similar to: Equation as a character string

Hello, I'd like to add labels to my plot that include a male or female symbol as subscript. I'm working in Windows Vista and R 3.0.0. I am able to add the male symbol to the plot as regular text (NOT as subscript), e.g. with: mtext("Male\u2642") This displays the word "Male" followed by the male symbol on the plot. But "\u2642" does not work when I try to

Hello R Community, I am using the Lavaan package in R 2.15.0 to analyze data collected from 1200 lakes across North America. My dataset includes 3 continuous independent variables (LOG_NTL, LOG_PTL, and LOG_SR_A_D) and 1 continuous dependent variable (BIOVOL) . I have successfully constructed structural equation models using the Lavaan package (example included below with code), but I have not

Hi, I have 20*60 data matrix (with some NAs) and I wish to perfom a Pearson correlation coefficient matrix as well as simple linear regression equation and coefficient of determination (R2) for every possible combination. Any tip/idea/library/script how do to so. Thanks, As hz -- View this message in context:

I am a new user of the function sem in package sem and lavaan for structural equation modeling 1. I don?t know what is the difference between this function and CFA function, I know that cfa for confirmatory analysis but I don?t know what is the difference between confirmatory analysis and structural equation modeling in the package lavaan. 2. I have data that I want to analyse but I have some

Awesome, thanks Arun, that's exactly what I was looking for! On Sat, Jan 26, 2013 at 9:21 PM, arun kirshna [via R] < ml-node+s789695n4656749h63@n4.nabble.com> wrote: > Hi, > Try this: > df[]<-lapply(df,as.character) > df2<-df > df[,1][grep("@",df$names)]<- "" > df > #names emails > #1 bob bobj@cup.com > #2

Hi all, I have two matrices: G<-matrix(c(2.0, 0.5, 0.5, 0.5, 2.0, 0.5, 0.5, 0.5,2.0),3,3) P<-matrix(c(1.0, 0.5, 0.5, 0.5, 1.0, 0.5, 0.5, 0.5,1.0),3,3) and I want to run this equation to get a new matrix F: F = [P+2G]^-1/2 P [P+2G]^-1/2 Could someone please tell me how to code this in R? Many thanks in advance for your time. Best wishes, Matt [[alternative HTML version deleted]]

I thought replacing the spaces following instances of +++,++,+,- with "\n" and then reading with scan should succeed. Like Ivan Krylov I was fairly sure that you meant the minus sign to be "-" rather than "?", but perhaps your were using MS Word as an editor which is inconsistent with effective use of R. If so, learn to use a proper programming editor, and in any case

Hello List, ? I have a dataset consisting of strings that I want to split while saving the delimiter. ? Some example data: ?leucocyten + gramnegatieve staven +++ grampositieve staven ++? ?leucocyten ? grampositieve coccen +? ? I want to split the strings such that I get the following result: c(?leucocyten +?, ??gramnegatieve staven +++?, ??grampositieve staven ++?) c(?leucocyten ??, ?grampositieve

Hi List l am interested in developing price model. I have found a research paper related to price model of corn in US market where it has taken demand & supply forces into consideration. Following are the equation: Supply equation: St= a0+a1Pt-1+a2Rt-1+a3St-1+a5D1+a6D2+a7D3+U1 -(1) Where D1,D2,D3=Quarterly Dummy Variables(Since quarterly data are considered) Here, Supply

Dear Emily, Using a look-behind solves the split problem in this case. (Note: Using Regex is in most/many cases the simplest solution.) str = c("leucocyten + gramnegatieve staven +++ grampositieve staven ++", "leucocyten ? grampositieve coccen +") tokens = strsplit(str, "(?<=[-+])\\s++", perl=TRUE) PROBLEM The current expression does NOT work for a different

Hi Dr. Snow, I am a graduate student working on analyzing data for my thesis and came across your post on an R forum: The default link function for the glm poisson family is a log link, which means that it is fitting the model: log(mu) ~ b0 + b1 * x But the data that you generate is based on a linear link. Therefore your glm analysis does not match with how the data was generated

rsync does not sync the timestamp on symlink (Solaris 8). It is probablly due to the limitation of Unix implementation of symlink, but I would like to know why rsync/Unix does not do this, and what we can do about it. Is the conclusion that "rsync syncs everything except the timestamp on symlink"? Why do I need timestamp on symlink? Supposed something stopped working because something

Dear R-Help, I am trying to use R to solve a nonlinear equation many times for different values. I am looking for a mathematical nonlinear equation solution which may not have a closed solution form. For example, I have equation: 2 = (t^2)/log(t) What is t? I am wondering how to solve it in R. Many thanks, Zhu Wang Statistical Science Department SMU.

Is there a way to display something like the quadratic equation, i.e. with a numerator and demonator on a plot? I think there is a way to create the equation in Latex, but wasn't sure if this format would translate to plotting. \begin{equation} ? x = \frac{b +/- sqrt(b^2 - 4*a*c)}{2*a} \end{equation} ? My searched turned up the following:

Dear R users,   I am struggling to fit expo-linear equation to my data using "nls" function. I am always getting error message as i highlighted below in yellow color:     ### Theexpo-linear equation which i am interested to fit my data:       response_variable =  (c/r)*log(1+exp(r*(Day-tt))), where "Day" is time-variable   ## my response variable   rl <-

Hello all! Maybe it's a newbie question(in fact I _am_, a newbie), but I hope you'll find the solution. I have an equation system which has k equation and n variables (k<n). I would like to obtain a description of the solutions (which can be the equation of lines or a plane, or everything else) with the lesser degree of freedom, obviously using R. In other words, I would like to

Sorry, I didn't mean a linear equation, of course this equation is not linear, I meant an equation in one unknown. Hi all, I've a linear equation of the form: 0.95=2 ( [3+ln(x/3)]^-13? + 4 [3+2ln(x/3)]^-13? + [3+4ln(x/3)]^-13 ) and I want to solve it for x, can I do this using R? Thanks in advance. Maram. ? ? ? ??? [[alternative HTML version deleted]] -------------- next

Dear all, I have a set of data with 4 inputs (independent variables) and one output (dependent variable). I want to perform a regression analysis in order to fit these data to a regression model, however due to the non-linearity of the model I do not have a clue which equation to use. I am thinking of starting with a very general equation including ^3 terms and interactions between the variables

Is there a way to add covariates to the system equation in a time-varying approach: Y[t] = F'[t]theta[t] + v[t], v[t] ~ N[0,V] #observation equation theta[t] = theta[t-1] + psi*Z[t] + w[t], w[t] ~ N[0,W] #system equation While F[t] is a matrix of regressors to capture the short term effect on the response series Y, Z[t] measures the long-term effect of either (1) two policies by a step

Hi everyone, I am having a bit of trouble correctly structuring an equation in R. Here is the equation Here is what I thought for(i in 1:numItem)for(x in 1:numCat) Ptheta[,i,x]<-(exp(-1.702*a[i]*(theta-b[i,x+1])) My problem is that I am not sure how to get it to read the equation as having two indexing points (i and x). Right now it is trying to read it as a matrix, but