logistic regression using glm. Very funny, in the outcome the interaction term is NOT significant, although that's completely counterintuitive. There are 3 variables : spot (binary response), constr (gene construct) and vernalized (growth conditions). Only for the FLC construct

Sorry guys, but I have another one: I want to write a function that returns a certain column of a dataframe. The function accepts two argument: the dataframe and the name of the column, but the column is not given as a "string" but as a variable name. EXAMPLE ---------------------- > testdata start stop censor groupvar var1 var2 1 0 1 0 1

Hello All, Recently developed the code below for graphing patterns of chemotherapy administration. As someone just starting to use R in their work, I managed to figure out some parts of the code but needed help with others. setwd("N:/Regimen Coding/0906/Plots Test") getwd() TestData <- structure(list(profile_key = c(1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3), line = c(1, 1,

I am having trouble getting standard errors for contrasts using se.contrast() in what appears to be a simple case to me. The following test example illustrates my problem: Lab <- factor(rep(c("1","2","3"),each=12)) Material <- factor(rep(c("A","B","C","D"),each=3,times=3)) Measurement <-

Hello all, due to unexplained differences between statistical results from collaborators and our lab that arose in the same large proteomics dataset we reevaluated the t.test() function. Here, we found a weird behaviour that is also reproducible in the following small test dataset: Suppose, we have two vectors with numbers and some missing values that refer to the same individuals and that

I want to change the way the plot is appearing in the barchart .. testdata <-

I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927

Dear all, I'm trying to replace NA values with -9999 in one column of a data frame. I've tried using is.na and the testdata[testdata$onecolumn==NA] <- 9999 approach, but whilst neither generate errors, neither result in -9999s appearing - the NAs remain there! I'd be grateful for any advice on what I'm doing wrong or any other suitable approaches. Many thanks, Steve

On 23/04/2018 11:49, Michael Felt wrote: > On 21/04/2018 16:21, Michael Felt wrote: > > > Question: I have not dug into the tests yet. Will copy to a "local" > directory, and not build out of tree and see if that fixes it (as it > does for many other packages). However, just in case it does not - how > can I fast-forward the tests to the "agent" tests?